Integrating Vector Particle Physics with the Dodecahedron Quark Ball and the Octahedral Hexagonal Fractal ©WRHohenberger By William R Hohenberger Natural Philosophy Alliance April 6, 2013 Internet Video Presentation

Table of Contents Part 1 – The Electromagnetic Wave Part 2 – The Octahedral Hexagonal Fractal Part 3 – Electron Cube Vs Octahedral Hexagonal Fractal Part 4 – Other Considerations Part 5 – Summary ©WRHohenberger

1.There is an aether that pervades all of the spaces within the universe including both the material and the nonmaterial worlds. Therefore, aether is a real substance!!! 2.Aether is a hyper-dynamic, non-homogeneous, elastic substance that contians a myriad of plethora's of various field structures, as holistic arrays of constantly changing motions and structures. I describe them as Field Vector Arrays. 3.Aether has a fine structure within which the smallest electromagnetic wave or highest frequency that can be manifested is directly related to or is a derivative of Planck's Length. I use the name ‘energy cell’ or ‘Aetheron’. 4.The electromagnetic wave is a rotating oscillating system within the aether with up to three generations of concentric waves. Of prime importance is the two generational dual concentric wave. 5.Assuming that aether is an elastic continuum, then whatever occurs in the inner (light) wave, the opposite must occur in the outer (dark) wave. This is a mechanical Universe. 6.Particles are fractal structures condensed from individual energy cells (aetherons) that are built from scalar multiples of the smallest electromagnetic wave at Planck's Frequency. Therefore, particles are condensed aether(ons). Some Basic Rules & Assumptions ©WRHohenberger

Part 1 The Electromagnetic Wave

Static Energy (potential energy – zero velocity)Dynamic Energy (kinetic energy) PendulumLeft Side Height of PendulumForward Velocity – No Static Energy Right Side Height of PendulumReverse Velocity – No Static Energy Water WavePositive Height of water Forward Circular Motion of Water Negative Height of water Backwards Circular Motion of Water Clock Timing SpringTension of spring – No velocityForward Velocity of Rotational Mass (rotary oscillating system)Compression of spring – No velocityReverse Velocity of Rotational Mass (Electrostatic Energy – Charge)(Electromagnetic Energy - Motion) Electromagnetic WaveTension of Aether – No aethereal velocityForward Rotation of Aethereal Mass (rotary oscillating system) Compression of Aether – No aethereal velocityReverse Rotation of Aethereal Mass Various Oscillating Systems ©WRHohenberger

Eq. 7.2 S = 0.5 (E x H) Eq. 7.3S = 0.5 ⋅ [(sinφ ⋅ E) ⋅ (sinφ ⋅ H) + (cosφ ⋅ H) ⋅ (cosφ ⋅ E)] Lockyer’s Summary A vector structure for the photon has been deduced that explains all of the questions raised by the paradox of electric E and magnetic H field strengths showing a paradoxical in- phase (sine/sine) that would not result in a lossless transport of the photon’s stored energy. The traveling wave of electromagnetic energy was shown to be the symbiosis of two conjugate resonances, and the paradoxes were explained logically by using a trigo- nometric identity (sin 2 φ + cos 2 φ =1). Chapter 7 - ENERGY (PHOTON) STRUCTURE Equation 7.2 gives the classic sinusoidal Poynting vector S effective power density value at a single peak value, but does not show the correct nature of the photon, over all cycle time. The correct sinusoidal mathematics that describes the above graphics is given in the trigonometric identity, Equation 7.3; Equation 7.3 gives the same effective value, as Equation 7.2, for the S Poynting vector, but uses the correct photon conjugate vector structure. From Tom Lockyer’s VPP, Pages 65 & 68

