Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨=𝒃𝒉 𝑨=𝒃𝒉 𝟖𝟎=𝟐𝟎𝒉 =(𝟏𝟎)(𝟖) Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 Find the value of h for each parallelogram, or the Area of the following figures. 𝑨=𝒃𝒉 𝑨=𝒃𝒉 𝟖𝟎=𝟐𝟎𝒉 =(𝟏𝟎)(𝟖) 𝟒=𝒉 =𝟖𝟎 𝒖𝒏 𝒊𝒕𝒔 𝟐

Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒃𝒉 = 𝟏 𝟐 (𝟏𝟐)(𝟏𝟎) Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 Find the value of h for each parallelogram, or the Area of the following figures. 𝑨= 𝟏 𝟐 𝒃𝒉 = 𝟏 𝟐 (𝟏𝟐)(𝟏𝟎) =𝟔𝟎 𝒄𝒎 𝟐

Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒃𝒉 = 𝟏 𝟐 (𝟖)(𝟓) Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 Find the value of h for each parallelogram, or the Area of the following figures. 𝑨= 𝟏 𝟐 𝒃𝒉 = 𝟏 𝟐 (𝟖)(𝟓) =𝟐𝟎 𝒎 𝟐 𝑨=𝒃𝒉 =(𝟖)(𝟓) 𝑨=𝟐𝟎+𝟒𝟎=𝟔𝟎 𝒎 𝟐 =𝟒𝟎 𝒎 𝟐

Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒅 𝟏 𝒅 𝟐 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 Find the value of h for each parallelogram, or the Area of the following figures. 𝑨= 𝟏 𝟐 𝒅 𝟏 𝒅 𝟐 𝑨= 𝟏 𝟐 (𝟖+𝟖)(𝟖+𝟏𝟒) 𝑨= 𝟏 𝟐 (𝟏𝟔)(𝟐𝟐) 𝑨=𝟏𝟕𝟔 𝒊𝒏 𝟐

Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒅 𝟏 𝒅 𝟐 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 Find the value of h for each parallelogram, or the Area of the following figures. 𝑨= 𝟏 𝟐 𝒅 𝟏 𝒅 𝟐 𝑨= 𝟏 𝟐 (𝟑+𝟑)(𝟑+𝟑) 𝑨= 𝟏 𝟐 (𝟔)(𝟔) 𝑨=𝟏𝟖 𝒎 𝟐

Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒉( 𝒃 𝟏 + 𝒃 𝟐 ) Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 Find the value of h for each parallelogram, or the Area of the following figures. =𝟐𝒏 𝟔 𝟑 𝒏 𝟑 𝒏 𝟔 𝑨= 𝟏 𝟐 𝒉( 𝒃 𝟏 + 𝒃 𝟐 ) 𝑨= 𝟏 𝟐 (𝟔 𝟑 )(𝟑𝟎+𝟑𝟔) 𝑨=𝟏𝟗𝟖 𝟑 𝒊𝒏 𝟐

Mrs. Rivas a = p = n = s = Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒂𝒑 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 𝟖 𝟑 𝟑 a = p = n = s = 𝟏𝟔 𝟑 =𝟒𝟖 120º 120º 𝟑 120º 60º s 𝑨= 𝟏 𝟐 𝒂𝒑 𝟏𝟔 30º 𝟖 =𝒔 𝟑 𝟖 𝑨= 𝟏 𝟐 𝟖 𝟑 𝟑 𝟒𝟖 360º = 120º 3 𝑨=𝟏𝟏𝟎.𝟗 𝒄𝒎 𝟐

Mrs. Rivas Worksheet Practice 10-3 and 10-4 360º = 36º 10 m1 = 36º Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 360º = 36º 10 m1 = 36º m2 = 36  2 = 18º m3 = 180 - 90 – 18 = 72º

a = p = n = s = Mrs. Rivas Worksheet Practice 10-3 and 10-4 = 2.5980 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 a = p = n = s = 1.5¯ 3 = 2.5980 60º 60º 60º 60º 60º 18 30º s3 6 60º 1.5 s 3 360º = 60º 6

