States of Matter Water. States of Matter  Objectives  Describe the structure of a water molecule  Discuss the physical properties of water. Explain.

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Presentation transcript:

States of Matter Water

States of Matter  Objectives  Describe the structure of a water molecule  Discuss the physical properties of water. Explain how they are determined by the structure of water  Calculate the amount of energy absorbed or released when a quantity of water changes state

States of Matter  Structure of Water  Water molecules consist of two atoms of hydrogen and one atom of oxygen united by polar-covalent bonds  The molecules in solid or liquid water are linked by hydrogen bonding  The number of linked molecules decreases with increasing temperature  Ice consists of water molecules in the hexagonal arrangement

States of Matter  Structure of Water  The hydrogen bonds between molecules of liquid water at 0.°C are fewer and more disordered than those between molecules of ice at the same temperature  Liquid water is denser than ice  As the temperature approaches the boiling point, groups of liquid water molecules absorb enough energy to break up into separate molecules

States of Matter  Ice and Water

States of Matter  Heating Curve for Water

States of Matter  Physical Properties of Water  At room temperature, pure liquid water is transparent, odorless, tasteless, and almost colorless  The molar enthalpy of fusion of ice is relatively large compared with the molar enthalpy of fusion of other solids  Water expands in volume as it freezes, because its molecules form an open rigid structure  This lower density explains why ice floats in liquid water

States of Matter  Physical Properties of Water  Both the boiling point and the molar enthalpy of vaporization of water are high compared with those of nonpolar substances of comparable molecular mass  The values are high because of the strong hydrogen bonding that must be overcome for boiling to occur  Steam (vaporized water) stores a great deal of energy as heat

States of Matter  Physical Properties of Water  Sample Problem  How much energy is absorbed when 47.0 g of ice melts at STP? How much energy is absorbed when this same mass of liquid water boils?  ΔH f = kJ/mol  ΔH v = kJ/mol

States of Matter  Physical Properties of Water  Sample Problem Solution  Given: mass of H 2 O(s) = 47.0 g mass of H 2 O(l) = 47.0 g molar enthalpy of fusion of ice (ΔH f ) = kJ/mol molar enthalpy of vaporization (ΔH v ) = kJ/mol  Unknown: energy absorbed when ice melts energy absorbed when liquid water boils  Convert the mass of water from grams to moles

States of Matter  Physical Properties of Water  Sample Problem Solution  Use the molar enthalpy of fusion of a solid to calculate the amount of energy absorbed when the solid melts  Calculate the amount of energy absorbed when water boils by using the molar enthalpy of vaporization

2.61 mol × kJ/mol = 15.7 kJ (on melting)  Physical Properties of Water  Sample Problem Solution States of Matter 2.61 mol × kJ/mol = 106 kJ (on vaporizing or boiling)