We use ratios to make comparisons between two things. Ratios can be written 3 ways. 1. As a fraction 3 5 We are comparing rectangles to triangles. 2. Using the word to 3 to 5 3. Using a colon 3:5 equivalent ratios Ratios that name the same comparisons To see if to ratios are equivalent 1. Change each to a decimal and compare the decimals. 2. Reduce both ratios and compare. 3. Use cross products.

Rate: is a ratio of 2 measurements with different units Example: It rained 4 inches in 30 days Here we are comparing days to inches The rate is 4 30 We can reduce to 2 15 A rate that has 1 unit as its second term (denominator) If a car travels 325 miles and uses 11 gallons of gas what is the mile per gallon? This is an example of a unit rate. How many miles per 1 gallon? Create a ratio Miles Gallons Since every fraction is a division problem we divide 325/ 11 Our Unit Rate is miles per gallon

Unit rates are often used to make comparisons. Drivers often use Miles Per Gallon(mpg) or Miles Per Hour(mph) Example: the 8th grade parents collect $ 2450 for pizza sales and the 7th grade parents collect $ 2250 for selling Subway. If there were th graders and th graders, which group collect more per student? We have 2 rates. 8th $ = $ 24.90/ student 7th $ = $ 25 per student The 7th grade parents collect $ 0.10 more per student We can make each a unit rate to see which group had more dollars per student.

Shop Rite has 24 oz box of Hulk Cereal for $ Path Mark has a 1lb box for$ Which is the better buy? Notice in this box the units are different (oz, lbs) Before we solve we need to make the units the same. 1 lb = 16 oz The rates are: Shop RitePath Mark $ oz $ oz We find the unit rates by division. = about $ 0.17per oz= about $ 0.16 per oz Shop Rite has the better buy on Hulk Cereal

An equation that shows that two ratios are equal We can write proportions in 2 forms. a:b = c:d If 2 ratios are equal then their cross product will be equal. a * d = b * c

A car travels 125 miles in 5 hours. How many miles will the car travel in 8 hours? Solve using proportions. Set an equation using cross products 125 = m * 8 = 5 * m Proportion Simplify1000 = 5m Solve by inverse operation (The opposite of multiplication is division ) 1000 /5 = m 200 = m In 8 hours a car can travel 200 miles

On a map 1.5 inches is equal to 5 miles. If the distance in real life is 22 mile how big will it be on the map? Proportions can help us with this problem. We know 1 ratio is 1.5 in: 5 m. We know 1 part of the second ratio is 22 m. Proportion1.5 in = X m 5 m 22 m Notice we lined up m to m and in to in Cross Products 1.5 x 22 = 5 x X Simplify 33 = 5X Inverse Operation33/5 = X 6.6 = X 22 miles is equal to 6.6 inches on the map

Dinner cost $75 and you wish to leave a 20% tip. How much will the tip be? We can use the percent proportion to solve. P = R B P is the percentage ( a value that is a number for the percent B is the base or the original amount R is the rate(the percent number over 100) In this problem the Base is $75, the Rate is 20 over 100 and we are solving for the Percentage ( how much money is equal to 20%) P = 20 $ Cross products 75 x 20 = P x 100 Simplify 1500 = 100P Inverse operation 1500/ 100 = P $15 = P The tip will be $15

We have seen 1 type of percent problem. Let’s look at 2 others. If we left a 20% tip which was $25, how much was the bill? Proportion 25 = 20 B 100 We know R is 20% and P is $25. We need to find B. Cross products 25 x 100 = 20 x B Simplify 2500 = 20B Inverse Operation 2500/ 20 = B $125 = B The dinner bill was $125

If Dinner cost $125 and we left a $35 tip what percent of the bill was the tip? P is $35, B is $125. We are trying to find R. Proportion 35= R Cross Products35 x 100 = 125 x R Simplify3500= 125 R Inverse Operation3500/ 125 = R 28% = R The tip was 28% of the bill

We have used a proportion to solve percent problems for P, R, and B. We can rewrite the proportion to an equation. P = R x B 1. Dinner cost $75 and you wish to leave a 20% tip. How much will the tip be? Let us look at the previous problems using the equation. P = R x B Formula Substitute P = 20% x $75 Solve: use the decimal form of the % P = 0.2 x 75 P = $15 The tip will be $15

2. If we left a 20% tip which was $25, how much was the bill? P = R x B Formula Substitute $ 25 = 20% x B Solve using inverse operation = B 125 = B The dinner bill was $125

