Chapter 2 Sections 5-6 Problem Solving and Formulas.

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Presentation transcript:

Chapter 2 Sections 5-6 Problem Solving and Formulas

Problem Solving The length of a rectangle is 6 inches more than its width. The perimeter of the rectangle is 24 in. What is the length? w w + 6 P = 2l +2w 24 = 2(w+6) + 2(w) 24 = 2w w 24 = 4w = 4w 3 = w l = w + 6 l = 3 +6 l = 9 in

The width of a rectangle is 2 cm less than its length. The perimeter of the rectangle is 16 cm. What is the length? l – 2 l P = 2l + 2w 16 = 2l + 2 (l - 2) 16 = 2l + 2l – 4 16 = 4l – 4 20 = 4l l = 5 cm

Consecutive Integers-differ by 1. The sum of three consecutive integers is 147. Find the integers. N: first number N+1: second number N +2 : third number N + N N + 2 = 147 3N + 3 = 147 3N = 144 N = 48 48, 49, 50

The sum of three consecutive integers is 48. The sum of four consecutive even integers is 60. The sum of two consecutive odd integers is 44.

Literal Equation- two or more variables Solve the formula A = ½ bh for height h. Solve the formula for the perimeter of a rectangle for the width. P = 2(l + w) Solve the formula V = lwh for w.

Transforming Equations Solve y = 5x + 7 for x. Solve z – br = p for b. Solve y + 2x = 5 for y. Solve 5x + 4y = 4 for y. Solve 2x + 7y = 4 for y.

HW # 6 Page 107 (1, 2, 4, 6 -8) Page 113 (1-6, 9 -14)