1. Objective The student will be able to:
solve two-step inequalities.
SOL: A.5abc
Designed by Skip Tyler, Varina High School

2. 1) Solve 5m - 8 > 12 + 8 + 8 5m > 20 5 5 m > 4 5(4) – 8 = 12
5m > 20
m > 4
5(4) – 8 = 12
Draw “the line”
Add 8 to both sides
Simplify
Divide both sides by 5
Check your answer
Graph the solution o 4 5 3

3. Which graph shows the solution to 2x - 10 ≥ 4?.
Answer Now

4. 2) Solve 12 - 3a > 18 - 12 - 12 -3a > 6 -3 -3 a < -2
-3a > 6
a < -2
12 - 3(-2) = 18
Draw “the line”
Subtract 12 from both sides
Simplify
Divide both sides by -3
Simplify (Switch the inequality!)
Check your answer
Graph the solution o -2 -1 -3

5. 3) Solve 3m - 4 < 11 o + 4 + 4 3m < 15 3 3 m < 5
3m < 15
m < 5
5(5) – 4 = 2(5) + 11
Draw “the line”
Add 4 to both sides
Simplify
Divide both sides by 3
Check your answer
Graph the solution o 5 6 4

6. 4) Solve - 18 ≤ 3r + 3 ● - 3 - 3 -21 ≤ 3r 3 3 -7 ≤ r or r ≥ -7
-21 ≤ 3r
-7 ≤ r or r ≥ -7
2(-7) – 18 = 5(-7) + 3
Draw “the line”
Subtract 3 from both sides
Simplify
Divide both sides by 3
Check your answer
Graph the solution ● -7 -6 -8

7. 6) Solve 6 ≥ 5x - 4
x ≥ -2
x ≤ -2
x ≥ 2
x ≤ 2
Answer Now

8. What are the values of x if 3(x + 4) - 5(x - 1) < 5?
Answer Now