Francis turbines Examples Losses in Francis turbines NPSH

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Presentation transcript:

Francis turbines Examples Losses in Francis turbines NPSH Main dimensions

Traditional runner X blade runner

SVARTISEN P = 350 MW H = 543 m Q* = 71,5 m3/S D0 = 4,86 m D1 = 4,31m B0 = 0,28 m n = 333 rpm

La Grande, Canada P = 169 MW H = 72 m Q = 265 m3/s D0 = 6,68 m D1e = 5,71m D1i = 2,35 m B0 = 1,4 m n = 112,5 rpm

Outlet draft tube runner Inlet guide vane

Hydraulic efficiency 1

Losses in Francis Turbines Draft tube Output Energy Head [m] Hydraulic Efficiency [%]

Losses in Francis Turbines Hydraulic Efficiency [%] Output Energy Output [%]

Friction losses between runner and covers

Gap losses Gap losses

Friction losses Friction losses in the spiral casing and stay vanes Guide vane losses Gap losses Runner losses Draft tube losses

Absolute path without the runner installed Relative path Absolute path with the runner installed

Velocity triangles

Net Positive Suction Head, NPSH 1 J

NPSH NPSH NB: HS has a negative value in this figure.

NPSH required

Main dimensions Dimensions of the outlet Speed Dimensions of the inlet

Dimensions of the outlet We assume cu2= 0 and choose b2 and u2 from NPSHR: 13o < b2 < 22o (Lowest value for highest head) 35 < u2 < 43 m/s (Highest value for highest head) 1,05 < a < 1,15 0,05 < b < 0,15

Diameter at the outlet Connection between cm2and choose D2 : D1 D2

Speed Connection between n and choose u2 :

Correction of the speed The speed of the generator is given from the number of poles and the net frequency

Example Given data: Flow rate Q = 71.5 m3/s Head H = 543 m We choose: b = 0,10 b2 = 22o u2 = 40 m/s

Find D2 from:

Find speed from:

Correct the speed with synchronic speed:

We keep the velocity triangle at the outlet: c2K u2K u2 b2 c2 w2

Dimensions of the inlet At best efficiency point, cu2= 0

Diameter at the inlet We choose: 0,7 < u1 < 0,75 D1 D2

Height of the inlet Continuity gives: We choose: cm2 = 1,1 · cm1

Inlet angle cu1 u1 b1 cm1 w1 c1

Example continues Given data: Flow rate Q = 71.5 m3/s Head H = 543 m We choose: hh = 0,96 u1 = 0,728 cu2 = 0

Diameter at the inlet D1

Height of the inlet B1

Inlet angle u1 w1 c1 b1 cu1 cm1

SVARTISEN P = 350 MW H = 543 m Q* = 71,5 m3/S D0 = 4,86 m D1 = 4,31m B0 = 0,28 m n = 333 rpm