Solving Two-Step Inequalities PRE-ALGEBRA LESSON 7-6 Solve each inequality. Graph the solutions. 1.w + 4 –5 2.7 < z – > a + 64.x – 5 –6 > < (For help, go to Lesson 2-9.) Check Skills You’ll Need 7-6

Solving Two-Step Inequalities PRE-ALGEBRA LESSON 7-6 Solutions 1. w + 4 –52. 7< z – 3 w + 4 – 4 –5 – < z – w –9 10< z z > 10 > > > 3. 4> a x – 5 –6 4 – 6 > a + 6 – 6x – –6 + 5 –2> a x –1 a< –2 < < < 7-6

Solving Two-Step Inequalities Solve and graph 7g + 11 > 67. PRE-ALGEBRA LESSON 7-6 7g + 11 > 67 7g + 11 – 11 > 67 – 11Subtract 11 from each side. 7g > 56Simplify. g > 8Simplify. Divide each side by 7. > 7g77g Quick Check 7-6

Solving Two-Step Inequalities Solve 6 – r – 6. PRE-ALGEBRA LESSON 7-6 < – r – 6 < – r – < 2323 Add 6 to each side. Simplify. 12 – r < 2323 Simplify. > –18 r, or r –18 < 3232 –(12) 3232 – 2323 –r Multiply each side by. Reverse the direction of the inequality symbol – > Quick Check 7-6

Solving Two-Step Inequalities Dale has $25 to spend at a carnival. If the admission to the carnival is $4 and the rides cost $1.50 each, what is the greatest number of rides Dale can go on? PRE-ALGEBRA LESSON Inequality r < Let = number of rides Dale goes on. Words $4 admission + $1.50/ride number of rides is less than or equal to $25 r 7-6

Solving Two-Step Inequalities (continued) PRE-ALGEBRA LESSON 7-6 The greatest number of rides Dale can go on is r 25 < Subtract 4 from each side r – 4 25 – 4 < Simplify.1.5r 21 < Divide each side by r < Simplify.r 14 < Quick Check 7-6

Solving Two-Step Inequalities PRE-ALGEBRA LESSON 7-6 Solve each inequality. 1.-2m a - 9 > 11 a > < m 15 >