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Pressure Conversions 1 atm = x 105 Pa 1 bar = 1 x 105 Pa

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Presentation on theme: "Pressure Conversions 1 atm = x 105 Pa 1 bar = 1 x 105 Pa"— Presentation transcript:

1 Pressure Conversions 1 atm = 1.01325 x 105 Pa 1 bar = 1 x 105 Pa
1 millibar (mb) = 100 Pa 1 atm = bar 1 atm = 760 torr 1 torr = 1 mm Hg

2 Section 8.7, pp

3

4 Boyle’s Law Change volume (V) and the pressure (P) will change
(assuming that temperature and the number of molecules are constant) Boyle’s Law PV = constant Pressure and Volume are inversely proportional P1V1 = P2V2

5 A gas occupying a volume of 725mL at a pressure of 0
A gas occupying a volume of 725mL at a pressure of atm is allowed to expand at constant temperature until its pressure reaches atm. What is the final volume? (725 ml)(0.970 atm) = (V2)(0.541 atm) V2 = ml or L

6 Change the amount of gas (n) and the volume (V) will change
(assuming that temperature and pressure constant) Avogadro’s Law n  V Number of Moles and Volume are proportional V V2 n n2 =

7

8 Change the temperature (T) and the pressure (P) will change
(assuming that the volume and number of moles are constant) Gay-Lussac’s Law T  P Temperature and Pressure are proportional P P2 T1 T2 =

9 An aerosol can is under a pressure of 3. 00 atm at 25C
An aerosol can is under a pressure of 3.00 atm at 25C. Directions on the can caution the user to keep the can in a place where the temperature does not exceed 52C. What would the pressure of the gas in the aerosol can be at 52C? 3.00 atm X atm 298 K K = X = 3.27 atm

10 Charles’ Law Change the temperature (T) and the volume (V) will change
(assuming that the pressure and number of moles are constant) Charles’ Law T  V Temperature and Pressure are proportional V V2 T T2 =

11 A sample of neon gas has a volume of 752mL at 25C
A sample of neon gas has a volume of 752mL at 25C. What volume will the gas occupy at 50C if the pressure remains constant? 752 ml X ml 298 K K = X = 815 ml

12 What we find is that everything is interrelated…
The combined Gas Law n  = constant Such that P1V1 P2V2 T T2 PV T =

13 A He filled balloon has a volume of 50. 0L at 15C and 820mmHg
A He filled balloon has a volume of 50.0L at 15C and 820mmHg. What volume will it occupy at 650mmHg and 10C? (50.0 L)(820 mmHg) = (X L)(650 mmHg) (288 K) (283 K) X = 62.0 L

14 PV = nRT Ideal Gas Law! PV n  = constant T
By defining the constant we can convert the proportionality into “workable” equation PV = nRT R is a constant which changes according to units, See Table 8.1 on page 401 R = L.atm/mol.K R = J/mol.K

15 Ideal Gas Conditions Negligible Interactions Negligible Particle Size
High Temperature Low Pressure

16 Standard Temperature and Pressure (STP) 0oC 1 atm
Under standard conditions, what is the volume of 1.00 mol of gas? PV = nRT (1 atm)( V ) = (1 mol)( L.atm/mol.K)(273 K) V = 22.4 L

17 How many moles of gas are in my 600 ml Pepsi bottle?
(assume that the room temperature is 22oC) PV = nRT (1 atm) (0.6 L) = n ( L.atm/mol.K) (295 K) n = mols


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