Chapter 19 Acids, Bases, and Salts 19.4 Neutralization Reactions

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Chapter 19 Acids, Bases, and Salts 19.4 Neutralization Reactions 19.1 Acid-Base Theories 19.2 Hydrogen Ions and Acidity 19.3 Strengths of Acids and Bases 19.4 Neutralization Reactions 19.5 Salts in Solution Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 1

What could cause leaves to turn yellow during the growing season? CHEMISTRY & YOU What could cause leaves to turn yellow during the growing season? This condition is called chlorosis because the plant lacks a pigment called chlorophyll. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 2

What products form when an acid and a base react? Acid-Base Reactions Acid-Base Reactions What products form when an acid and a base react? Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 3

HCl(g) + NaOH(aq) → NaCl(aq) + H2O(l) Acid-Base Reactions Suppose you mix a solution of a strong acid, such as HCl, with a solution of a strong base, such as NaOH. The products are sodium chloride and water. HCl(g) + NaOH(aq) → NaCl(aq) + H2O(l) Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 4

In general, acids and bases react to produce a salt and water. Acid-Base Reactions In general, acids and bases react to produce a salt and water. The complete reaction of a strong acid and a strong base produces a neutral solution. Thus, this type of reaction is called a neutralization reaction. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 5

Acid-Base Reactions When you hear the word salt, you may think of the substance that is used to flavor food. Table salt (NaCl) is only one example of a salt. Salts are ionic compounds consisting of an anion from an acid and a cation from a base. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 6

Acid-Base Reactions A reaction between an acid and a base will go to completion when the solutions contain equal numbers of hydrogen ions and hydroxide ions. The balanced equation provides the correct ratio of acid to base. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 7

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) Acid-Base Reactions For hydrochloric acid and sodium hydroxide, the mole ratio is 1:1. HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) 1 mol Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 8

For sulfuric acid and sodium hydroxide, the ratio is 1:2. Acid-Base Reactions For sulfuric acid and sodium hydroxide, the ratio is 1:2. 1 mol 2 mol Two moles of the base are required to neutralize one mole of the acid. H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l) Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 9

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l) Acid-Base Reactions Similarly, hydrochloric acid and calcium hydroxide react in a 2:1 ratio. 2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l) 2 mol 1 mol Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 10

Finding the Moles Needed for Neutralization Sample Problem 19.7 Finding the Moles Needed for Neutralization The term neutralization is used to describe both the reaction and the point at which a neutralization reaction is complete. How many moles of sulfuric acid are required to neutralize 0.50 mol of sodium hydroxide? The equation for the reaction is H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 11

Analyze List the knowns and the unknown. Sample Problem 19.7 Analyze List the knowns and the unknown. 1 To determine the number of moles of acid, you need to know the number of moles of base and the mole ratio of acid to base. KNOWNS mol NaOH = 0.50 mol 1 mol H2SO4/2 mol NaOH (from balanced equation) UNKNOWN mol H2SO4 = ? mol Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 12

Calculate Solve for the unknown. Sample Problem 19.7 Calculate Solve for the unknown. 2 Use the mole ratio of acid to base to determine the number of moles of acid. 0.50 mol NaOH × 1 mol H2SO4 2 mol NaOH = 0.25 mol H2SO4 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 13

Evaluate Does the result make sense? Sample Problem 19.7 Evaluate Does the result make sense? 3 Because the mole ratio of H2SO4 to NaOH is 1:2, the number of moles of H2SO4 should be half the number of the moles of NaOH. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 14

Why are acid-base reactions called neutralization reactions? Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 15

Why are acid-base reactions called neutralization reactions? The complete reaction of an acid with a base creates a solution of a salt in water. This solution has a neutral pH. It is neither acidic nor basic. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 16

At what point in a titration does neutralization occur? Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 17

Titration You can use a neutralization reaction to determine the concentration of an acid or base. The process of adding a measured amount of a solution of known concentration to a solution of unknown concentration is called a titration. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 18

The steps in an acid-base titration are as follows: A measured volume of an acid solution of unknown concentration is added to a flask. Several drops of an indicator are added to the solution while the flask is gently swirled. Measured volumes of a base of known concentrations are mixed into the acid until the indicator just barely changes color. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 19

Titration A flask with a known volume of acids (and an indicator) is placed beneath a buret that is filled with a base of known concentration. The base is slowly added from the buret to the acid. A change in the color of the solution is the signal that neutralization has occurred. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 20

The solution of known concentration is the standard solution. Titration The solution of known concentration is the standard solution. You can use a similar procedure to find the concentration of a base using a standard acid. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 21

Titration Neutralization occurs when the number of moles of hydrogen ions is equal to the number of moles of hydroxide ions. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 22

Titration Neutralization occurs when the number of moles of hydrogen ions is equal to the number of moles of hydroxide ions. The point at which neutralization occurs is called the equivalence point. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 23