In Figure 7.1, the traveling wave appears, to our relativistic distorted view, to be in phase (100 percent power factor) on account of the time coincidence, between the E and H peak values. This (100 percent power factor) is not reality, because the vacuum is reactive, making the Poynting vectors E and H time coincidence inconsistent with the required (sine/cosine) reactive relationship. Also, in violation of nature, the energy seems to disappear, as E and H go to zero twice each cycle in the traveling wave. This energy disappearance is not natural, the photon energy is known to be continuous, not discontinuous as it appears, when viewed from our stationary frame of reference. Refer to Figure 7.1, the traveling wave paradox, of lost energy twice each cycle, as E and H identically pass through zero, is explained by using two conjugate resonances. The photon is a symbiosis of (two) E to H and H to E resonances combined into the axial (S) vector. This symbiosis not only gives the lateral (sine/sine) power factor but also gives the axial (cosine/cosine) loss-less resonances from each conjugate, separately, effectively storing the energy resonantly. Lateral events are not distorted by relativistic effects, so we do see the lateral E, H as they appear in both the stationary view and the relativistic view of the Poynting vector, as (sine/sine). The Lorentz-Fitzgerald contraction makes (S) appear to be zero briefly, from our stationary frame of view. Thus relativity modifies the classical equation for photon power density given in (Equation 7.2) into that shown in (Equation 7.3.) From Tom Lockyer’s VPP, Pages 65 & 66 Lockyer’s Explanation of Sine/Sine Paradox

360° Graph of an Electromagnetic Wave ©WRHohenberger

360° Graph of an Electromagnetic Wave ©WRHohenberger

1 st Generation EM Wave – (The Inner Light Wave) LIGHT WAVE

©WRHohenberger DARK WAVE 2 nd Generation EM Wave – (The Outer Dark Wave)

©WRHohenberger Combined Concentric Light & Dark 2 nd Generation EM Wave

360° Graph of an Electromagnetic Wave ©WRHohenberger

Quark Ball with a Baryon Octet Spin Vectors Method for Developing the DBQ Dodecahedron Quark Ball Dodecahedron Quark Ball Baryon Octet ©WRHohenberger

Baryon Octet & Decuplet Families Meson Family Baryon Decuplet Baryon Octet DBQ Dodecahedron Quark Ball Particle Correlations ©WRHohenberger

Poynting Vector Relationship to Dual Concentric Waves From Tom Lockyer’s VPP, Page 71

From Tom Lockyer’s VPP, Page 70 Vector Development

©WRHohenberger From Tom Lockyer’s VPP Vector Analysis

©WRHohenberger Constructing an Octahedron

VPP Electron Cube Compared to DBQ Dodecahedron Quark Ball ©WRHohenberger

Transposition Graphs ©WRHohenberger

Transposition Graphs ©WRHohenberger

Transposition Graphs ©WRHohenberger

Electromagnetic Photon Stores Energy Resonantly The photon resonant structure conserves and transports energy over vast distances, in the vacuum of space, with no apparent losses. (Rather than tired light, the red shift is thought to be a Doppler effect from an expanding universe.) The energy is alternately stored in the inductance (L = μ o λ ) and the capacitance is (C = ε o λ ) of the vacuum. For any frequency (f) the wavelength is (λ = c / f ) and the corresponding space inductance is (L = μ o λ ) and capacitance (C = ε o λ) and their combinations are analogous to the familiar (LC) electrical resonant circuit. From Tom Lockyer’s VPP, Page 67 Lockyer’s Explanation of Photon Resonant Light Energy

Part 2 The Octahedral Hexagonal Fractal ©WRHohenberger

N S = π / NS = sin π / N r 1 / r 2 r 1 / r r 2 / r ©WRHohenberger Chart of Various Twist-Loop Fractals

o r2r1 r2r1 r R1R1 R2R2 R O 2r 2Θ R First, Second, & Third Generations of an 11 Twist-Loop Fractal ©WRHohenberger

First & Second Generation 7 Twist-Loop Fractal ©WRHohenberger

First and Second Generation 9.5 Twist-Loop Fractal ©WRHohenberger

First, Second, & Third Generation Hexagonal Fractal ©WRHohenberger

The Hexagonal Fractal ©WRHohenberger

The Octahedral Hexagonal Fractal and the Dodecahedron Quark Ball

©WRHohenberger Sierpinksi’s Pyramid & The Octahedral Hexagonal Fractal

Part 3 (VPP) Electron Cube Vs (OHF) Octagonal Hexagonal Fractal ©WRHohenberger

R.707R = R c.5R = R m Volume Cube = R 3 Volume Cylinder (Rotating Cube) =  (.707R) 2 x R =  R 3 /2 = ( /2) R 3 ©WRHohenberger Cube Vs Octahedron

If you are talking about logarithmic variables then and.618 are important numbers, since the natural logarithm of each number is the same except for the sign; However, if you are talking about mass structures then and.707 are important, since /.7071 = 2 the same multiplier for the hexagonal fractal. ©WRHohenberger The Phi Pyramid

