Lesson 3 The Rig - Drilling Equipment

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Presentation transcript:

Lesson 3 The Rig - Drilling Equipment PETE 411 Well Drilling Lesson 3 The Rig - Drilling Equipment

Contents Rig Pumps Solids Control Equipment Air Drilling The Rotary System The Swivel The Well Control System The Well Monitoring System Offshore Drilling

Assignments: READ: ADE Ch. 1, to p.30 HW #1: ADE 1.1, 1.2, 1.3 Due Monday, Sept. 9, 2002 at the beginning of class NOTE: Answers in book are not always correct...

Schematic of Rig Circulating System for liquid drilling fluid

Example 1.3 Compute the pump factor in units of barrels per stroke for a double-acting duplex pump having: 6.5-inch liners (dL) 2.5 inch rods (dr) 18-inch strokes (LS) and a volumetric efficiency of 90%. (EV)

Solution: The pump factor for a duplex pump can be determined using Equation 1.10

Thus: Pump Factor = 0.2052 bbl/stroke Recall: There are 231 in.3 in an U. S. gallon and 42 U.S. gallons in a U.S. barrel. Thus converting to the desired field units yields: 1991 in.3/stroke * gal/231 in.3 * bbl/42 gal. = 0.2052 bbl/stroke. Thus: Pump Factor = 0.2052 bbl/stroke

Pump Factor = 3 * p/4 dL2 LS EV/(231 * 42)

Example: Pump Factor for Triplex Pump

Example: Pump Rate = Pump Factor * Strokes/min = 0.09442 = 7.554 bbl/min = 317.3 gal/min Pump Rate = 317 gal/min

Hydrocyclone desander desilter * No moving parts * Low cost * Pressure drop * Diameter

Decanting Centrifuge Use?

Use?

Fig. 1.33 Schematic of Rotary System

Fig. 1.34 Cutaway View of Swivel * Seals * Bearings ROTATING

Cutaway View and Dimensions for Example Tool Joint PIN BOX TJ Shoulder Fig. 1.38 Cutaway View and Dimensions for Example Tool Joint

Fig. 1.39 Stabilizer * Keeps pipe in center of hole * Aids in drilling straight hole * Prolongs bit life

Kick Detection During Drilling Operations Fig. 1.41 Kick Detection During Drilling Operations 3 GAIN IN PIT VOLUME EQUAL TO KICK VOLUME KICK 2 1

Fig. 1.46 Remote Control Panel for operating Blowout Preventers CHOKE What to do if KICK occurs?

Fig. 1.44 Annular Blowout Preventer DP TJ DC OH Press Fig. 1.44 Annular Blowout Preventer

Ram Blowout Preventer

Ram Blowout Preventer - cont’d SHEAR / BLIND RAM ASSEMBLY Ram Blowout Preventer - cont’d

Fig. 1.48 Rotating Blowout Preventer

Fig. 1.51 High-Pressure Circulating System for Well Control Operations Kick Keep BHP const.

Fig. 1.56 Subsurface Well Monitoring System MWD

Fig. 1.57 Spread Mooring Systems OFFSHORE DRILLING Fig. 1.57 Spread Mooring Systems

Fig. 1.58 Schematic of Equipment for Marine Drilling

Fig. 1.59 Operation of a Heave Compensator

Fig. 1.60 Subsea BOP Stack

Fig. 1.63 Subsea Equipment Installation Procedure

Typical Casing Strings Water Level Depth Seafloor Below ML Conductor pile 36” 30” 200’ Conductor Casing 26” 20” 1000’ Surface Casing 17 1/2” 13 3/8” 4000’ Hole Csg. Depth

Some Typical Casing Strings Depth Below ML Conductor pile 36” 30” 200’ Conductor Casing 26” 20” 1000’ Surface Casing 17 1/2” 13 3/8” 4000’ Hole Csg. Depth

Capacity = Area * Length

What is the capacity of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe? Capacity = Area * Length Area = p/4 d2 = p/4 * 4.2762 = 14.36 in2 Length = 10,000 ft = 120,000 in Capacity = 14.36 *120,000 in3 /(231*42 in3 /bbl) Capacity = 177.6 bbls

What is the displacement of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe? Capacity = Area * Length Area = p /4 (od2 - id2 ) = p /4 * (52 - 4.2762) = 5.275 in2 Length = 10,000 ft = 120,000 in Displ. = 5.276 * 120,000 in3 /(231 * 42 in3 /bbl) Displacement = ? Bbls Displ. = 65.26 bbls