Titration The indicator that is chosen for a titration must change color at or near the pH of the equivalence point. The point at which the indicator changes color is the end point of the titration. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 24

Interpret Graphs This graph shows how the pH of a solution changes during the titration of a strong acid (HCl) with a strong base (NaOH). The initial acid solution has a low pH (about 1). As NaOH is added, the pH increases because some of the acid reacts with the base. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 25

Interpret Graphs This graph shows how the pH of a solution changes during the titration of a strong acid (HCl) with a strong base (NaOH). The equivalence point for this reaction occurs at a pH of 7. As the titration nears the equivalence point, the pH rises dramatically because hydrogen ions are being used up. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 26

Interpret Graphs This graph shows how the pH of a solution changes during the titration of a strong acid (HCl) with a strong base (NaOH). Extending the titration beyond the point of neutralization produces a further increase of pH. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 27

Interpret Graphs This graph shows how the pH of a solution changes during the titration of a strong acid (HCl) with a strong base (NaOH). If the titration of HCl and NaOH could be stopped right at the equivalence point, the solution in the beaker would consist of only H2O and NaCl, plus a small amount of indicator. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 28

CHEMISTRY & YOU Iron compounds need to dissociate before the iron can be absorbed by plants. However, these compounds become less soluble as the pH rises. For most plants, a pH between 5.0 and 6.5 will provide enough usable iron. How could you change the pH of soil? Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 29

CHEMISTRY & YOU Iron compounds need to dissociate before the iron can be absorbed by plants. However, these compounds become less soluble as the pH rises. For most plants, a pH between 5.0 and 6.5 will provide enough usable iron. How could you change the pH of soil? You can change the pH of basic soil by adding an acidic compound. To acidic soil you can add a basic compound. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 30

H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l). Sample Problem 19.8 Determining Concentration by Titration A 25-mL solution of H2SO4 is neutralized by 18 mL of 1.0M NaOH. What is the concentration of the H2SO4 solution? The equation for the reaction is H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l). Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 31

Analyze List the knowns and the unknown. Sample Problem 19.8 Analyze List the knowns and the unknown. 1 The conversion steps are as follows: L NaOH → mol NaOH → mol H2SO4 → M H2SO4. KNOWNS [NaOH] = 1.0M VNaOH = 18 mL = 0.018 L VH2SO4 = 18 mL = 0.018 L UNKNOWN [H2SO4] = ?M Convert volume to liters because molarity is in moles per liter. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 32

Calculate Solve for the unknown. Sample Problem 19.8 Calculate Solve for the unknown. 2 Use the molarity to convert the volume of base to moles of base. 0.018 L NaOH × 1.0 mol NaOH 1 L NaOH = 0.018 mol NaOH Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 33

Calculate Solve for the unknown. Sample Problem 19.8 Calculate Solve for the unknown. 2 Use the mole ratio to find the moles of acid. 0.018 mol NaOH × 1.0 mol H2SO4 2 mol NaOH = 0.0090 mol H2SO4 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 34

Calculate Solve for the unknown. Sample Problem 19.8 Calculate Solve for the unknown. 2 Calculate the molarity by dividing moles of acid by liters of solution. molarity = mol of solute L of solution 0.0090 mol 0.025 L = = 0.36M H2SO4 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 35

Evaluate Does the result make sense? Sample Problem 19.8 Evaluate Does the result make sense? 3 If the acid had the same molarity as the base (1.0M), 50 mL of base would neutralize 25 mL of acid. Because the volume of the base is much less than 50 mL, the molarity of the acid must be much less than 1.0M. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 36

In strong acids, are all ionizable hydrogens completely ionized In strong acids, are all ionizable hydrogens completely ionized? In weak acids? Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 37

In strong acids, are all ionizable hydrogens completely ionized In strong acids, are all ionizable hydrogens completely ionized? In weak acids? In strong acids, all ionizable hydrogens are completely ionized. In weak acids, all ionizable hydrogens are partially ionized. Some hydrogens in these acids (those with larger Ka values) have a greater degree of ionization. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 38

In general, acids and bases react to produce a salt and water. Key Concepts In general, acids and bases react to produce a salt and water. Neutralization occurs when the number of moles of hydrogen ions is equal to the number of moles of hydroxide ions. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 39

Glossary Terms neutralization reaction: a reaction in which an acid and a base react in an aqueous solution to produce a salt and water titration: process used to determine the concentration of a solution (often an acid or base) in which a solution of known concentration (the standard) is added to a measured amount of the solution of unknown concentration until an indicator signals the end point Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 40

Glossary Terms standard solution: a solution of known concentration used in carrying out a titration equivalence point: the point in a titration where the number of moles of hydrogen ions equals the number of moles of hydroxide ions end point: the point in a titration at which the indicator changes color Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 41

BIG IDEA Reactions Chemists use acid-base reactions to determine the concentration of an acid or a base in solution. Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 42

END OF 19.4 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 43