Chapter 4 Section 3 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley.

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Chapter 4 Section 3 Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

Solving Systems of Linear Equations by Elimination Solve linear systems by elimination. Multiply when using the elimination method. Use an alternative method to find the second value in a solution. Use the elimination method to solve special systems. 4 4

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley 1 Objective 1 Slide Solve linear systems by elimination.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley An algebraic method that depends on the addition property of equality can also be used to solve systems. Adding the same quantity to each side of an equation results in equal sums: If A = B,thenA + C = B + C. Solve linear systems by elimination. Slide We can take this addition a step further. Adding equal quantities, rather than the same quantity, to each side of an equation also results in equal sums: If A = B,thenA + C = B + D. Using the addition property to solve systems is called the elimination method. With this method, the idea is to eliminate one of the variables. To do this, one pair of variable terms in the two equations must have coefficients that are opposite.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 1 Using the Elimination Method Solution: Slide Solve the system. The solution set is A system is not completely solved until values for both x and y are found. Do not stop after finding the value of only one variable. Remember to write the solution set as a set containing an ordered pair

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solving a Linear System by Elimination Slide In general, use the following steps to solve a linear system of equations by the elimination method. Step 1: Write both equations in standard form, Ax + By = C. Step 2: Transform the equations as needed so that the coefficients of one pair of variable terms are opposites. Multiply one or both equations by appropriate numbers so that the sum of the coefficients of either the x- or y-term is 0. Step 3: Add the new equations to eliminate a variable. The sum should be an equation with just one variable. Step 5: Substitute the result from Step 4 into either of the original equations, and solve for the other variable. Step 4: Solve the equation from Step 3 for the remaining variable. Step 6: Check the solution in both of the original equations. Then write the solution set. It does not matter which variable is eliminated first. Choose the one that is more convenient to work with.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 2 Using the Elimination Method Solution: Slide Solve the system. The solution set is

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley 2 Objective 2 Multiply when using the elimination method. Slide

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 3 Multiplying Both Equations When Using the Elimination Method Solution: Slide Solve the system. The solution set is When using the elimination method, remember to multiply both sides of an equation by the same nonzero number.

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley 3 Objective 3 Use an alternative method to find the second value in a solution. Slide

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 4 Finding the Second Value by Using an Alternative Method Solution: Slide Solve the system. The solution set is + +

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley 4 Objective 4 Use the elimination method to solve special systems. Slide

Copyright © 2008 Pearson Education, Inc. Publishing as Pearson Addison-Wesley EXAMPLE 5 Using the Elimination Method for an Inconsistent System or Dependent Equations Solution: Slide Solve each system by the elimination method. The solution set is + +