Lockyer’s Calculated Results for Electron Charge From Tom Lockyer’s VPP, Pages 72 & 76

R c =.70 7R R R m =.5 R R c =.70 7R Rc=RRc=R R R m =.70 7R Volume (Octahedron) =1/3 x (.707R) 2 x R = 1/3 x R 2 /2 x R = R 3 /6 Vol (Rotating Octahedron) =  /3 x (.5R) 2 x R =  /3 x R 2 /4 x R =  R 3 /12 = ( /2) R 3 /6 Volume (Octahedron) = 1/3 x (R) 2 x √2R = 1/3 x R 2 x √2(R) = (2√2)R 3 /6 = (√2/3)R 3 Vol (Rotating Octahedron) =  /3 x (.707R) 2 x 1.414R =  /3 x R 2 /2 x √2R = (2√2)( /2) R 3 /6 =√2  R 3 /6 = ( /2)( √2/3)R 3 Volume (Octahedron) = 1 /3 x (1.414R) 2 x 2R = 1 /3 x 2R 2 x 2R = (2√2)(2√2)R 3 /6 = 8R 3 /6 (2√2)(√2/3)R 3 = (4/3)R 3 Vol (Rotating Octahedron). =  /3 x (R) 2 x 2R = 2  R 3 /3 = 2√2( /2)( √2/3)R 3 = ( /2) 4/3R 3 ©WRHohenberger Comparing Octahedron Volumes Volume Cube = R 3 Volume Rotating Cube = ( /2) R 3

Surface Area (Octahedron) = 8 x (√2/2)R/2 x √3(√2/2)R/2 = √3R 2 SA (Rotating Octahedron) = 2[  x (1/2) R x (√2/2)R] = (√2/2)  R 2 Surface Area (Octahedron) = 8 x R/2 x √3R/2 = 2√3R 2 SA (Rotating Octahedron) = 2[  x (√2/2)R x R = √2  R 2 Surface Area (Octahedron) = 8 x √2R/2 x √3√2R/2 = 4√3R 2 SA (Rotating Octahedron). = 2[  x R x √2R] = 2√2  R 2 ©WRHohenberger Comparing Octahedron Surface Area Surface Area = 6R 2 Volume Cube = R 3 Surface Area 2 Ends Rotating Cube =  R 2 Volume Rotating Cube = ( /2) R 3 Surface Area Sides Rotating Cube = 2√2  R 2 R c =.70 7R R R m =.5 R R c =.70 7R Rc=RRc=R R R m =.70 7R

Vol. (Rotating Octahedron) = ( /2) R 3 /6 1/6 #.166 1/# 6.0 √1/# SA (Rotating Octahedron) (√2/2)R 2 #.7071 Vol. (Rotating Octahedron) = (√2/3)( /2) R 3 √2/ SA (Rotating Octahedron) = √2  R Vol. (Rotating Octahedron) = (4/3)( /2) R 3 4/ SA (Rotating Octahedron). = 2√2  R ©WRHohenberger Comparing Octahedrons R c =.70 7R R R m =.5 R R c =.70 7R Rc=RRc=R R R m =.7 07R Surface Area = 6R 2 Volume Cube = R 3 Surface Area 2 Ends Rotating Cube =  R 2 Volume Rotating Cube = ( /2) R 3 Surface Area Sides Rotating Cube = 2√2  R 2

R c =.707 R R R m =.5R R c =.707 R Vol. (Rotating Octahedron) = ( √2/3)(/2)R 3 # /# √1/# Surface Area (Rotating Octahedron) = √2R 2 # ©WRHohenberger Deriving the Octahedron Correction Scaling Factor 1/ √[1/(√2/3)R 3 ] = √2R 2 1 = √[3/√2R 3 √2R 2 1 = 3/√2R 3 2R 4 1 = (6/√2)R R = √2/6 = (1/3)(1/ √2) R = (√ 2/6] = = /√ ( √2) = Volume Cube = R 3 Volume Rotating Cube = ( /2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

Vol. (Rotating Octahedron) = (1/6)(/2)R 3 # /# √1/# Surface Area (Rotating Octahedron) = (√2/2)R 2 # ©WRHohenberger Deriving the Octahedron Correction Scaling Factor 1/√[1/(1/6)R 3 ] = (√2/2)R 2 1/√[6/R 3 ] = (√2/2)R 2 1 = √[6/R 3 ] (√2/2)R 2 1 = [6/R 3 ] (1/2)R 4 1 = (6/2)R R = 1/3 R = Volume Cube = R 3 Volume Rotating Cube = (/2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

