3.2 The Remainder Theorem.

Slides:



Advertisements
Similar presentations
Chapter 6: Polynomials and Polynomial Functions Section 6
Advertisements

5.3 Division of Polynomials. Dividing a Polynomial by a monomial.  Divide each term of the polynomial by the monomial.
Pre Calc Lesson 2.2 Synthetic Division ‘Remainder’ and ‘Factor’ Theorems Review Long Division: 5365 ÷ 27 Now review ‘long division’ of polynomials: (2x.
5.5 Apply the Remainder and Factor Theorem
Remainder and Factor Theorem Unit 11. Definitions Roots and Zeros: The real number, r, is a zero of f(x) iff: 1.) r is a solution, or root of f(x)=0 2.)
7.5.1 Zeros of Polynomial Functions
Quick Crisp Review Zeros of a polynomial function are where the x-intercepts or solutions when you set the equation equal to zero. Synthetic and long division.
Polynomial Division and the Remainder Theorem Section 9.4.
6.5 The Remainder and Factor Theorems p. 352 How do you divide polynomials? What is the remainder theorem? What is the difference between synthetic substitution.
Section 2.3 Polynomial and Synthetic Division Long Division of polynomials Ex. (6x 3 -19x 2 +16x-4) divided by (x-2) Ex. (x 3 -1) divided by (x-1) Ex (2x.
1 What we will learn today…  How to divide polynomials and relate the result to the remainder and factor theorems  How to use polynomial division.
Real Zeros of Polynomial Functions
Warm-Up 2/
Today in Pre-Calculus Go over homework Notes: Remainder and Factor Theorems Homework.
7.4 THE REMAINDER & FACTOR THEOREMS Objectives: The student will be able to… 1)evaluate functions using synthetic substitution 2)determine whether a binomial.
 The remainder theorem states that the remainder that you get when you divide a polynomial P(x) by (x – a) is equal to P(a).  The factor theorem is.
Section 5.3(d) Synthetic Substitution. Long division Synthetic Division can be used to find the value of a function. This process is called Synthetic.
Section 2-2 Synthetic Division; The Remainder and Factor Theorems.
7.3 Products and Factors of Polynomials Objectives: Multiply polynomials, and divide one polynomial by another by using long division and synthetic division.
Warm Up 1.What is the absolute minimum of f(x) = 2x 4 – 17x x 2 – 7x – 15 2.A ball is thrown into the air. It’s height above the ground in feet is.
Factor Theorem Using Long Division, Synthetic Division, & Factoring to Solve Polynomials.
3.6 Day 2 Why Synthetic Division? What use is this method, besides the obvious saving of time and paper?
Using theorems to factor polynomials.  If a polynomial f(x) is divided by x-k, then the remainder r = f(k)  This is saying, when you divide (using synthetic.
Section 4-3 The Remainder and Factor Theorems. Remainder Theorem Remainder Theorem – If a polynomial P(x) is divided by x-r, the remainder is a constant,
Warm Up no 0, 3 x = -3. Homework Questions Section 2.2 Synthetic Division; The Remainder and Factor Theorems Objective: To use synthetic division and.
If a polynomial f(x) is divided by (x-a), the remainder (a constant) is the value of the function when x is equal to a, i.e. f(a). Therefore, we can use.
ALGEBRA II REMAINDER and FACTOR THEOREMS.
2.5 Apply the Remainder and Factor Theorem Long Division and Synthetic Division Pg. 85.
Help the Poor Math Student  Vocabulary Dividend: number being divided Divisor: number you are dividing by Quotient: is number you get when you divide.
LESSON 5.6 Rational Zeros of Polynomial Functions.
Get out your homework, but keep it at your desk..
Quotient Dividend Remainder Divisor Long Division.
Polynomial and Synthetic Division Objective: To solve polynomial equations by long division and synthetic division.
Sect. 2-2 Synthetic Division; The remainder and Factor theorems Objective: SWBAT use the synthetic division and to apply the remainder and factor theorems.
Warm – up #2 Find the remainder when P(x) is divided by x – c.
Long and Synthetic Division. Long Division Polynomial long division can be used to divide a polynomial d(x), producing a quotient polynomial q(x) and.
Polynomial Division Objective: To divide polynomials by long division and synthetic division.
Last Answer LETTER I h(x) = 3x 4 – 8x Last Answer LETTER R Without graphing, solve this polynomial: y = x 3 – 12x x.
Math zeros of the function 3 and -2 x-intercepts of the graph are located at x = 3 or x = -2 What is the relationship between the x-intercepts of.
Dividing Polynomials Section 4.3.
Lesson 6-3: Dividing Polynomials
Divide x3 + x2 – 10x + 8 by x+4 using long division.
Warm Up Compute the following by using long division.
Chapter Polynomials of Higher Degree
3x + 2 6x3 - 5x2 – 12x – 4 2x2 – 3x – 2 6x3 + 4x2 -9x2 – 12x -9x2 – 6x
Section 5.4 – Dividing Polynomials
Homework Questions?.
Do Now  .
Division of a Polynomial
Divide by x - 1 Synthetic Division: a much faster way!
Remainder Theorem What’s left over?.
3.4 Zeros of Polynomial Functions
Dividing Polynomials Long Division A little review:
1a. Divide using long division. (9x3 – 48x2 + 13x + 3) ÷ (x – 5)
Dividing Polynomials Algebra
Warm Up 1. Divide f(a) = 4a2 – 3a + 6 by a – 2 using any method.
Notes 5.6 (Day 1) Find Rational Zeros.
Apply the Remainder and Factor Theorems
Remainder and Factor Theorem
Today in Precalculus Go over homework Notes: Remainder
The Factor Theorem Warm Up x-intercepts of the graph are located at
7.3 Products and Factors of Polynomials
What is synthetic division?
What is synthetic division?
21 = P(x) = Q(x) . (x - r) + P(r) 4.3 The Remainder Theorem
What is synthetic division?
Warm Up.
Warm Up.
Polynomials Thursday, 31 October 2019.
Dividing Polynomials (SYNTHETIC Division)
Presentation transcript:

3.2 The Remainder Theorem

Homework from last day P. 124 #1 – 5 And from Tuesday, p. P. 114 #1, 2, 3, 5, 6, 9, C4

The Remainder Theorem Given P(x) = x3 - 4x2 + 5x + 1, determine the remainder when P(x) is divided by x - 1. -1 1 -4 5 1 The remainder is 3. -1 -2 3 1 -3 2 3 NOTE: P(1) gives the same answer as the remainder using synthetic division. Using f(x) = x3 - 4x2 + 5x + 1, determine P(1): P(1) = (1)3 - 4(1)2 + 5(1) + 1 = 1 - 4 + 5 + 1 = 3 Therefore P(1) is equal to the remainder. In other words, when the polynomial x3 - 4x2 + 5x + 1 is divided by x - 1, the remainder is P (1).

Remainder Theorem: When a polynomial P(x) is divided by x - a, the remainder is P(a). [think x - a, then x = a] Determine the remainder when x3 - 4x2 + 5x - 1 is divided by: a) x - 2 b) x + 1 Calculate P(-1) P(-1) = (-1)3 - 4(-1)2 + 5(-1) - 1 = -1 - 4 - 5 - 1 = -11 Calculate P(2) P(2) = (2)3 - 4(2)2 + 5(2) - 1 = 8 - 16 + 10 - 1 = 1 The remainder is -11. The remainder is 1. Point (-1, -11) is on the graph of of f(x) = x3 - 4x2 + 5x - 1 Point (2, 1) is on the graph of of f(x) = x3 - 4x2 + 5x - 1

Applications When the remainder is 30. is divided by Determine the value of k.

Problem Solving When the polynomial 3x3 + ax2 + bx -9 is divided by x - 2 , the remainder is -5. When the polynomial is divided by x + 1, the remainder is -16. What are the values of a and b?

Assignment Page 124 6a,7b, 8a,c, 9, 11, 14

Using Synthetic Division 1. (4x3 - 11x2 + 8x + 6) ÷ (x - 2) -2 4 -11 8 6 P(x) = (x - 2)(4x2 - 3x + 2) + 10 - 8 6 -4 4 -3 2 10 2. (2x3 - 2x2 + 3x + 3) ÷ (x - 1) -1 2 -2 3 3 -2 0 -3 P(x) = (x - 1)(2x2 + 3) + 6 2 0 3 6