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Ch 02 Graph Worksheet Answers

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1 Ch 02 Graph Worksheet Answers

2 1. What is the average acceleration from t = 0 to t = 3 seconds
1. What is the average acceleration from t = 0 to t = 3 seconds? From t = 0 to t = 4 seconds?

3 (15-10)/3 = 1.67 m/s2 (15-10)/4 = 1.25 m/s2

4 2. What is the acceleration depicted on this graph?

5 Zero. A constant change in position means constant velocity
Zero. A constant change in position means constant velocity. Constant velocity means no acceleration.

6 3. What is the velocity depicted on this graph?

7 (20m-0m)/4 sec = 5 m/s

8 4. How far does this object travel from zero to four seconds?.

9 x = v0t + ½ a t2 assuming it starts from rest: x = (0)4 + ½ (2
x = v0t + ½ a t2 assuming it starts from rest: x = (0)4 + ½ (2.5)42 x = 20 m

10 5. What is the acceleration depicted on this graph
5. What is the acceleration depicted on this graph? How far did the object travel during the 5 seconds?

11 a = (15-10)/5 = 1 m/s2 x = v0t + ½ a t2 x = (10)5 + ½ (1) 52 x = 62
a = (15-10)/5 = 1 m/s2 x = v0t + ½ a t2 x = (10)5 + ½ (1) x = 62.5 m

12 6. What is the velocity from 1 second to 3 seconds
6. What is the velocity from 1 second to 3 seconds? How far did the object travel from 1 second to 3 seconds?

13 Zero velocity, no change in position
Zero velocity, no change in position. Zero velocity so zero displacement.

14 7. What is the velocity from 3 seconds to 10 seconds
7. What is the velocity from 3 seconds to 10 seconds? How far did the object travel from 3 seconds to 10 seconds?

15 (30-100)/(10-3) = -10 m/s x = 70 meters

16 8. What is the velocity from 10 seconds to 13 seconds
8. What is the velocity from 10 seconds to 13 seconds? How far did the object travel from 10 seconds to 13 seconds?

17 Zero velocity, no change in position
Zero velocity, no change in position. Zero velocity so zero displacement.

18 9. What is the velocity from 13 seconds to 17 seconds
9. What is the velocity from 13 seconds to 17 seconds? How far did the object travel from 13 seconds to 17 seconds?

19 (90-30)/(17-13) = 15 m/s x = 60 meters

20 10. What is the average velocity for the entire trip?

21 (90-100)/(17-1) = m/s

22

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