©WRHohenberger Calculating Octahedron Electron Charge Js = x Vol 2 = [ ]Vol. Vol 2 = x Pe = x E = x D = x 10 5 SA = L2 [ ] SA = x e = x

Volume Sphere = 4/3 ( Radius) 3 = (4/3)(R/2) 3 = (4/3)(1/8)R 3 = (1/3)(/2)R 3 # /# √1/# Surface Area Sphere = 4 ( Radius) 2 = 4(R/2) 2 = R 2 # ©WRHohenberger Deriving the inside Sphere Correction Scaling Factor 1/√[1/(1/3)R 3 ] = R 2 1/√[3/R 3 ] = R 2 1 = √[3/R 3 ] R 2 1 = [3/R 3 ] R 4 1 = 3R R = 1/3 R = R R Volume Cube = R 3 Volume Rotating Cube = (/2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

Volume Sphere = 4/3  R 3 = (4/3)  (√5R/2) 3 = (5√5/3)( /2) R 3 # /# √1/# Surface Area Sphere = 4  R 2 = 4 (√5R/2 ) 2 = 5 R 2 # ©WRHohenberger Deriving the Sphere Correction Scaling Factor 1/√[1/(5√5/3)R 3 ] = 5R 2 1/√[(3/5√5)/R 3 ] = 5R 2 1 = √[( 3/5√5)/ R 3 ] 5R 2 1 = [(3/5√5)/R 3 ] 25R 4 1 = [(3/√5)] 5R = [(15/√5)R R = √5/15 R = √5/15 = (√5/5)(1/3)= √5R = 1/3 R = R.√5R/2 Volume Cube = R 3 Volume Rotating Cube = ( /2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

Volume Rotating VPP Cube (Cylinder) [( √2/2)R] 2 R = ( /2) R 3 # /# √1/# Surface Area 2 Ends of Cylinder = (2)  R 2 = 2 [( √2/2)R] 2 =  R 2 # ©WRHohenberger Deriving the VPP Cube Correction Scaling Factor 1/√[1/R 3 ] = R 2 1 = √[1/R 3 ] R 2 1 = [1/R 3 ] R 4 1 = R R = R c =.707R R R m =.5R Volume Cube = R 3 Volume Rotating Cube = ( /2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

Volume VPP Cylinder = (  /2)R 3 # /# √1/# Surface Area VPP Cylinder = (2√2+1)  R 2 # ©WRHohenberger Deriving the VPP Entire Cylinder Correction Scaling Factor 1/√[1/R 3 ] = ((2√2+1)R 2 1 = √[1/R 3 ] ((2√2+1)R 2 1 = [1/R 3 ] (8+4√2+1)R 4 1 = (9+4√2)R R = 1 /(9+4√2) R = 1/ R = R c =.707R R R m =.5R Volume Cube = R 3 Volume Rotating Cube = ( /2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

Type R Scaling Factor Compton Frequency Rot. VPP Cube Blue Rot. Octahedron Inside Sphere Comparative Data for Various Polyhedrons ©WRHohenberger R R R c =.7 70R R R m =.5R

.5 R R Sphere Volume = (4/3) (Radius) 3 = (4/3) (R/2) 3 = (4/3) (1/8)R 3 = (1/3)(/2)R 3 Surface Area = 4 (Radius) 2 = 4 (1/4)R 2 = R 2 Rotating Octahedron (2 Cones) Volume = /3 (Radius) 2 (Height) = /3 (R/2) 2 R = /3 (1/4)R 2 R = (1/6)(/2)R 3 Surface Area = 2[ (Radius) (Side)] = 2 x (1/2)R x ( √2/2) R = ( √2/2) R 2 ©WRHohenberger VPP Rotating Cube Volume =  (Radius) 2 (Height) =  (√2/2) 2 R 2 R =  (1/2)R 2 R = (/2)R 3 Surface Area (2 Ends) = 2[ (Radius) 2 ] = 2[ x ( √2 /2) 2 R 2 ] = R 2 Comparative Data for Various Polyhedrons

