D2011 Project CEA-IRSN Results Alain MILLARD, Frédéric DELERUYELLE Gyeongju, Korea, April 20-23, 2009 Task A - STEPS 0/1.

Slides:



Advertisements
Similar presentations
Institut für Meteorologie und Klimatologie Universität Hannover
Advertisements

Entropy changes of pure substances: retrieving data from property tables. Tds relations relate properties of any pure substance exactly to entropy change.
How to read the Humidity chart & do the operating diagram for Cooling tower of Air-Water at 1 atm. Assume you have air of a definite air- water mixture.
Entry Task: Dec 7th Block 1
Theoretical solutions for NATM excavation in soft rock with non-hydrostatic in-situ stresses Nagasaki University Z. Guan Y. Jiang Y.Tanabasi 1. Philosophy.
ChemE 260 Phase Equilibrium and Thermodynamic Data Tables April 1, 2005 Dr. William Baratuci Senior Lecturer Chemical Engineering Department University.
Freeze drying Subtitle © 2011 COMSOL. All rights reserved.
13 Pot-in-Pot refridgerator Natália Ružičková Task The ‘pot-in-pot refrigerator’ is a device that keeps food cool using the principle of evaporative.
Conductivity Testing of Unsaturated Soils A Presentation to the Case Western Reserve University May 6, 2004 By Andrew G. Heydinger Department of Civil.
Ta-Te Lin, Yi-Chung Chang
Subsurface Air Flow Air is a fluid (but not a liquid) that behaves similarly to water We see pressure changes in the subsurface due to barometric pressure.
Lec 7: Property tables, ideal and real gases
Lecture 3411/30/05. Vapor pressure vs. boiling point?
Introduction to the Ventilation Experiment (VE) and Task A B. Garitte and A. Gens (CIMNE – UPC) Dept. of Geotechnical Engineering and Geosciences TECHNICAL.
Atmospheric Analysis Lecture 3.
Summary of results to date B. Garitte and A. Gens 2nd DECOVALEX 2011 workshop, 20 th of October 2008, Wakkanai, Japan Dept. of Geotechnical Engineering.
Introduction to the Task A Task Force Meeting B. Garitte and A. Gens 2nd DECOVALEX 2011 workshop, 20 th of October 2008, Wakkanai, Japan Dept. of Geotechnical.
D2011 Project CEA-IRSN Results Alain MILLARD, Frédéric DELERUYELLE Wakkanai, Japan, October 20-23, 2008 Task A - STEPS 0/1.
Humidity First let us consider five humidity variables
Thermal analysis There is a resemblance between the thermal problem and the stress analysis. The same element types, even the same FE mesh, can be used.
University of South Carolina FCR Laboratory Dept. of Chemical Engineering By W. K. Lee, S. Shimpalee, J. Glandt and J. W. Van Zee Fuel Cell Research Laboratory.
Status report on Step1 of Task A, DECOVALEX-2011 modeling for Ventilation Experiment –modeling for Ventilation Experiment By Xiaoyan Liu, Chengyuan Zhang.
Current Status of CAS Team on Task A Step 0: Model Inception two-phase flowmodeling for the laboratory drying test – two-phase flow modeling for the laboratory.
NOTES: 14.4 – Dalton’s Law & Graham’s Law
Divide yourselves into groups of three (3). Write your names and your complete solution into your answer sheet, and box / encircle your final answer.
Geankoplis Singh&Heldman
Introduction to Convection: Mass Transfer Chapter Six and Appendix E Sections 6.1 to 6.8 and E.4.
A Comparison of Numerical Methods and Analytical Methods in Determination of Tunnel Walls Displacement Behdeen Oraee-Mirzamani Imperial College London,
Partial Pressure Problems. Vocabulary Used in Partial Pressure Problems 1. Partial Pressure- The pressure of each gas in a mixture. 2. Dalton’s Law- The.
Barometer Vacuum Height of column in. (76 cm) Air pressure Mercury.
The Gas Laws =13WUqWd_Yk8 =13WUqWd_Yk8.
Vapor pressure and liquids Vapor : A gas that exists below its critical point Gas : gas that exists above its critical point ِNote : A gas can not condense.
Atmospheric Pressure Chapter 6.
Evaporation Slides prepared by Daene C. McKinney and Venkatesh Merwade
Weather Instruments. Thermometer What does it do? What does it do? It measures the air temperature It measures the air temperature.
Evaporation What is evaporation? How is evaporation measured? How is evaporation estimated? Reading: Applied Hydrology Sections 3.5 and 3.6 With assistance.
Agenda 1. Examples from Property Tables 2. Ideal Gas Examples 3. Property Throwdown 4. Closed System Energy Balance Theory 5. Closed System Energy Balance.
Saturation = filled to capacity
Atmospheric Properties II Martin Visbeck DEES, Lamont-Doherty Earth Observatory
Lecture 8 Evapotranspiration (1) Evaporation Processes General Comments Physical Characteristics Free Water Surface (the simplest case) Approaches to Evaporation.
Just add them up! 200 kPa500 kPa400 kPa1100 kPa ++=
HUMIDITY  Humidity is the amount of water vapor in the air. Water vapor is the gas phase of water and is invisible. Humidity indicates the likelihood.
Partial Pressure Problems. Vocabulary Used in Partial Pressure Problems 1. Partial Pressure- The pressure of each gas in a mixture. 2. Dalton’s Law- The.
Two-Phase Gas-Liquid Systems (Saturation, Condensation, Vaporization) Saturation  When any noncondensable gas (or a gaseous mixture) comes in contact.
Ideal Gas Law PV = nRT P= pressure (atm) V= volume (L)
Problems Dr. Kagan ERYURUK.
1. A commercial polyvinyl alcohol (PVA) pervaporation membrane will be utilised to partially dehydrate an ethanol(1)/water(2) mixture containing 75.8%
Unit 9 Acc Chem Review Note: You must memorize STP and the gas laws!!
Evaporation What is evaporation? How is evaporation measured?
ME 475/675 Introduction to Combustion Lecture 12 Droplet evaporation, Example 3.2.
Evaporation What is evaporation? How is evaporation measured? How is evaporation estimated? Reading for today: Applied Hydrology Sections 3.5 and 3.6 Reading.
Page 79 and 81 of INB. Essential question: Why must scientist’s account for water vapor when they collect gases by water displacement?
Moisture  There are several methods of expressing the moisture content (water in vapor form) of a volume of air.  Vapor Pressure: The partial pressure.
1 Equations of State The relationship among the state variables, temperature, pressure, and specific volume is called the equation of state. We now consider.
MAE 5310: COMBUSTION FUNDAMENTALS
Date of download: 10/10/2017 Copyright © ASME. All rights reserved.
3rd DECOVALEX 2011 workshop, 21th of April 2009, , Gyeongju, Korea
Lecture 8 Evapotranspiration (1)
«Development and analysis of heat exchanger combined with fire tank with a view of its application as part of geothermal heat pump»
PhET Partial Pressures Simulation Unit 9: Stoichiometry PhET Partial Pressures Simulation.
Working with Phases and Properties of Substances
First Law of Thermodynamics
Phase Diagrams: Solid, Liquid & Gas Roadmaps
QUIZ 2 The quality of steam at 7 MPa and enthalpy of 2600 kJ/kg: 0.526
First Law of Thermodynamics
Phase Transition Example
Study these weather words!
Boiling is a liquid-to-vapor phase change process just like evaporation, but there are significant differences between the two. Evaporation occurs at.
Example 5.10 Amplitudes associated with a plane wave in 20˚C (r = 998 kg/m3 and c = 1481 m/s) Frequency (kHz) I (W/m2) P (kPa) Prms (kParms) 0.
Collecting a gas over water
Presentation transcript:

D2011 Project CEA-IRSN Results Alain MILLARD, Frédéric DELERUYELLE Gyeongju, Korea, April 20-23, 2009 Task A - STEPS 0/1

Contents Step 0 –New theoretical model –Drying test results Step 1 –Hypothesis –Preliminary results Conclusion

Step 0 Model used previously : –P g = P atm –No vapor diffusion (Richard’s approximation) –Intrinsic permeability : –Relative permeability : –Adopted values : K 0 = m 2 λ’ = 0.68

Drying test

Results K 0 = m 2, H r = 33% Water content profilesChange in mass with time

New theoretical model Total water mass balance : Liquid mass flux : Constant gaz pressure hypothesis : p g = p atm Vapor mass flux : Vapor pressure : =>

New theoretical model Vapor diffusivity in air : New adopted values : K 0 = m 2 λ’ = 0.4

New results K 0 = m 2, H r = 33% Water content profilesChange in mass with time

Step 1 – VE Experiment Phases 0,1 Phase 1

Step 1 – Hypothesis 2D plane strain model Isotropic properties Isotropic in-situ stresses Constant temperature T=15°C Same models and properties as for Step 0 Influence of boundary conditions in tunnel Phases 0 and 1 : calculation over 2120 days

Mesh 130 m

Initial and boundary conditions σ = -3.2MPa, P l = 1.21MPa P l = Hr (t) or exchange U. n = 0 Φ l. n = 0 σ (0) and P l (0) affine in z S l (0) = 1 φ (0) = 0.16

Hr(t) in the tunnel prescribed Mean in SA3 Mean in tunnel

Exchange bc in the tunnel ► Inside the tunnel : ► Identification of α on the mean evaporated water mass from the water pans : ● From 08/09/2003 to 28/01/2004 : Δm = g ● Use of mean h r ext (t) in SA3 => α = Kg/m 2 /s

Base case No vapor diffusion K 0 = m 2 λ’ = 0.68 Prescribed mean h r in the tunnel E = 6000 MPa

Extracted water mass kg

Relative humidity – SB1 0,67 m 0,90 m 1,00 m 1,15 m 1.40 m

Relative humidity – SB2

Relative displacement – SD1 mm

Relative displacement – SD2 mm

Water pressure kPa

Initial water pressure 2 MPa -12 MPa 0.

Variant 1 Vapor diffusion accounted for K 0 = m 2 λ’ = 0.4 Prescribed mean H r in the tunnel E = 6000 MPa

Extracted water mass

Relative humidity – SB1

Relative humidity – SB2

Relative displacement – SD1

Relative displacement – SD2

Water pressure

Variant 2 Vapor diffusion accounted for K 0 = m 2 λ’ = 0.4 Exchange boundary condition in the tunnel E = 1000 MPa

Extracted water mass

Relative humidity – SB1

Relative humidity – SB2

Relative displacement – SD1

Relative displacement – SD2

Water pressure

Conclusions Step 0 : –Accounting for vapor diffusion in a simplified way –Results similar to other teams Step 1 : –Preliminary results –Best results using vapor diffusion and exchange condition –Over-estimated extracted water mass –Reduced rock stiffness

Thank you for your attention