Physics 207: Lecture 21, Pg 1 Physics 207, Lecture 21, Nov. 15 l Agenda: l Agenda: Chapter 16, Finish, Chapter 17, Sound  Traveling Waves  Reflection.

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Physics 207: Lecture 21, Pg 1 Physics 207, Lecture 21, Nov. 15 l Agenda: l Agenda: Chapter 16, Finish, Chapter 17, Sound  Traveling Waves  Reflection  Transmission  Power Chapter 17, Sound  Plane waves, spherical waves  Loudness Assignments: l Problem Set 8 due Nov. 21, Tuesday 11:59 PM Ch. 16: Ch. 16: 3, 18, 30, 40, 58, 59 (Honors) Ch. 17: 3, 15, 34, 38, 40 l For Monday, Chapter 16, Doppler effect Start Chapter 17

Physics 207: Lecture 21, Pg 2 Wave Properties Wavelength: The distance between identical points on the wave. l Amplitude: The maximum displacement A of a point on the wave. l A wave varies in time and space. Animation Animation 1 Wavelength A y x

Physics 207: Lecture 21, Pg 3 Wave Properties Look at the spatial part (Let t =0). Animation Wavelength A y x x = 0y = A x = /4y = A cos(  /2) = 0 x = /2y = A cos(  ) = -A

Physics 207: Lecture 21, Pg 4 Look at the temporal (time-dependent) part l Let x = 0 Animation  Period A y t t = 0y = A t =T / 4y = A cos(-  /2) = 0 t =T / 2y = A cos(-  ) = -A

Physics 207: Lecture 21, Pg 5 Wave Properties... l Period: The time T for a point on the wave to undergo one complete oscillation. Speed: The wave moves one wavelength in one period T so its speed is v =  / T. Animation

Physics 207: Lecture 21, Pg 6 Lecture 21, Exercise 1 Wave Motion l The speed of sound in air is a bit over 300 m/s, and the speed of light in air is about 300,000,000 m/s. l Suppose we make a sound wave and a light wave that both have a wavelength of 3 meters. What is the ratio of the frequency of the light wave to that of the sound wave ? (Recall v =  / T =  f ) (A) About 1,000,000 (B) About 0.000,001 (C) About 1000

Physics 207: Lecture 21, Pg 7 Wave Forms continuous waves l So far we have examined “continuous waves” that go on forever in each direction ! v v l We can also have “pulses” caused by a brief disturbance of the medium: v l And “pulse trains” which are somewhere in between.

Physics 207: Lecture 21, Pg 8 Lecture 20, Exercise 2 Wave Motion l A harmonic wave moving in the positive x direction can be described by the equation v = / T = f = (  ) (  f) =  / k and, by definition,  > 0 and the “wavevector” or wave number” k ≡  y(x,t) = A cos( (2  /  )  x -  t ) = A cos(k x –  t ) with v =  / k, if  / k > 0 then v >0 or if  / k < 0 then v < 0 l Which of the following equations describes a harmonic wave moving in the negative x direction ? (A) y(x,t) = A sin (  k x   t ) (B) y(x,t) = A cos ( k x   t ) (C) y(x,t) = A cos (  k x   t )

Physics 207: Lecture 21, Pg 9 Lecture 20, Exercise 3 Wave Motion A boat is moored in a fixed location, and waves make it move up and down. If the spacing between wave crests is 20 meters and the speed of the waves is 5 m/s, how long  t does it take the boat to go from the top of a crest to the bottom of a trough ? (Recall v =  / T =  f ) (A) 2 sec (B) 4 sec (C) 8 sec t t +  t

Physics 207: Lecture 21, Pg 10 Waves on a string l What determines the speed of a wave ? l Consider a pulse propagating along a string: v l “Snap” a rope to see such a pulse l How can you make it go faster ? Animation

Physics 207: Lecture 21, Pg 11 Waves on a string... l The tension in the string is F The mass per unit length of the string is  (kg/m) l The shape of the string at the pulse’s maximum is circular and has radius R R  F Suppose:

Physics 207: Lecture 21, Pg 12 Waves on a string... l So we find: l Increasing the tension increases the speed. l Increasing the string mass density decreases the speed. l The speed depends only on the nature of the medium and not on amplitude, frequency, etc. v tension F mass per unit length  Animation

Physics 207: Lecture 21, Pg 13 Reflection of a Wave, Fixed End l When the pulse reaches the support, the pulse moves back along the string in the opposite direction l This is the reflection of the pulse l The pulse is inverted

Physics 207: Lecture 21, Pg 14 Reflection of a Wave, Fixed End Animation

Physics 207: Lecture 21, Pg 15 Reflection of a Wave, Free End l With a free end, the string is free to move vertically l The pulse is reflected l The pulse is not inverted

Physics 207: Lecture 21, Pg 16 Reflection of a Wave, Free End Animation

Physics 207: Lecture 21, Pg 17 Transmission of a Wave, Case 1 l When the boundary is intermediate between the last two extremes ( The right hand rope is massive or massless.) then part of the energy in the incident pulse is reflected and part is transmitted l Some energy passes through the boundary Here  rhs >  lhs Animation

Physics 207: Lecture 21, Pg 18 Transmission of a Wave, Case 2 l Now assume a heavier string is attached to a light string l Part of the pulse is reflected and part is transmitted l The reflected part is not inverted Animation

