Semiconductor Device Modeling and Characterization EE5342, Lecture 1-Spring 2011 Professor Ronald L. Carter

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Semiconductor Device Modeling and Characterization EE5342, Lecture 1-Spring 2011 Professor Ronald L. Carter

©rlc L01 19Jan20112 Web Pages *Bring the following to the first class R. L. Carter’s web page – EE 5342 web page and syllabus – University and College Ethics Policies

©rlc L01 19Jan20113 First Assignment to –In the body of the message include subscribe EE5342 This will subscribe you to the EE5342 list. Will receive all EE5342 messages If you have any questions, send to with EE5342 in subject line.

©rlc L01 19Jan20114 A Quick Review of Physics Review of –Semiconductor Quantum Physics –Semiconductor carrier statistics –Semiconductor carrier dynamics

©rlc L01 19Jan20115 Bohr model H atom Electron (-q) rev. around proton (+q) Coulomb force, F=q 2 /4  o r 2, q=1.6E-19 Coul,  o =8.854E-14 Fd/cm Quantization L = mvr = nh/2  E n = -(mq 4 )/[8  o 2 h 2 n 2 ] ~ eV/n 2 r n = [n 2  o h]/[  mq 2 ] ~ 0.05 nm = 1/2 A o for n=1, ground state

©rlc L01 19Jan20116 Quantum Concepts Bohr Atom Light Quanta (particle-like waves) Wave-like properties of particles Wave-Particle Duality

©rlc L01 19Jan20117 Energy Quanta for Light Photoelectric Effect: T max is the energy of the electron emitted from a material surface when light of frequency f is incident. f o, frequency for zero KE, mat’l spec. h is Planck’s (a universal) constant h = 6.625E-34 J-sec

©rlc L01 19Jan20118 Photon: A particle -like wave E = hf, the quantum of energy for light. (PE effect & black body rad.) f = c/, c = 3E8m/sec, = wavelength From Poynting’s theorem (em waves), momentum density = energy density/c Postulate a Photon “momentum” p = h/  = hk, h = h/2  wavenumber, k =  2  /

©rlc L01 19Jan20119 Wave-particle Duality Compton showed  p = hk initial - hk final, so an photon (wave) is particle-like DeBroglie hypothesized a particle could be wave-like,  = h/p Davisson and Germer demonstrated wave-like interference phenomena for electrons to complete the duality model

©rlc L01 19Jan Newtonian Mechanics Kinetic energy, KE = mv 2 /2 = p 2 /2m Conservation of Energy Theorem Momentum, p = mv Conservation of Momentum Thm Newton’s second Law F = ma = m dv/dt = m d 2 x/dt 2

©rlc L01 19Jan Quantum Mechanics Schrodinger’s wave equation developed to maintain consistence with wave-particle duality and other “quantum” effects Position, mass, etc. of a particle replaced by a “wave function”,  (x,t) Prob. density = |  (x,t)   (x,t)|

©rlc L01 19Jan Schrodinger Equation Separation of variables gives  (x,t) =  (x)  (t) The time-independent part of the Schrodinger equation for a single particle with KE = E and PE = V.

©rlc L01 19Jan Solutions for the Schrodinger Equation Solutions of the form of  (x) = A exp(jKx) + B exp (-jKx) K = [8  2 m(E-V)/h 2 ] 1/2 Subj. to boundary conds. and norm.  (x) is finite, single-valued, conts. d  (x)/dx is finite, s-v, and conts.

©rlc L01 19Jan Infinite Potential Well V = 0, 0 < x < a V --> inf. for x a Assume E is finite, so  (x) = 0 outside of well

©rlc L01 19Jan Step Potential V = 0, x < 0 (region 1) V = V o, x > 0 (region 2) Region 1 has free particle solutions Region 2 has free particle soln. for E > V o, and evanescent solutions for E < V o A reflection coefficient can be def.

©rlc L01 19Jan Finite Potential Barrier Region 1: x < 0, V = 0 Region 1: 0 < x < a, V = V o Region 3: x > a, V = 0 Regions 1 and 3 are free particle solutions Region 2 is evanescent for E < V o Reflection and Transmission coeffs. For all E

©rlc L01 19Jan Kronig-Penney Model A simple one-dimensional model of a crystalline solid V = 0, 0 < x < a, the ionic region V = V o, a < x < (a + b) = L, between ions V(x+nL) = V(x), n = 0, +1, +2, +3, …, representing the symmetry of the assemblage of ions and requiring that  (x+L) =  (x) exp(jkL), Bloch’s Thm

©rlc L01 19Jan K-P Potential Function*

©rlc L01 19Jan K-P Static Wavefunctions Inside the ions, 0 < x < a  (x) = A exp(j  x) + B exp (-j  x)  = [8  2 mE/h] 1/2 Between ions region, a < x < (a + b) = L  (x) = C exp(  x) + D exp (-  x)  = [8  2 m(V o -E)/h 2 ] 1/2

©rlc L01 19Jan K-P Impulse Solution Limiting case of V o -> inf. and b -> 0, while  2 b = 2P/a is finite In this way  2 b 2 = 2Pb/a < 1, giving sinh(  b) ~  b and cosh(  b) ~ 1 The solution is expressed by P sin(  a)/(  a) + cos(  a) = cos(ka) Allowed values of LHS bounded by +1 k = free electron wave # = 2  /

©rlc L01 19Jan K-P Solutions* P sin(  a)/(  a) + cos(  a) vs.  a x x

©rlc L01 19Jan K-P E(k) Relationship*

©rlc L01 19Jan References *Fundamentals of Semiconductor Theory and Device Physics, by Shyh Wang, Prentice Hall, **Semiconductor Physics & Devices, by Donald A. Neamen, 2nd ed., Irwin, Chicago.