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9.1 Law of Sines.

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Presentation on theme: "9.1 Law of Sines."— Presentation transcript:

1 9.1 Law of Sines

2 Law of Sines Used to solve oblique s ( s that are NOT right s) OR

3 Case 1: 2 Angles & 1 side known(AAS or ASA)
Case 1: 2 Angles & 1 side known(AAS or ASA) Ex 1) Solve the triangle where A = 37 , B = 82 , and a = 23 B C = 180 - 37 - 82 = 61 82 c a = 23 A 37 C b

4 Case 1: 2 Angles & 1 side known Ex 1) Solve the triangle where
Case 1: 2 Angles & 1 side known Ex 1) Solve the triangle where A = 37 , B = 82 , and a = 23 B 82 c a = 23 A 37 C b a = 23 A = 37 b = 38 B = 82 c = 33 C = 61 answer when “solving” a

5 Case 2: 2 sides & 1 angle opposite one of those sides known
(Ambiguous) (ASS – can’t do but know case 2) Case 2: 2 sides & 1 angle opposite one of those sides known A known angle is obtuse if a  b, then no if a > b, then unique A known angle is acute sinB > 1 → no sinB = 1 → right 0 < sinB < 1 → either or s or 0 < sinB < 1

6 Ex 2) Solve the triangle where A = 123 , a = 14, b = 21
Obtuse Impossible!!! → No (Ambiguous Case with no solution)

7 Ex 3) Solve the triangle where A = 48 , a = 61, b = 32
Acute Ex 3) Solve the triangle where A = 48 , a = 61, b = 32 Sine is (+)  B in QI or QII B = sin-1(0.3898) = 23° Or B = 180° - 23° = 157° But if B = 157° and A = 48° Not possible since > 180 So, B = 23° C = 180° - 48° - 23° = 109°

8 Ex 3) Solve the triangle where A = 48 , a = 61, b = 32
b = B = 23° c = C = 109° (Ambiguous Case w/ unique solution)

9 Homework #901 Pg – 12 all


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