Triangles: the Ambiguous Case By: Rachel Atmadja, 2002 Source: Glencoe Adv. Mathematical Concepts Pg 324 #16.

Slides:



Advertisements
Similar presentations
TF.01.3 – Sine Law: The Ambiguous Case
Advertisements

Chapter 6 – Trigonometric Functions: Right Triangle Approach
Starter a 6 c A 49° 96° 1.Use the Law of Sines to calculate side c of the triangle. 2.Now find the Area of a Triangle.
 Work out problems on board  Reminder about minutes/seconds at the end.
The Sine Law (animated). Sine Law Let’s begin with the triangle  ABC:
Triangles- The Ambiguous Case Lily Yang Solving Triangles If you are given: Side-Side-Side (SSS) or Side-Angle-Side (SAS), use the Law of Cosines.
Laws of Sines. Introduction  In the last module we studied techniques for solving RIGHT triangles.  In this section and the next, you will solve OBLIQUE.
Aim: How do we handle the ambiguous case? Do Now: In ∆ABC, m  A = 30°, a = 6 and c = 10. Find  C to the nearest degree. We can use the Law of Sine to.
Copyright © 2011 Pearson, Inc. 5.5 Law of Sines. Copyright © 2011 Pearson, Inc. Slide What you’ll learn about Deriving the Law of Sines Solving.
Law of Sines. Triangles Review Can the following side lengths be the side lengths of a triangle?
Chapter 7 review Number 73 This method shows how to find the direction by adding the vector. You will use the laws of sines and cosines. To view this show,
LAW OF SINES: THE AMBIGUOUS CASE. Review Identify if the given oblique triangle can be solved using the Law of Sines or the Law of Cosines 1. X = 21 0,
Triangle Warm-up Can the following side lengths be the side lengths of a triangle?
6.1 Laws of Sines. The Laws of Sine can be used with Oblique triangle Oblique triangle is a triangle that contains no right angle.
Ambiguous Case of the Law of Sines Section 5.7. We get the ambiguous case when we are given SSA. Given a, b and A, find B. In calculator, inverse key.
5.5 Law of Sines. I. Law of Sines In any triangle with opposite sides a, b, and c: AB C b c a The Law of Sines is used to solve any triangle where you.
Homework Questions. LOGS Warm-up Convert from log form to exponential form Convert from exponential form to log form Expand Condense.
Quiz 1) Find side a and Angle C C A=45º c b=12 a B=72º 2) Find the Area A c b=14 a=18 B C=57º.
Trigonometry Section 6.1 Law of Sines. For a triangle, we will label the angles with capital letters A, B, C, and the sides with lowercase a, b, c where.
Notes Over 8.1 Solving Oblique Triangles To solve an oblique triangle, you need to be given one side, and at least two other parts (sides or angles).
Section Day 2 The Ambiguous Case of the Law of Sines.
7.1 The Law of Sines 56 46° 63° A B C. 7.1 The Law of Sines 14 64° 82° A B C.
Ambiguous Law of Sines Compute b sin A, then compare to a No solution One Solution Two Solutions One Solution Compute side a to side b No solution One.
EXAMPLE 2 Solve the SSA case with one solution Solve ABC with A = 115°, a = 20, and b = 11. SOLUTION First make a sketch. Because A is obtuse and the side.
Section 4.2 – The Law of Sines. If none of the angles of a triangle is a right angle, the triangle is called oblique. An oblique triangle has either three.
Law of Sines AAS ONE SOLUTION SSA AMBIGUOUS CASE ASA ONE SOLUTION Domain error NO SOLUTION Second angle option violates triangle angle-sum theorem ONE.
Law of Sines Section 6.1. So far we have learned how to solve for only one type of triangle Right Triangles Next, we are going to be solving oblique triangles.
GCSE Mathematics Problem Solving Shape and Measure Higher Tier.
EXAMPLE 1 Solve a triangle for the AAS or ASA case Solve ABC with C = 107°, B = 25°, and b = 15. SOLUTION First find the angle: A = 180° – 107° – 25° =
Lesson 29 – Sine Law & The Ambiguous Case IB Math HL - Santowski 6/23/20161Math HL - Santowski.
Homework Questions. LOGS Warm-up Evaluating Logs.
Pre calculus Problem of the Day Homework p. p odds, odds Find the area of a triangle with the given dimensions. r = 15 in s = 13 in t.
Problem The direction of the 75-lb forces may vary, but the angle between the forces is always 50 o. Determine the value of  for which the resultant.
Splash Screen. Then/Now You used trigonometric ratios to solve right triangles. Use the Law of Sines to solve triangles. Use the Law of Cosines to solve.
Math 20-1 Chapter 1 Sequences and Series 2.3B The Ambiguous Case of the Sine Law The Sine Law State the formula for the Law of Sines. What specific.
What you’ll learn Use the Law of Sines to solve oblique triangles. Use the Law of Sines to solve, if possible, the triangle or triangles in the ambiguous.
6.1: The Law of Sines. Law of Sines In any triangle ABC (in standard notation): a__ = b__ = c__ Sin A Sin B Sin C * Used with AAS and SSA problems.
Sine Law Homework Questions??? Pg. 25 # 3, 5, 7, 9.
Solving Right Triangles
Law of sines 6-1.
5.7 The Ambiguous Case for the Law of Sines
9.1 Law of Sines.
Objective: Use the law of sine. (SSA)
ASS triangles ,the law of sines and the ambiguous case.
5.6 The sine law Watch this!! Ambiguous Case
Unit 6: Trigonometry Lesson: Law of coSines.
The Ambiguous Case (SSA)
Solving Right Triangles
Laws of Sines.
Law of Sines What You will learn:
50 a 28.1o Warm-up: Find the altitude of the triangle.
Solving OBLIQUE triangles (ssa)
Homework Questions.
Homework Questions.
Copyright © 2017, 2013, 2009 Pearson Education, Inc.
5.3 The Ambiguous Case.
Homework Questions.
Law of Sines Goal: To solve triangles which aren’t necessarily
Section 6.1.
Law of Sines AAS ONE SOLUTION SSA AMBIGUOUS CASE ASA ONE SOLUTION
5.5 Law of Sines.
Law of Sines and Law of Cosines
Warm-up: Solve the triangle. mA = 70, c = 26, a = 25
8-6 Using the Law of Sines Objectives:
LT: I can use the Law of Sines and the Law of Cosines to find missing measurements on a triangle. Warm-Up Find the missing information.
Warm Up – 2/27 - Thursday Find the area of each triangle.
Law of Sines.
8-5 Using the Law of Sines Objectives:
Law of Sines (Lesson 5-5) The Law of Sines is an extended proportion. Each ratio in the proportion is the ratio of an angle of a triangle to the length.
When can we use the Sine Law?
Presentation transcript:

