Chemical Reaction Engineering Chapter 4, Part 3: Pressure Drop in a Packed Bed Reactor.

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Presentation transcript:

Chemical Reaction Engineering Chapter 4, Part 3: Pressure Drop in a Packed Bed Reactor

Algorithm for Isothermal Reactor Design 1.Mole Balance and Design Equation 2.Rate Law 3.Stoichiometry 4.Combine 5.Evaluate

Algorithm Analyze the following second order gas phase reaction that occurs isothermally in a PBR:

Algorithm Analyze the following second order gas phase reaction that occurs isothermally in a PBR: Mole Balance: Must use the differential form of the mole balance to separate variables:

Algorithm Analyze the following second order gas phase reaction that occurs isothermally in a PBR: Mole Balance: Must use the differential form of the mole balance to separate variables: Rate Law: Second order in A and irreversible:

Algorithm Analyze the following second order gas phase reaction that occurs isothermally in a PBR: Mole Balance: Must use the differential form of the mole balance to separate variables: Rate Law: Second order in A and irreversible: Stoichiometry: with T=T 0

Algorithm Analyze the following second order gas phase reaction that occurs isothermally in a PBR: Mole Balance: Must use the differential form of the mole balance to separate variables: Rate Law: Second order in A and irreversible: Stoichiometry: with T=T 0 Combine: Need to find (P/P 0 ) as a function of W (or V if you have a PFR).

Pressure Drop in Packed Bed Reactors

Ergun Equation:

Pressure Drop in Packed Bed Reactors Ergun Equation:

Pressure Drop in Packed Bed Reactors Ergun Equation:

Pressure Drop in Packed Bed Reactors Ergun Equation: Let

Pressure Drop in Packed Bed Reactors Ergun Equation: Let Catalyst Weight: Let and

Multiple Reactions and Pressure Drop

In terms of conversion:

Multiple Reactions and Pressure Drop In terms of conversion:

Multiple Reactions and Pressure Drop In terms of conversion:

Analytical Solution

Separate Integrate

Analytical Solution For gas phase reactions, as the pressure drop increases, the concentation decreases, resulting in a decreased rate of reaction, hence a lower conversion when compared to a reactor without a pressure drop. Separate Integrate

What if… D p and A c change? } } Laminar Turbulent

What if… D p and A c change? } } Laminar Turbulent

What if… D p and A c change? } } Laminar Turbulent

What if… D p and A c change? } } Laminar Turbulent

Polymath Solution