Mrs. Rivas a = p = n = s = Worksheet Practice 10-3 and 10-4 𝟒 s2 = 12 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 90º 90º 90º s2 = 12 90º s 45º 45º s =6¯ 2 a = p = n = s = 𝟔 𝟐 𝟒𝟖 𝟐 𝟒 𝟏𝟐 𝟐

a = p = n = s = Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒂𝒑 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒂𝒑 a = p = n = s = 𝟐 𝟑 𝑨= 𝟏 𝟐 𝟐 𝟑 (𝟐𝟒) 24 𝟐 𝟐 6 𝑨=𝟐𝟒 𝟑 𝒄𝒎 𝟐 4

a = p = n = s = Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒂𝒑 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 𝑨= 𝟏 𝟐 𝒂𝒑 a = p = n = s = 𝟔 𝟑𝟔 𝟑 𝑨= 𝟏 𝟐 (𝟔)(𝟑𝟔 𝟑 ) 𝟔 𝟑 𝟔 𝟑 𝟑 360º 𝟏𝟐 𝟑 𝑨=𝟏𝟎𝟖 𝟑 𝒎 𝟐 = 120º 3

Mrs. Rivas Worksheet Practice 10-3 and 10-4 a 9 3 Perimeter = = b 12 4 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 a 9 3 Perimeter = = b 12 4 a² Area = 3² 9 b² = 4² 16

Mrs. Rivas Worksheet Practice 10-3 and 10-4 a 4 1 Perimeter = = b 8 2 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 a 4 1 Perimeter = = b 8 2 a² Area = 1² 1 b² = 2² 4

Mrs. Rivas Worksheet Practice 10-3 and 10-4 a 12 12 Perimeter = = b 5 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 a 12 12 Perimeter = = b 5 5 a² Area = 12² 144 b² = 5² 25

Mrs. Rivas Worksheet Practice 10-3 and 10-4 30 3 = 10 1 3² 9 = 1² 1 9 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 30 3 = 10 1 3² 9 = 1² 1 9 100 x = 1 × 100 ÷ 9 = 11 = 1

Mrs. Rivas Worksheet Practice 10-3 and 10-4 10 2 = 25 5 2² 4 = 5² 25 4 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 10 2 = 25 5 2² 4 = 5² 25 4 x x = 500 × 4 ÷ 25 = 80 = 25 500

Mrs. Rivas Worksheet Practice 10-3 and 10-4 a Perimeter = b a² Area = Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 a Perimeter = b 9 3 = 1 3² 1² a² Area = b² 10 4 = 5 2 5² 2² 25 8 12 = 2 3 2² 3² 4 9

Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝒉=−𝟐 𝒌=−𝟏𝟎 𝒓= 𝟐𝟓 =𝟓 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 21. What are the center and radius of the circle with equation (𝑥 + 2) 2 + (𝑦 + 10) 2 =25? 𝒉=−𝟐 𝒌=−𝟏𝟎 𝒓= 𝟐𝟓 =𝟓

Mrs. Rivas Worksheet Practice 10-3 and 10-4 𝟔𝟎°= 𝟑𝟔𝟎−𝒙−𝒙 𝟐 Ida S. Baker H.S. Worksheet Practice 10-3 and 10-4 22. Vicky looked at the outside of a circular stadium with binoculars. She estimated the angle of her vision was reduced to 60º. She is positioned so that the line of site on either side is tangent to the stadium. What was the measure of the arc of the stadium intercepted by the lines of site? 60° 𝟔𝟎°= 𝟑𝟔𝟎−𝒙−𝒙 𝟐 𝟐∙𝟔𝟎°= 𝟑𝟔𝟎−𝟐𝒙 𝟐 ∙𝟐 𝟔𝟎°= 𝟑𝟔𝟎−𝟐𝒙 𝟐 𝟏𝟐𝟎°=𝟑𝟔𝟎−𝟐𝒙 −𝟐𝟒𝟎°=−𝟐𝒙 𝟏𝟐𝟎°=𝒙