Triangles: the Ambiguous Case By: Rachel Atmadja, 2002 Source: Glencoe Adv. Mathematical Concepts Pg 324 #16

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A The ‘magic’ number: 32(sin 37 )= 19.3

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A The ‘magic’ number: 32(sin 37 )= < 27 < 32

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A The ‘magic’ number: 32(sin 37 )= < 27 < 32 Therefore, there are 2 solutions

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A Use law of Sines to find A: Sin 37 Sin A =

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A Sin 37 Sin A A = 45.5 = 45.5 Use law of Sines to find A:

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A Sin 37 Sin A A = 45.5 C = 180 – 37 – 45.5 = 97.5 = 45.5 Now find C:

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A Sin 37 Sin A Sin c A = 45.5 C = 97.5 = 45.5 Now use the Law of Sines to find side c =

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A Sin 37 Sin A Sin c A = 45.5 C = 97.5 c = 44.5 = 45.5 Now use the Law of Sines to find side c =

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A A = 45.5 C = 97.5 c = Now to find the 2 nd set of solution, let’s being by finding A2: A

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A A = 45.5 A2 = C = 97.5 c = Notice that A and A2 are supplementary angles. To find A2, simply subtract A from 180 A

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A A = 45.5 A2 = C = 97.5C2 = 8.5 c = Now find C2. You can find C2 simply by subtracting angles B and A2 from 180. A

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A A = 45.5 A2 = C = 97.5C2 = 8.5 c = Use the Law of Sines to find side c2: A

The Ambiguous Case Find all solutions for the triangle below: B = 37 a = 32 b = 27 C B A Sin 37 Sin c2 A = 45.5 A2 = C = 97.5C2 = 8.5 c = 44.5 c2 = Use the Law of Sines to find side c2: A =