Chapter 19 Gas Stoichiometry.

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Presentation transcript:

Chapter 19 Gas Stoichiometry

If an excess of chlorine gas reacts with a solution containing 20 If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl

If an excess of chlorine gas reacts with a solution containing 20 If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr

If an excess of chlorine gas reacts with a solution containing 20 If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 119g KBr

If an excess of chlorine gas reacts with a solution containing 20 If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 119g KBr 2 mol KBr

If an excess of chlorine gas reacts with a solution containing 20 If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 119g KBr 2 mol KBr 1 mol Br2

If an excess of chlorine gas reacts with a solution containing 20 If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 1000 cm3 119g KBr 2 mol KBr 1 mol Br2 1 dm3

If an excess of chlorine gas reacts with a solution containing 20 If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 1000 cm3 119g KBr 2 mol KBr 1 mol Br2 1 dm3 = 1880 cm3

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 22.4 dm3

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 22.4 dm3 3 mol O2

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 27.0 g 22.4 dm3 3 mol O2 mol Al

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 27.0 g = 8.04 g 22.4 dm3 3 mol O2 mol Al

How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl

How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl

H2 + Cl2 → 2HCl This is a volume – volume calculation. How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations. 50.0 cm3 HCl

H2 + Cl2 → 2HCl This is a volume – volume calculation. How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations. 1 cm3 Cl2 50.0 cm3 HCl = 25.0 cm3 2 cm3 HCl

Homework Gas Laws Lab (due today). Worksheet: Ideal Gas Equation (due tomorrow). Worksheet: Gas Stoichiometry (due in two days). Lab Summary: “Molecular Mass of a Gas” (due in two days). Study Guide Chapter 19 (due in two days).