Series and parallel. (a) recall and use appropriate circuit symbols (b) draw and interpret circuit diagrams containing sources, switches, resistors, ammeters,

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Presentation transcript:

Series and parallel

(a) recall and use appropriate circuit symbols (b) draw and interpret circuit diagrams containing sources, switches, resistors, ammeters, voltmeters, and/or any other type of component referred to in the syllabus (e) derive, using Kirchhoff’s laws, a formula for the combined resistance of two or more resistors in series (f) solve problems using the formula for the combined resistance of two or more resistors in series (g) derive, using Kirchhoff’s laws, a formula for the combined resistance of two or more resistors in parallel (h) solve problems using the formula for the combined resistance of two or more resistors in parallel

Key points Adding resistors in series increases the effective resistance. Adding resistors in parallel decreases the effective resistance.

Combining lamps in series and parallel What is the defining equation for resistance R = V / I where V is the pd across a component and I is the current through it. Watch the demonstration – What happens to the current? And V? The ratio V/I has increased: adding resistors in series increases overall resistance. Watcch again – What happens this time? The current increases and the effective (load) resistance decreases.

Deriving formulae You are trying to find the single resistor R tot which will have the same resistance as two or more resistors R 1, R 2 etc in series Series resistors have the same current but the pds add, so: V tot = I R tot = I R 1 + I R Then divide by I to get R tot

Deriving formulae Parallel resistors have all have the same pd across them but the currents add, so: I tot = V / R tot = V / R 1 + V / R 2 etc... then divide by V to get..... I tot /V = 1 / R tot = 1 / R1 + 1 / R2... Note you still have to take the reciprocal to get the value of R tot.

Hate reciprocals? It is unusual (at A-level) for questions to involve more than two resistors in parallel so the parallel formula for two resistors can be rearranged to give: R tot = R 1 R 2 / (R 1 +R 2 ) or ‘product over sum’. This can save the faint-hearted from reciprocals! When n resistors of the same value (R) are connected in parallel the result is an effective resistance R / n.

Example Calculate the combined resistance of A 40Ω resistor and a 60Ω resistor: In series In parallel

Predicting and measuring resistance Carry out the experiment – Resistors in series and parallel

Reading p206 – 209 Practice P216&7 q4 – 8 P274 q1&2 Weblinks