3. If Dinner cost $125 and we left a $35 tip what percent of the bill was the tip? Formula Substitute Solve using inverse operation P = R x B $ 35 = R x $ = R Note: We are dividing by numbers not the rate so we use the numbers = RSince our answer is a decimal we convert that decimal to get a percent 28% = R The tip was 28% of the bill

When money is borrowed, interest is charged for the use of that money for a certain period of time. When the money is paid back, the principal (amount of money that was borrowed) and the interest is paid back. The amount to interest depends on the interest rate, the amount of money borrowed (principal) and the length of time that the money is borrowed. The formula for finding simple interest is: Interest = Principal * Rate * Time How much will the interest be if we borrow 20,000 for 2 years at 6%? I = P x R x T I = x 6% x 2 Note: we use the decimal form to multiply and the length of time is based on 1 year. I = x 0.06 x 2 I = 2400 The interest will be $ 2400

If we put in the bank at 5.5% for 18 months, How much will we have at the end of 18 months? There are differences in this problem 1. The interest rate has a decimal 2. The time is not if full years 3. We are asked for a total not just the interest. I = P x R x T I = x 5.5% 18 months I = x x Note: since 1 year = 12 months we use 12 as a denominator. We could reduce ( 1 1 ) or use the decimal form(1.5) 2 I = 1650 This is the interest. We now add that to the principle of = The total at the end of the time period is $21650

Many of the things we buy, the money we earn and the places we live come with a tax..The tax is found by finding a percentage of the purchase or income called the tax rate. By finding the percentage we can calculate tax. In much the same way we did with simple interest except we eliminate the time component of the formula. The formula can be written: When a total is asked for we add the percentage to the original amount as we did with simple interest. Tax = Principle * tax rate

We purchased a car for $28,568. If the tax rate is 6%, how much tax did we pay? Tax = Principle * tax rate T = $28568 * 6% T = * 0.06 T = The tax on our car is $ What is the total cost of the car? This problem requires us to just add the tax and the price of the car much the same as we did with the total for simple interest. $ $ = $ $ is the total cost of the car

Retailers often offer sales. They are usually in percents, We can solve these problems in the same way using percents. A DVD is on sale for 20% off. It originally sells for $275. How much will we save? We can put our % equation in this form. D = P * RD = $275 * 20%D = 275 * 0.2D = 55 The discount on the DVD is $ 55 What is the sale price of the DVD? To solve we just subtract our discount from the original price $ $55 = $ 225 The sale price of the DVD is $ 225

Macy’s is having a 20% off sale. If you buy it today you receive an additional 15% of the sale price.If you buy a $45 sweater today how much will it cost? In this problem it looks as if you will get 35% off. But we will only get 15% off the sale price not the original price. D = $ 36 *15 % D = 45 * 0.2D = $ 9$ 45 - $ 9 = $36 The sale price is $ 36. Now we take off the 15%. D = 36 * 0.15D = $ 5.40$ 36 - $ 5.40 = $31.60 D = $ 45 *20 % The final price is $ But how much would it be if there was a 6% sales tax???

Often times when we buy things they can either increase in value (appreciate) or decrease in value (depreciate). Usually, the homes we buy appreciate. When we sell our homes we often get more than we paid for them. We also buy stocks in the hope that they will also go up (not always the case) On the other hand, cars often go down in value as they get older. The differences can looked at as Percent of Change. We refer to these situations as either the percent of increase (appreciation) or the percent of decrease (depreciation)

Joe Smith bought his home in 1999 for $ 325,000 and sold it in 2003 for $ 545,000. What was his percent of increase? 1. Determine whether this is an increase or a decrease. ( If the new price is higher it is an increase. If the new price is lower it is a decrease. In this case the price is an increase). 2. Subtract the higher price from the lower price to find the difference. $545,000 - $325,000 = $220, Make a fraction by placing the difference over the original price. $ 220,000 $ 325,000 difference Original price 4. Change the fraction to a decimal by division. Then to a percent by moving the decimal point. The percent of increase is 67.7% (Answer rounded to the nearest tenth of a percent).

Mrs. Princing bought stock in the I.O.U company worth $5500 in May. In June the stock was worth $3000. Find the percent of change in the stock. Find the difference. $ $3000 = $2500 Since the new price is lower we will be finding the percent of decrease. Make a fraction $ 2500 $ 5500 Change to decimal Change to percent 45.5% The percent of change (decrease) for Mrs. Princing’s stock is 45.5 % ( rounded to the nearest tenth).