Series Resistive Circuits Let’s Review!!!! Current The flow of electrons in a conductive path. I is the symbol for current. Current is measured in Amperes.

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Presentation transcript:

Series Resistive Circuits

Let’s Review!!!! Current The flow of electrons in a conductive path. I is the symbol for current. Current is measured in Amperes or Amps. A is the symbol for Amps.

Let’s Review!!!! Voltage The force that produces a current. V and E are the symbols for voltage. Voltage is measured in Volts. V is the symbol for Volts.

Let’s Review!!!! Resistance The opposition to the flow of electrons. R is the symbol for resistance. Resistance is measured in Ohms. Ω is the abbreviation for Ohms.

Let’s Review!!!! Ohm’s Law The mathematical relationship between Current, Voltage and Resistance. RI V V = I  RV = I  R I = V / R R = V / I

Let’s Play Press this button to set up different circuits with light bulbs attached in series.

Series Circuits A Series Circuit offers a single continuous path for current to flow. Voltage Source Load “R” Current Path

Series Circuit I _ + VR

Current is the same everywhere in the circuit. The Total Resistance is the sum of all the individual resistors. The Sum of the Voltage Drops across each resistor is equal to the Source Voltage.

ITIT _ + VTVT R2R2 I1I1 I3I3 I2I2 R1R1 R3R3 I T = I 1 = I 2 = I 3 V T = V 1 + V 2 + V 3 R T = R 1 + R 2 + R 3

Series Circuit Simulator Press this button to see what the effects of changes the voltage and the resistance has on the circuit current ins a series circuit. Go to the circuit section of this demonstration.

Example #1 V T = 10v ITIT _ + I1I1 I2I2 R 1 =2Ω R 2 =3Ω 2A Component R( Ω) I(A)V(V) R1R1 R2R2 Total 2Ω2Ω 3Ω3Ω 10V

Find: R T R T = R 1 + R 2 R T = 2Ω + 3Ω R T = 5Ω

Example #1 V T = 10v ITIT _ + I1I1 I2I2 R 1 =2Ω R 2 =3Ω 2A Component R( Ω) I(A)V(V) R1R1 R2R2 Total 2Ω2Ω 3Ω3Ω 10V 5Ω5Ω

Find: I T IT =IT = I T = 10v / 5Ω I T = 2A I T = I 1 = I 2 = 2A RTRT ITIT VTVT Ohm’s Law VT / RTVT / RT

Example #1 V T = 10v ITIT _ + I1I1 I2I2 R 1 =2Ω R 2 =3Ω 2A Component R( Ω) I(A)V(V) R1R1 R2R2 Total 2Ω2Ω 3Ω3Ω 10V 5Ω5Ω2A

In a series circuit current is the same throughout the circuit!!! I T = I 1 = I 2

Example #1 V T = 10v ITIT _ + I1I1 I2I2 R 1 =2Ω R 2 =3Ω 2A Component R( Ω) I(A)V(V) R1R1 R2R2 Total 2Ω2Ω 3Ω3Ω 10V 5Ω5Ω2A

Find: V 1 R1R1 I1I1 V1V1 Ohm’s Law V1=V1= I1  R1I1  R1 V 1 = 2A  2Ω V 1 = 4V

Example #1 V T = 10v ITIT _ + I1I1 I2I2 R 1 =2Ω R 2 =3Ω 2A Component R( Ω) I(A)V(V) R1R1 R2R2 Total 2Ω2Ω 3Ω3Ω 10V 5Ω5Ω2A 4V

R2R2 I2I2 V2V2 Ohm’s Law Find: V 2 V2=V2= I2  R2I2  R2 V 2 = 2A  3Ω V 2 = 6V

Example #1 V T = 10v ITIT _ + I1I1 I2I2 R 1 =2Ω R 2 =3Ω 2A Component R( Ω) I(A)V(V) R1R1 R2R2 Total 2Ω2Ω 3Ω3Ω 10V 5Ω5Ω2A 4V 6V

Example V T = 20v R 2 =4Ω ITIT _ + I1I1 I3I3 I2I2 R 1 =1Ω R 3 =5Ω Component R( Ω) I(A)V(V) R1R1 R2R2 R3R3 Total 1Ω1Ω 4Ω4Ω 5Ω5Ω 20v

