The Chemistry of Acids and Bases. Acids and Bases: Titration At the conclusion of our time together, you should be able to: 1. Do a titration of an acid.

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Presentation transcript:

The Chemistry of Acids and Bases

Acids and Bases: Titration At the conclusion of our time together, you should be able to: 1. Do a titration of an acid with a base 2. Calculate the equivalence point (neutralization point) for a titration problem 3. Define normality

Familiar Saying Failure to be present causes the vital organ to become more enamored. Distance makes the heart grow fonder!!

ACID-BASE REACTIONS Titrations H 2 C 2 O 4 (aq) + 2 NaOH(aq) ---> acid base acid base Na 2 C 2 O 4 (aq) + 2 H 2 O(liq) Carry out this reaction using TITRATION. Oxalic Acid, H 2 C 2 O 4

Setup For Titrating An Acid With A Base

TitrationTitration 1. Add solution from the buret. 2. Reagent (base) reacts with compound (acid) in solution in the flask. 3. Indicator shows when exact stoichiometric reaction has occurred. (Acid = Base) This is called the NEUTRALIZATION point. This is called the NEUTRALIZATION point. The equivalence point has been reached

The Formula for Titration Use: Use: M 1 * E * V 1 = M 2 * E * V 2 M = molarity of acid and base E = number of H+ or OH- per mole of acid or base M x E = Normality V = volume

Various Protic Titration #1: Standardize a solution of NaOH — i.e., accurately determine its concentration mL of M NaOH is neutralized with 25.0 mL of HCl by titration to an equivalence point. What is the concentration of the acid?

How do you do this?? Use: Use: M 1 * E * V 1 = M 2 * E * V M x 1 x 32.7 mL = M x 1 x 25.0 mL = M HCl pH= -log (0.131 x 1) = 0.883

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#2: You have 50.0 mL of M NaOH neutralized 20.0 mL of sulfuric acid. Determine the M of the acid? M x 1 x 50.0 mL = M x 2 x 20.0 mL = M H 2 SO 4 For each mole of sulfuric acid there are 2 moles of H +, therefore, pH = -log (0.313 x 2) = 0.203

Bill Gates' Rules Here is a list of 11 things that many high school and college graduates did not learn in school. In his book, Bill Gates talks about how feel-good, politically-correct teachings created a full generation of kids with no concept of reality and how this concept has set them up for failure in the real world. RULE 5 Flipping burgers is not beneath your dignity. Your grandparents had a different word for burger flipping; they called it opportunity.

Acids and Bases: Titration Let’s see if you can: 1. Do a titration of an acid with a base 2. Calculate the equivalence point (neutralization point) for a titration problem 3. Define normality

#4 Various Protic Use: Use: M 1 * E * V 1 = M 2 * E * V M x 2 x 29.6 mL = M x 1 x 40.0 mL = M HNO 3 pOH= -log ( x 2) = 1.00

Pass the Clicker!!!

Normality is defined as M * V 2. E * V 3. M * E 4. M * E * V 5. Not listed

A method used to determine the concentration of an unknown acid or base Equivalence point 2. Neutralization point 3. Titration 4. Titrant 5. Normality 6. Flask 7. Buret 8. Not listed

The titrant is usually added to a(n) Equivalence point 2. Neutralization point 3. Titration 4. Titrant 5. Normality 6. Flask 7. Buret 8. Not listed

The indicator is usually added to the Equivalence point 2. Neutralization point 3. Titration 4. Titrant 5. Normality 6. Flask 7. Buret 8. Not listed

Going Down!!

3 M sulfuric acid would have a normality of N 2. 2 N 3. 5 N 4. 6 N 5. 9 N 6. Not listed

100.0 mL of 3.0 M sulfuric acid neutralizes 50.0 mL of sodium hydroxide. What is the molarity of the base? M M M M M 6. Not listed

100.0 mL of M nitric acid neutralizes M of aluminum hydroxide. How many mL of the base did you use? mL mL mL mL mL 6. Not listed

Murphy's Laws of Science and Technology Whenever a system becomes completely defined, some fool discovers something which either abolishes the system or expands it beyond recognition.

The Chemistry of Acids and Bases

Acids and Bases: Titration At the conclusion of our time together, you should be able to: 1. Do a titration of an acid with a base 2. Calculate the equivalence point (neutralization point) for a titration problem 3. Define normality 4. Determine the percent acid with a titration problem

You will pay, I guarantee it!!!

Lemonade Titration Problem M x 1 x 8.70 mL = M x 3 x 10.0 mL = M citric acid

Lemonade Titration Problem M x L = x g g/mol = g in 10 mL

Lemonade Titration Problem Using the density of citric acid in lemonade: 10.0 mL x g/mL = 9.60 g lemonade in 10.0 mL of solution g citric acid in 10.0 mL x 100 = 9.60 g lemonade in 10.0 mL 0.580%