Calculations Lots of different formats for our answers, sometimes certain units are more helpful than others. Some branches of chemistry have a tendency.

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16.2 Concentration of Solutions

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Presentation transcript:

Calculations Lots of different formats for our answers, sometimes certain units are more helpful than others. Some branches of chemistry have a tendency to use one unit more than another.

N-40 – Solution Calculations Target: I can perform calculations related to solutions

Assumptions to make… UNLESS TOLD OTHERWISE… Assume your solvent is water…it is the “Universal Solvent” Assume the density of your solution is the same as water (1mL = 1g)

Ratio of masses expressed as a % Mass Percent or Percent Composition Ratio of masses expressed as a %

Parts per Million - ppm Ratio of masses but not expressed as a %, but rather out of one million – used when very low levels are significant like for pollution. 𝑝𝑝𝑚= 𝑚𝑎𝑠𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒 𝑚𝑎𝑠𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛 𝑥 1,000,000

Grams/Liter Ratio of mass of solute to volume of solution. Easy for when measuring a solid solute dissolved in a liquid. Used to test solubility. “Quick and dirty” unit. 𝐺𝑟𝑎𝑚𝑠 𝑝𝑒𝑟 𝐿𝑖𝑡𝑒𝑟= 𝑚𝑎𝑠𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛

Mole Fraction Ratio of moles of solute nA , to moles of total solution (solute nA + solvent nB)

Molarity – the best one!  Ratio of moles of solute to liters of solution. Similar to grams/L but converting it to moles lets us perform chemistry calculations better. Always trying to get to moles anyway!

Practice #1 734g Li2SO4 1 mol Li2SO4 = 6.68 mol Li2SO4 734 grams of lithium sulfate are dissolved to make 2500 mL of solution. What is the Molarity? Convert 734 grams of Li2SO4 in moles. 734g Li2SO4 1 mol Li2SO4 = 6.68 mol Li2SO4 109.962 g Li2SO4 𝑀= 𝑀𝑜𝑙𝑒𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒 𝐿𝑖𝑡𝑒𝑟𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛 = 6.68 𝑚𝑜𝑙 2.500 𝐿𝑖𝑡𝑒𝑟𝑠 =2.67 𝑀

Practice #2 1 mol Pb(C2H3O2)4 6.7 x 10-2 g Pb(C2H3O2)4 6.7 x 10-2 grams of Pb(C2H3O2)4 are dissolved to make 3.5 mL of solution. What is the concentration? When not told what unit to use, assume molarity! 1 mol Pb(C2H3O2)4 6.7 x 10-2 g Pb(C2H3O2)4 = 1.51 x 10-4 mol Pb(C2H3O2)4 443.2 g Pb(C2H3O2)4 𝑀= 𝑀𝑜𝑙𝑒𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒 𝐿𝑖𝑡𝑒𝑟𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛 = 1.51 𝑥 10−4 𝑚𝑜𝑙 0.0035 𝐿𝑖𝑡𝑒𝑟𝑠 =0.0432 𝑀

Making Dilutions 𝑀1𝑉1=𝑀2𝑉2 When you take one more concentrated solution and take a small amount of it and dilute it down by adding more solvent. 𝑀1𝑉1=𝑀2𝑉2

𝑉1=195.65 𝑚𝐿 𝑜𝑓 𝑡ℎ𝑒 2.3𝑀 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛 𝑖𝑠 𝑛𝑒𝑒𝑑𝑒𝑑 Practice #1 How much of a 2.3 M solution do you have to use in order to make 750mL of a 0.6 M solution? 2.3𝑀 𝑉1 = 0.6𝑀 750𝑚𝐿 𝑉1=195.65 𝑚𝐿 𝑜𝑓 𝑡ℎ𝑒 2.3𝑀 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛 𝑖𝑠 𝑛𝑒𝑒𝑑𝑒𝑑 How much water did you add??? 750-195.65 = 554.35mL H2O Extra H2O 750mL of 0.6 M SOLUTION 2.3M 195.65mL of the STRONGER STUFF 2.3M