Piecewise-defined Functions y x O Ex. 1: x 2 4 6 ... y –1 0 1 ... h/d h d d ... ½ x – 2, x > 2 (1, 3) f(x) = 3, x = 1 x –2 –1 0 1 y 7 5 3 1 h/d d d d h –2x + 3, –2 ≤ x < 1 Domain: [–2, 1]  (2, ∞) Range: (–1, ∞) Evaluate: a) f(0) = 3 b) f(1) = 3 c) f(2) = undefined y x O Ex. 2: x –3 –4 –5 ... y –4 –5 –6 ... h/d h d d ... x – 1, x < –3 (4, 1) f(x) = –2/3 x + 2, –3 ≤ x < 3 x –3 0 3 y 4 2 0 h/d d d h x – 3, x = 4 Domain: (–∞, 3)  {4} Range: (–∞, –4)  (0, 4] Evaluate: a) f(–1) = 22/3 b) f(3) = undefined c) f(4) = 1

Piecewise-defined Functions (cont’d) y x O Ex. 3: x 2 4 6 ... y 1 –2 –5 ... h/d h d d ... –3/2 x + 4, x > 2 f(x) = x –3 –2 0 1 2 y –7 –5 –1 1 3 h/d h d d d d 2x – 1, –3 < x ≤ 2 Domain: (–3, ∞) Range: (–∞, 3] Evaluate: a) f(–2) = –5 b) f(2) = 3 c) f(4) = –2 y x O x –3 –2 –1 0 1 y 3 2 1 0 1 h/d d d d d h Ex. 4: |x|, –3 ≤ x < 1 x 1 2 y 3 3 h/d d h f(x) = 3, 1 ≤ x < 2 (3, –2) x – 5, x = 3 Domain: [–3, 2)  {3} Range: _{–2}  [0, 3]_ Evaluate: a) f(–3) = 3 b) f(1.5) = 3 c) f(3) = –2

Piecewise-defined Functions (cont’d) y x O x 1 4 9 … y 1 2 3 … h/d h d d … Ex. 5:  x, x > 1 x –2 –1 0 1 y 4 1 0 1 h/d h d d d f(x) = x2, –2 < x ≤ 1 –2x – 7, x ≤ –2 x –2 –3 –4 … y –3 –1 1 … h/d d d d … Domain: (–∞, ∞) Range: [–3, ∞) Evaluate: a) f(4) = 2 b) f(1) = 1 c) f(–3) = –1 y x O Ex. 6: ½x + 3/2, x ≥ 1 1, –3 ≤ x < 1 x + 2, x < –3 f(x) = Domain: (–∞, ∞) Range: (–∞, –1)  {1}  [2, ∞) Increasing: (–∞, –3)  (1, ∞) Decreasing: None

Piecewise-defined Functions (cont’d) y x O is in Ex. 7: –½x, x  (2, ∞) x2, x  (–1, 2] –2x – 1, x  (–∞, –1) f(x) = Domain: (–∞, –1)  (–1, ∞) Range: (–∞, –1)  (0, ∞) Increasing: (0, 2) Decreasing: (–∞, –1)  (–1, 0)  (2, ∞) y x O Ex. 8: 2x – 6, x  [3, ∞) |x|, x  [–2, 3) x + 4, x  (–∞, –2) f(x) = Domain: (–∞, ∞) Range: (–∞, ∞) Increasing: (–∞, –2)  (0, 3) Decreasing: (–2, 0)  (3, ∞) 2x – 6, x  [3, ∞) |x|, x  (–2, 3) x + 4, x  (–∞, –2] OR f(x) =