a = v2 – v1 t a = 8 m/s s a = 8 m/s2 a = 36 m/s – 4 m/s 4 s #6 d

Slides:



Advertisements
Similar presentations
Linear Kinematics - v = x/t - time rate change of position (m/s) a =  v/t - time rate change of velocity (m/s/s)  v - Change in velocity (in m/s) a -
Advertisements

Graphing motion. Displacement vs. time Displacement (m) time(s) Describe the motion of the object represented by this graph This object is at rest 2m.
Physics: Concepts and Connections, 4 th ed., Art Hobson Chapter 3 – Motion.
Motion and Forces Unit Chapter 1 Section 3. Acceleration.
Acceleration. MEANING FORMULA = A = Acceleration V f = V i = t=
INTERPRETING VELOCITY VS TIME GRAPHS HONORS PHYSICS.
Velocity, speed and acceleration 5m/s velocity 5m/s North East 5m/s speed 5m/s going round Velocity is speed in a given direction An object moving at a.
Things to know!. Velocity-Time Graphs A velocity-time (V-T) graph shows an object’s velocity as a function of time. A horizontal line = constant velocity.
IF WE MEASURE DISTANCE AND TIME, WE GET:
The city school PHYSICS Saqib javeed April12,2011.
Physics Chapter 5. Position-Time Graph  Time is always on the x axis  The slope is speed or velocity Time (s) Position (m) Slope = Δ y Δ x.
Graphs of motion Contents: Position graphs Whiteboard Qualitative Instantaneous Velocity graphs Whiteboard Qualitative.
Acceleration Definition 2 ways to do it Positive acceleration Negative acceleration (deceleration) A change in velocity Change speed and/or Change direction.
Velocity-Time Graphs What is it and how do I read one?
STARTER During a road trip, in 6 hours you travel 300 miles. What is your average velocity? Average Velocity = distance travelled/time taken = 300 miles/6.
Adding SubtractingMultiplyingDividingMiscellaneous.
VELOCITY TIME GRAPHS. The Velocity vs. Time Graph Velocity (m/s) Time (s) ∆v ∆t Velocity vs. time.
Example Suppose that the position function of a particle moving on a coordinate line is given by s(t) = 2t3-21t2+60t+3 Analyze the motion of the particle.
Linear Kinematics - v = s/t - time rate change of position (m/s) a =  v/t - time rate change of velocity (m/s/s)  v - Change in velocity (in m/s) a -
1. What distance will a train stop in if its initial velocity is 23 m/s and its acceleration is m/s/s? 1058 m xvivfatxvivfat.
Aim: How do we use the kinematics formulas? Do Now: What is the difference between average velocity and instantaneous velocity? Quiz Tomorrow.
Linear Kinematics - displacement, velocity and acceleration Contents:
What is acceleration Acceleration  is the rate at which velocity changes over time. An Object will accelerate if its speed, direction of motion or both.
He Ashely is approaching a stoplight moving with a velocity of 30.0 m/s. The light turns yellow, and Ashley applies the breaks and skids to a stop. If.
3:00. 2:59 2:58 2:57 2:56 2:55 2:54 2:53 2:52.
A 4.25 kg block of wood has a kinetic coefficient of friction of and a static of between it and the level floor. 0. Calculate the kinetic friction.
F = ma F = Force m = Mass a = Acceleration. The Manned Manoeuvring Unit.
Constant Acceleration Consistent change in velocity with respect to time.
Speeding Up and Slowing Down? Acceleration.
Acceleration Acceleration is the rate of change of velocity.
Acceleration. Acceleration Acceleration is the rate of change in velocity. Acceleration can be a change in speed or direction.
1D Kinematics Equations and Problems. Velocity The rate at an object changes position relative to something stationary. X VT ÷ x ÷
Angular Mechanics - Radians r  s Full circle: 360 o = 2  Radians  = s/r Radians = m/m = ? TOC.
Acceleration.
Uniform Acceleration Formulas
Mechanics 1 : Kinematics
Describing Motion Some More Equations….
Acceleration.
Acceleration.
AVERAGE VELOCITY: V = d/t V = (Vi + Vf)/2
Integrated Physics and Chemistry
Top Fire Protection Services Ottawa available on Dubinskyconstruction
a) find the acceleration
Kinematics.
9.2 Calculating Acceleration
Ch 02 Graph Worksheet Answers
9.2 Calculating Acceleration
Graphing Motion Walk Around
Motion Unit Miss McDonald Science 8
9.2 Calculating Acceleration
Kinematics.
Describing and Measuring Motion
3.2 Part B Notes Motion graphs.
9.2 Calculating Acceleration
Unit 2: Acceleration (Lesson 1)
Total Distance Traveled
Calculations and Worked Examples
This waveform is 35.0 cm long. How long is the wavelength?
Adding with 9’s.
Adding with 10’s.
Section 9.4 – Solving Differential Equations Symbolically
vi - initial velocity (m/s) vf - final velocity (m/s)
Final Velocity and Acceleration Equations
Newton’s 2nd Law of Motion
Velocity vs. time graphs
Adding ____ + 10.
ACCELERATION.
Vectors - Doing basic physics with vectors Contents:
u - initial velocity (m/s) v - final velocity (m/s)
Motion Graphs 2 x v a.
Presentation transcript:

a = v2 – v1 t a = 8 m/s s a = 8 m/s2 a = 36 m/s – 4 m/s 4 s #6 d V1 = 4 m/s V2 = 36 m/s a = ? t = 4 s a = v2 – v1 t a = 36 m/s – 4 m/s 4 s a = 8 m/s s a = 8 m/s2

a = v2 – v1 t a = 3 m/s s a = 3 m/s2 a = 4.5 m/s – (-3 m/s) 2.5 s #8 d V1 = -3 m/s V2 = +4.5 m/s a = ? t = 2.5 s a = v2 – v1 t a = 4.5 m/s – (-3 m/s) 2.5 s a = 3 m/s s a = 3 m/s2

a = v2 – v1 t a = -8.33 m/s2 a = 0 m/s – 25 m/s 3 s #9 d V1 = 0 m/s t = 3 s a = v2 – v1 t a = 0 m/s – 25 m/s 3 s Increased Stopping time results in smaller acceleration a = -8.33 m/s2

a = v2 – v1 t v2 = 1 m/s v2 = v1 + at b) v2 = -1 m/s #18 d V1 = 2 m/s V2 = ? a = -0.5 m/s2 t = 2 s a = v2 – v1 t v2 = v1 + at v2 = 2 m/s + (-0.5 m/s2)(2s) b) v2 = 2 m/s + (-0.5 m/s2)(6s) v2 = 1 m/s b) v2 = -1 m/s

a = v2 – v1 t t = v2 – v1 a t = 3m/s – 22m/s -2.1 m/s2 t = 9.05 s #21 d V1 = 22 m/s V2 = 3 m/s a = -2.1 m/s2 t = ? a = v2 – v1 t t = v2 – v1 a t = 3m/s – 22m/s -2.1 m/s2 t = 9.05 s

d = v1t + ½ at2 d = 0 + ½ (3 m/s2)(30s)2 d = 1,350 m #39 d = ? V1 = 0 m/s V2 = a = 3 m/s2 t = 30 s d = v1t + ½ at2 d = 0 + ½ (3 m/s2)(30s)2 d = 1,350 m

d = v1t + ½ at2 v2 = v1 + at d = 0 + ½ (3 m/s2)(30s)2 d = 1,350 m #39 d = ? V1 = 0 m/s V2 = ? a = 3 m/s2 t = 30 s d = v1t + ½ at2 d = 0 + ½ (3 m/s2)(30s)2 d = 1,350 m v2 = v1 + at v2 = 0 + (3 m/s2)(30s) v2 = 90 m/s

d = v1t + ½ at2 d = (12m/s)(6s) + ½ (-1.6 m/s2)(6s)2 = 72m – 28.8m #89 d = ? V1 = 12 m/s V2 = a = -1.6 m/s2 t = 6 s t = 9 s d = v1t + ½ at2 d = (12m/s)(6s) + ½ (-1.6 m/s2)(6s)2 = 72m – 28.8m d = 43.2 m (@ 6s) d = (12m/s)(9s) + ½ (-1.6 m/s2)(9s)2 d = 43.2 m (@ 9s)

v2 = v1 + at v2 = -28 m/s How about at t = 25s? #89 – Follow-Up: Determine VELOCITY at every second for 12 full seconds. a = -1.6m/s/s v2 = v1 + at How about at t = 25s? -0.8m/s -2.4m/s v2 = -28 m/s -4m/s 0.8m/s -5.6m/s 2.4m/s -7.2m/s 4m/s -8.8m/s 5.6m/s -10.4m/s 7.2m/s -12m/s 8.8m/s 10.4m/s @t0, v = 12m/s

v22 = v12 + 2ad v22 = 0 + 2(49m/s2)(325m) v22 = 31,850 m2/s2 #88 d = 325 m V1 = 0 m/s V2 = ? a = 49 m/s2 v22 = v12 + 2ad v22 = 0 + 2(49m/s2)(325m) v22 = 31,850 m2/s2 v2 = 178.5 m/s

#92 d = ? V1 = 66 m/s V2 = 88 m/s a = t = 12s