CHARLES The neon gas inside a dry cleaner’s window sign is at a temperature of 114 oC and fills a space that totals 0.65 L. If this same sample of gas was transferred to a different sign with twice the volume, while maintaining the same pressure, what would the neon’s new temperature be?

V1 = V2 T2 = T1V2 T1 T2 V1 . T2 = (387 K) (1.3 L) . T2 = 774 K CHARLES

Avogadro If a weather balloon containing 121 moles of helium gas has a volume of 2.710 kL at 20OC and 1.05 atm, how many moles of helium gas are in a 25.0 L birthday balloon at a temperature of 293K and a pressure of 798 mmHg?

V1 = V2 n2 = n1V2 n1 n2 V1 . n2 = (121 mol) (25.0 L) . n2 = 1.12 mol Avogadro

Gay-Lussac Assuming a constant volume, a balloon with an internal pressure of 0.987 atm at 298 K would be what temperature at a pressure of 0.646 atm?

P1 = P2 T2 = T1P2 T1 T2 P1 . T2 = (298 K) (0.646 atm) . T2 = 195K Gay-Lussac

Combined Shortly after beginning to blow a bubble gum bubble, a child’s 14.3 mL bubble contains 0.000202 moles of air at 98oF and 1.11 atm. At the moment just before it popped, the child had added an additional 0.00149 moles of air, and the final temperature and pressure were 97.3oF and 758 torr respectively. What was the volume of the bubble right before it popped?

P1V1 = P2V2 V2 = P1V1n2T2 n1T1 n2T2 n1T1P2 . V2 = (1.11atm)(14.3mL)(0.001692 mol)(309K) . (0.000202mol)(310K)(0.997atm) V2 = 133 mL Combined

Boyle In a thermonuclear device,the pressure of the 0.50 L of gas within the bomb casing reaches 4.0x106atm. When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. What is the volume of the gas after the explosion?

P1V1 = P2V2 V2 = P1V1 . V2 = (4.0 x 106 atm)(0.50 L) . V2 = 2.0 x 106 L Boyle