Shear Stress Shear stress is defined a the component of force that acts parallel to a surface area Shear stress is defined a the component of force that.

Slides:



Advertisements
Similar presentations
Sample Problem 4.2 SOLUTION:
Advertisements

PH0101 UNIT 1 LECTURE 1 Elasticity and Plasticity Stress and Strain
8.0 SECOND MOMENT OR MOMENT OF INERTIA OF AN AREA
Torsion of a Circular Cylinder A Course Project By George Kodikulam Mukesh Nagapuri Bharath Kumar Vudhamari Pradeep Kumar Bitla SriLakshmi Ganoothula Continuum.
Chapter 3 – Stress and Deformation Analysis (ref MCHT 213!!)
Sample Problem 4.2 SOLUTION:
4 Pure Bending.
Bending Moments A bending moment exists in a structural element when an external force is applied to the element so that the element bends (or wishes to.
GUJARAT TECHNOLOGICAL UNIVERSITY B.E Semester: 3 Civil Engineering Structural Analysis-1 Faculty: Chandra Bhakuni
1 Classes #3 & #4 Civil Engineering Materials – CIVE 2110 Torsion Fall 2010 Dr. Gupta Dr. Pickett.
2E4: SOLIDS & STRUCTURES Lecture 13 Dr. Bidisha Ghosh Notes: lids & Structures.
CTC / MTC 222 Strength of Materials Chapter 1 Basic Concepts.
Torsion: Shear Stress & Twist ( )
Chapter 5 – Torsion Figure: 05-00CO.
Torsion Torsional Deformation of a circular shaft,
3 Torsion.
Strength of Material-5 Torsion Dr. Attaullah Shah.
Torsional Shaft Function: transmit torques from one plane to the other. Design of torsional shafts: stress and deformation T T T.
STRUCTURAL MECHANICS: CE203
Strength of Materials I EGCE201 กำลังวัสดุ 1
Torsion  Introduction -- Analyzing the stresses and strains in machine parts which are subjected to torque T Circular -- Cross-section Non-circular.
Chapter 5 Torsion.
BFC (Mechanics of Materials) Chapter 6: Torsion
Strengths Torsion of Circular Shafts Chapter 12. Introduction A member subjected to twisting moments (torques) is called a shaft Only solid and hollow.
CHAPTER 5 TORSION.
Chapter 3 Torsion Torsion Engr. Othman A. Tayeh. DEFORMATIONS IN A CIRCULAR SHAFT Φ the angle of twist.
SAFE 605: Application of Safety Engineering Principles Strength of Materials.
CTC / MTC 222 Strength of Materials Chapter 5 Torsional Shear Stress and Torsional Deformation.
Copyright © 2011 Pearson Education South Asia Pte Ltd
Torsion T T Torsional Deformation of a Circular Shaft
Mechanical Properties Session 07-14
CTC / MTC 222 Strength of Materials
Beams: Pure Bending ( ) MAE 314 – Solid Mechanics Yun Jing Beams: Pure Bending.
3 Torsion.
Sample Problem 4.2 SOLUTION:
Beams Beams: Comparison with trusses, plates t
BSE 2294 Animal Structures and Environment
NCSX Modular Coil Composite Conductor Torsion Measurement of the Conductor Shear Modulus at Both Room and Liquid Nitrogen Temperatures 15 Dec 2004.
Mechanics of Materials – MAE 243 (Section 002) Spring 2008
Rotation Rotational Variables Angular Vectors Linear and Angular Variables Rotational Kinetic Energy Rotational Inertia Parallel Axis Theorem Newton’s.
Mechanics of Materials – MAE 243 (Section 002) Spring 2008
Strengths Chapter 10 Strains. 1-1 Intro Structural materials deform under the action of forces Three kinds of deformation Increase in length called an.
9 Torsion.
Load and Stress Analysis
Chapter 12 Static Equilibrium and Elasticity. Static Equilibrium Equilibrium implies that the object moves with both constant velocity and constant angular.
Mechanics of Materials – MAE 243 (Section 002) Spring 2008 Dr. Konstantinos A. Sierros.
CTC / MTC 222 Strength of Materials Chapter 1 Basic Concepts.
UNIT-05. Torsion And Buckling of columns
Static Equilibrium and Elasticity
PROBLEMS ON TORSION.
3 Torsion.
Forging new generations of engineers
Main Steps of Beam Bending Analysis Step 1 – Find Reactions at External Supports –Free Body Diagram (FBD) of Entire Beam –Equations of Force and Moment.
8.0 SECOND MOMENT OR MOMENT OF INERTIA OF AN AREA
Stress and Strain ( , 3.14) MAE 316 – Strength of Mechanical Components NC State University Department of Mechanical & Aerospace Engineering Stress.
MECHANICS OF MATERIALS Fourth Edition Ferdinand P. Beer E. Russell Johnston, Jr. John T. DeWolf Lecture Notes: J. Walt Oler Texas Tech University CHAPTER.
1 - 1 Dr.T.VENKATAMUNI, M.Tech, Ph.D PROFESSOR & HOD DEPARTMENT OF MECHANICAL ENGINEERING JEPPIAAR INSTITUTE OF TECHNOLOGY.
BME 315 – Biomechanics Chapter 4. Mechanical Properties of the Body Professor: Darryl Thelen University of Wisconsin-Madison Fall 2009.
STRENGTH OF MATERIALS UNIT – III Torsion.
Pure Bending.
Mechanical Properties of Materials
3 Torsion.
3 Torsion.
Structure I Course Code: ARCH 208 Dr. Aeid A. Abdulrazeg
Theory of Simple Bending
Units of N m.
Strength of Material Torsion Dr. Attaullah Shah.
TORSION CO 2 : ABILITY TO ANALYZE TORQUE-LOADED MEMBER EVALUATE THE VALUES AND DISTRIBUTION OF BENDING AND SHEAR STRESSES IN BEAM SECTION By: ROSHAZITA.
Mechanics of Materials ENGR Lecture 22 Torsion 1
Simple Stresses & Strain
Presentation transcript:

Shear Stress Shear stress is defined a the component of force that acts parallel to a surface area Shear stress is defined a the component of force that acts parallel to a surface area Shear stress is a stress state where the shape of a material tends to change (usually by "sliding" forces – torque by transversely-acting forces) without particular volume change. Shear stress is a stress state where the shape of a material tends to change (usually by "sliding" forces – torque by transversely-acting forces) without particular volume change. The shape change is evaluated by measuring the change of the angle's magnitude (shear strain). The shape change is evaluated by measuring the change of the angle's magnitude (shear strain).

Examples of Shear Stress Structural members in pure shear stress are the torsion bars and the driveshafts in automobiles. Structural members in pure shear stress are the torsion bars and the driveshafts in automobiles. Riveted and bolted may also be mainly subjected to shear stress. Riveted and bolted may also be mainly subjected to shear stress.

Shear Stress Formula

Shear Strain Shear strain is the displacement that occurs in a body that is parallel to the forces applied. Shear strain is the displacement that occurs in a body that is parallel to the forces applied.

Shear Strain Formula Shear strain is the displacement that occurs in a body that is parallel to the forces applied. Shear strain is the displacement that occurs in a body that is parallel to the forces applied. Shear Strain = DL / L Shear Strain = DL / L Where: Where: –DL = Horizontal Displacement from Vertical –L = Original Length

Modulus of Rigidity (G) Also referred to as the Shear Modulus Also referred to as the Shear Modulus Ratio of shear stress to shear strain Ratio of shear stress to shear strain G = Shear Stress Shear Strain

Bearing Stress Bearing stress is the stress caused by one part acting directly on another. Bearing stress is the stress caused by one part acting directly on another. Bearing stress is a compressive stress and is equal to the bearing force divided by the bearing area. Bearing stress is a compressive stress and is equal to the bearing force divided by the bearing area.

Bearing Stress Bearing stress is a compressive stress and is equal to the bearing force divided by the bearing area. Bearing stress is a compressive stress and is equal to the bearing force divided by the bearing area.  (bearing) = Compressive Forces/Area  (bearing) = Compressive Forces/Area

Torque Torque is a measure of how much a force acting on an object causes that object to rotate. Torque is a measure of how much a force acting on an object causes that object to rotate. The object rotates about a pivot point. The object rotates about a pivot point. A force is applied at a distance from that pivot point. A force is applied at a distance from that pivot point. The distance from the pivot point to the point where the force acts is the moment arm. The distance from the pivot point to the point where the force acts is the moment arm.

Torsion Torsion occurs when an external torque is applied and an internal torque, shear stress, and deformation (twist) develops in response to the externally applied torque. Torsion occurs when an external torque is applied and an internal torque, shear stress, and deformation (twist) develops in response to the externally applied torque. There is a corresponding deformation (angle of twist) which results from the applied torque and the resisting internal torque causing the shaft to twist. There is a corresponding deformation (angle of twist) which results from the applied torque and the resisting internal torque causing the shaft to twist.

Torsion and Shearing Stress There is also an internal shear stress which develops inside the shaft. There is also an internal shear stress which develops inside the shaft. This shearing stress on the cross sectional area varies from zero at the center of the shaft linearly to a maximum at the outer edge. This shearing stress on the cross sectional area varies from zero at the center of the shaft linearly to a maximum at the outer edge. This may be thought of as being due to the adjacent cross sectional areas of the shaft trying to twist passed each other. This may be thought of as being due to the adjacent cross sectional areas of the shaft trying to twist passed each other.

Torsion The angle of twist can be found by using: The angle of twist can be found by using: Where: Where: –Theta is the angle of twist in radians –T is the torque ( N * m or ft * lbs ). –L is the length of the object the torque is being applied to or over. –G is the shear modulus or more commonly the modulus of rigidity –J is the polar moment of inertia

Torsion Example A steel, cylindrical bar has a 20,000 in-lb torque applied to it. A steel, cylindrical bar has a 20,000 in-lb torque applied to it. The radius of the bar is.5 inches and it is 5 feet in length The radius of the bar is.5 inches and it is 5 feet in length The steel used in this example has a shear modulus of 11 X 10 6 psi The steel used in this example has a shear modulus of 11 X 10 6 psi The polar moment of inertia for a circular object is calculated using: The polar moment of inertia for a circular object is calculated using: –J = (  r 4 )/ 2 =.10 in 4 The torsion can be calculated using: The torsion can be calculated using: –  (20,000 in-lb)(60 in)/(.10 in 4 )(11 X 10 6 psi) = 1.09 radians –Angle in degrees = Angle in Radians * 180 / Pi –Converting radians into degrees, the steel bar is expected to twist 62.5 degrees