Physics 207: Lecture 21, Pg 19 From Prof. Zagzebski’s seminar on Ultrasound

Physics 207: Lecture 21, Pg 20 Wave Power l A wave propagates because each part of the medium transfers its motion to an adjacent region.  Energy is transferred since work is done ! l How much energy is moving down the string per unit time. (i.e. how much power ?) P

Physics 207: Lecture 21, Pg 21 Wave Power... l Think about grabbing the left side of the string and pulling it up and down in the y direction. l You are clearly doing work since F. dr > 0 as your hand moves up and down. l This energy must be moving away from your hand (to the right) since the kinetic energy (motion) of the string stays the same. P

Physics 207: Lecture 21, Pg 22 Wave Power... l Power is the energy transferred per unit time dE/dt l So what is the energy density? (Energy / Length) For SHM E = ½ k A 2 with  2 = k / m In one wavelength E = ½  m  2 A 2 = ½   2 A 2 In one period P avg =  E/  T = ½  2 A 2 / T and / T = v So P avg = ½   2 A 2 v and v = (F/  ) ½ P

Physics 207: Lecture 21, Pg 23 Lecture 21, Exercise 4 Wave Power l A wave propagates on a string. If just the amplitude and the wavelength are doubled, by what factor will the average power carried by the wave change ? P final /P init = ? Recall P avg = ½   2 A 2 v and / T = v =  / k =  / 2  (A) 1/4 (B) 1/2 (C) 1 (D) 2 (E) 4 initial final

Physics 207: Lecture 21, Pg 24 Recapping y x A l Waves on a string l General harmonic waves tension mass / length

Physics 207: Lecture 21, Pg 25 Transverse and longitudinal waves l Transverse waves: Displacement is perpendicular to the energy flow (velocity). Examples include water waves, waves in a rope, S-waves, …. l Longitudinal waves: Amplitude and velocity have the same “direction”.  Examples: Sound waves, P-waves l Note: Longitudinal waves travel faster than transverse waves (i.e., a larger modulus or spring constant)!

Physics 207: Lecture 21, Pg 26 Chapter 17: Sound, A special kind of longitudinal wave Consider a vibrating guitar string String Vibrates Piece of string undergoes harmonic motion Air molecules alternatively compressed and rarefied Animation

Physics 207: Lecture 21, Pg 27 Sound Now consider your ear Eardrum vibrates Nerves tell brain “sound!”

Physics 207: Lecture 21, Pg 28 Speed of Sound Waves, General l The speed of sound waves in a medium depends on the compressibility and the density of the medium l The compressibility can sometimes be expressed in terms of the elastic modulus of the material l The speed of all mechanical waves follows a general form: Waves on a string 

Physics 207: Lecture 21, Pg 29 Speed of Sound in Liquid or Gas l The bulk modulus of the material is B The density of the material is  l The speed of sound in that medium is

Physics 207: Lecture 21, Pg 30 Speed of Sound in a Solid Rod l The Young’s modulus of the material is Y The density of the material is  l The speed of sound in the rod is

Physics 207: Lecture 21, Pg 31 Speed of Sound in Air l The speed of sound also depends on the temperature of the medium l This is particularly important with gases l For air, the relationship between the speed and temperature is  The 331 m/s is the speed at 0 o C  T C is the air temperature in Centigrade

Physics 207: Lecture 21, Pg 32 Sound Level: How loud is loud? l The range of intensities detectible by the human ear is very large It is convenient to use a logarithmic scale to determine the intensity level, 

Physics 207: Lecture 21, Pg 33 Sound Level l I 0 is called the reference intensity  It is taken to be the threshold of hearing  I 0 = 1.00 x W/ m 2  I is the intensity of the sound whose level is to be determined  is in decibels (dB) Threshold of pain: I = 1.00 W/m 2 ;  = 120 dB Threshold of hearing: I 0 = 1.00 x W/ m 2 ;  = 0 dB

Physics 207: Lecture 21, Pg 34 Sound Level, Example l What is the sound level that corresponds to an intensity of 2.0 x W/m 2 ?  = 10 log (2.0 x W/m 2 / 1.0 x W/m 2 ) = 10 log 2.0 x 10 5 = 53 dB l Rule of thumb: An apparent “doubling” in the loudness is approximately equivalent to an increase of 10 dB. l This factor is not linear with intensity

Physics 207: Lecture 21, Pg 35 Loudness and Intensity l Sound level in decibels relates to a physical measurement of the strength of a sound l We can also describe a psychological “measurement” of the strength of a sound l Our bodies “calibrate” a sound by comparing it to a reference sound l This would be the threshold of hearing l Actually, the threshold of hearing is this value for 1000 Hz

Physics 207: Lecture 21, Pg 36 Lecture 21 Recap l Agenda: l Agenda: Chapter 16, Finish, Chapter 17, Begin  Traveling Waves  Reflection  Transmission  Power  Chapter 17, Sound  Plane Wave, spherical wave  Loudness Assignments: l Problem Set 8 due Nov. 21, Tuesday 11:59 PM Ch. 16: Ch. 16: 3, 18, 30, 40, 58, 59 (Honors) Ch. 17: 3, 15, 34, 38, 40 l For Monday, Chapter 16, Doppler effect Start Chapter 17