Volume Sphere = 4/3(Radius) 3 = (4/3)(R/2) 3 = (4/3)(1/8)R 3 = [(3)](1/3)(/2)R 3 # /# √1/# Surface Area Sphere = 4 ( Radius) 2 = 4(R/2) 2 = R 2 # ©WRHohenberger Deriving the Triple Sphere Correction Scaling Factor 1/√[1/R 3 ] = R 2 1 = √[1/R 3 ] R 2 1 = [1/R 3 ] R 4 1 = R R = 1 Volume Cube = R 3 Volume Rotating Cube = (/2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

Volume (Rotating Octahedron) = [(3)](1/6)(/2)R 3 # /# √1/# Surface Area (Rotating Octahedron) = (√2/2)R 2 # ©WRHohenberger Deriving the Triple Octahedron Correction Scaling Factor 1/√[1/(1/2)R 3 ] = (√2/2)R 2 1/√[2/R 3 ] = (√2/2)R 2 1 = √[2/R 3 ] (√2/2)R 2 1 = [2/R 3 ] (1/2)R 4 1 = R R = 1 Volume Cube = R 3 Volume Rotating Cube = (/2) R 3 Surface Area = 6R 2 Surface Area 2 Ends Rotating Cube =  R 2 Surface Area Sides Rotating Cube = 2√2  R 2

1 st Generation Electron DBQ Octahedron Mass Structure with Briddell’s Field Structure Lines of Force ©WRHohenberger

Part 4 Other Considerations ©WRHohenberger

The Structure of Aether ©WRHohenberger

Neutrinos, Electrons, Positrons & Virtual Positrons Octahedron Contains an inner Octahedron Fractal at its center ©WRHohenberger Electron/Neutrino Virtual Positron

2R/√6 =.8164R LRad Calculating Electron Charge from new Rotational Axis ©WRHohenberger

Virtual Electron-Positron Lattice

The Structure of Aether ©WRHohenberger

1 – There is a significant congruency between Lockyer’s Vector Particle Physics (VPP) and my own Dodecahedron Quark Ball (DQB), since both are derived from a vector field analysis, although mine is of physical vector field forces within the aether. 2 – VPP generates a plethora of mathematical derivations for the electron, and DQB defines entire families of particles. 3 – Quarks are not particles but instead are field structure arrays within a dual concentric electromagnetic wave. 4 – There may be up to three generations of concentric electromagnetic waves, which form particles when three such waves from three dual concentric waves are superimposed on top of each other on x, y, z Cartesian coordinates. 5 – The quantum limit of the fine structure of the aether forces saturated energy to drop out of suspension, from which twist-loop fractals form particles of matter. 6 – Particles form from the inner electromagnetic (light) wave, and their corresponding field structures form from the outer electromagnetic (dark) wave, which are reflections or mirror images of opposites of each other. 7 – Particle mass structures are captured energy cells, while field structures are lines of force carried by free energy cells. 8 – There is still a lot of work to be done to IRREFUTABLY prove that the electron is an octahedron. ©WRHohenberger Part 5 Summary

Part 6 Protons ©WRHohenberger

Data for Electron Proton Scaling Ratios ©WRHohenberger

Expanded Data for Electon Proton Scaling Ratios ©WRHohenberger

A Periodic Table for Fractals ©WRHohenberger

Planck’s Length Vs Octagonal Hexagonal Fractal - Fractal Scaling Ratio ©WRHohenberger

Proton Mass Calculations ©WRHohenberger

Proton Mass Calculations

The next problem is to determine how the 1,061,540,183 energy cells in Eq. 23 are structured within each of the seven generations. The solution is to take the seventh root of 2  times the proton charge radius divided by the Planck’s Length, with a result of This number was then rounded off to the nearest odd number of energy loops or 857, which was then divided into the number of energy cells in a single generation of the twist- loop structure to determine the number of interlaced loops. 7 √(Proton Charge Circumference/Planck’s Length) = # of Twist-Loops 7 √(2  Proton Charge Radius) = # of Twist-Loops 7 √(2 )(.8768(69)E-15/ E-35 ) = Proton Twist-Loop Calculations ©WRHohenberger

Proton Charge Radius = 8.768E-16 Charge Radius Circumference = = 2 R = E-15 Planck’s Length = E-35 Ratio of Cir./PL = E+20 7 th root Cir. = Loops S = Sin /857 = / S = for 1 / 32 in. Dia. = 8.52 inches 1,061,540,183 (11 Layers) Proton Twist-Loop Calculations ©WRHohenberger

Proton Structure ©WRHohenberger

Proton Loop Calculations ©WRHohenberger