Find: R T R T = R 1 + R 2 + R 3 R T = 1Ω + 4Ω + 5Ω R T = 10Ω

Example V T = 20v R 2 =4Ω ITIT _ + I1I1 I3I3 I2I2 R 1 =1Ω R 3 =5Ω Component R( Ω) I(A)V(V) R1R1 R2R2 R3R3 Total 1Ω1Ω 4Ω4Ω 5Ω5Ω 20v10Ω

Find: I T IT =IT = I T = 20v / 10Ω I T = 2A I T = I 1 = I 2 = I 3 = 2A RTRT ITIT VTVT Ohm’s Law VT / RTVT / RT

Example V T = 20v R 2 =4Ω ITIT _ + I1I1 I3I3 I2I2 R 1 =1Ω R 3 =5Ω Component R( Ω) I(A)V(V) R1R1 R2R2 R3R3 Total 1Ω1Ω 4Ω4Ω 5Ω5Ω 20v10Ω2A

Find: V 1 R1R1 I1I1 V1V1 Ohm’s Law V1=V1= I1  R1I1  R1 V 1 = 2A  1Ω V 1 = 2V

Example V T = 20v R 2 =4Ω ITIT _ + I1I1 I3I3 I2I2 R 1 =1Ω R 3 =5Ω Component R( Ω) I(A)V(V) R1R1 R2R2 R3R3 Total 1Ω1Ω 4Ω4Ω 5Ω5Ω 20v10Ω2A 2v

Find: V 2 R2R2 I2I2 V2V2 Ohm’s Law V2=V2= I2  R2I2  R2 V 2 = 2A  4Ω V 2 = 8V

Example V T = 20v R 2 =4Ω ITIT _ + I1I1 I3I3 I2I2 R 1 =1Ω R 3 =5Ω Component R( Ω) I(A)V(V) R1R1 R2R2 R3R3 Total 1Ω1Ω 4Ω4Ω 5Ω5Ω 20v10Ω2A 2v 8v

Find: V 3 R3R3 I3I3 V3V3 Ohm’s Law V3=V3= I3  R3I3  R3 V 3 = 2A  5Ω V 3 = 10V

Example V T = 20v R 2 =4Ω ITIT _ + I1I1 I3I3 I2I2 R 1 =1Ω R 3 =5Ω Component R( Ω) I(A)V(V) R1R1 R2R2 R3R3 Total 1Ω1Ω 4Ω4Ω 5Ω5Ω 20v10Ω2A 2v 8v 10v

Example VTVT I T =4mA _ + I1I1 I2I2 R 1 =8kΩ R 2 =2kΩ 2A Component R( Ω) I(mA)V(V) R1R1 R2R2 Total 8k Ω 2k Ω 4mA

I T = I 1 = I 2

Example VTVT I T =4mA _ + I1I1 I2I2 R 1 =8kΩ R 2 =2kΩ 2A Component R( Ω) I(mA)V(V) R1R1 R2R2 Total 8k Ω 2k Ω 4mA 10kΩ 32v 8v 40v

Find: R T R T = R 1 + R 2 R T = 2kΩ + 8kΩ R T = 10kΩ or 10,000Ω Press this button to go back to previous screen.

Find: I 1,2 I T = 4mA I T = I 1 = I 2 = 4mA Press this button to go back to previous screen.

Find: E T RTRT ITIT VTVT Ohm’s Law VT=VT= IT  RTIT  RT V T = 4mA  10kΩ V T = 40V Press this button to go back to previous screen. V T = 0.004A  10,000Ω

Find: E 1 R1R1 I1I1 V1V1 Ohm’s Law VT=VT= I1  R1I1  R1 V T = 4mA  8kΩ V T = 32V Press this button to go back to previous screen. V T = 0.004A  8,000Ω

Find: E 2 R2R2 I2I2 V2V2 Ohm’s Law V2=V2= I2  R2I2  R2 V T = 4mA  2kΩ V T = 8V Press this button to go back to previous screen. V T = 0.004A  2,000Ω

Let’s Practice V T = 100V I T =10mA _ + I1I1 I2I2 R 1 = 4kΩ R 2 = ? Find: I 1 I 2 R T R 2 V 1 V 2 Draw this circuit on a sheet of paper.