EEE340Lecture Electric flux density and dielectric constant Where the electric flux density (displacement) Absolute permittivity Relative permittivity (dielectric constant) Electric susceptibility

EEE340Lecture 132 Example Dielectric shell. Find and. Solution Make Gaussian surface r<r i r i <r<r o r>r o The electric flux Regardless of r  is in i or ii or iii However the E-field expressions are r r o r i <r<r o

EEE340Lecture : Dielectric strength Breakdown Transformer oil with air bubbles. Example 3-13 Two spherical conductors. Solution. a). From equal potential condition, or b2 b1

EEE340Lecture 134 That b) The electric field at the sphere surfaces:

EEE340Lecture Boundary conditions for electrostatic fields The tangential component of the E-field is continuous across the boundary E 1t =E 2t Show. Apply In the integral form Where L is a narrow frame abcd. So that and

EEE340Lecture 136 The normal component of field is continuous across the interface, provided no surface charge exists. Show. Make a flat disk Gaussian surface Hence Special cases :

EEE340Lecture 137 Example. Given a charge-free flat dielectric interface separating  1 =5  o and  2 =2  o. If find Solution Using boundary conditions: Hence and z x E1E1 E2E2