Equations – Success if you can do these

Slides:

Advertisements

Similar presentations

Solving Percent Problems Using Proportions

Advertisements

Solving Equations with Brackets or Fractions. Single Bracket Solve 3(x + 4) = 24 3x + 12 = 24 3x + 12 – 12 = x = 12 x = 4 Multiply brackets out.

Solve the equation -3v = -21 Multiply or Divide? 1.

 Sometimes you have a formula and you need to solve for some variable other than the "standard" one. Example: Perimeter of a square P=4s It may be that.

Solving Equations Using Multiplication and Division Algebra 1 Section 3.2a.

Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x –

Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination.

Solving Inequalities Just like with equations, the solution to an inequality is a value that makes the inequality true. You can solve inequalities in.

Objective The student will be able to: solve equations using multiplication and division.

Section 3.2 Solving Equations using Multiplication and Division.

Solving Quadratic Equations. Find the quadratic equation if the solutions are 3 and -2. x = 3 x = -2 Make them equal zero. x – 3 = 0x + 2 = 0 (x – 3)(x.

* Collect the like terms 1. 2a = 2a x -2x + 9 = 6x z – – 5z = 2z - 6.

Solving 2 step equations. Two step equations have addition or subtraction and multiply or divide 3x + 1 = 10 3x + 1 = 10 4y + 2 = 10 4y + 2 = 10 2b +

Lesson 7.4 Solving Multiplication and Division Equations 2/3/10.

4-6 Solving Equations with Fractions What You’ll Learn ► To solve one – step equations ► To solve two – equations.

1) Solve. -5t = 60 To get the variable by itself, which number needs to be moved? -5 To move the -5, you have to do the opposite operation. What operation.

Objectives The student will be able to:

Section 1-3: Solving Equations

Solving Equations With Fractions

SOLVING INEQUALITIES LESSON 6(2).

Solving 2 Step Equations.

Solving Two- Step Equations

Solving Two-Step Equations

Solving EQUATIONS Lesson #2 created by: ms. Guarnieri

Warm-Up BC 3. |A|.

Solving Two- Step Equations

Math Objective: Solve Two-Step Equations

Solving Two and Multi Step Equations

Solving Systems Using Elimination

Solving One-Step Equations

Solving 2-Step Variable Equations

Objective The student will be able to:

Do Now 1) t + 3 = – 2 2) 18 – 4v = 42.

Objective The student will be able to:

Solving Two-Step Equations

Equations – Success if you can do these

Solving Equations Finding Your Balance

a + 2 = 6 What does this represent? 2 a

Solving 1 and 2 Step Equations

Equations and Inequalities

Solving Multiplication Equations

Warm Up Solve for x. Simplify Simplify

Solving Equations by Combining Like Terms

Equations – Success if you can do these

Multiplying and Dividing Integers

Solving Equations with Variables on Both Sides

Solving Equations with Variables on Both Sides

The Percent Proportion

Multiplying fraction and whole number

Think about… How is an equation like a balance scale?

Solving Multi-Step Equations

2.2 Solving Equations with Variables on Both Sides

IF YOU MULTIPLY or DIVIDE BY A NEGATIVE YOU MUST SWITCH THE SIGN!

Equations – Success if you can do these

Learn to solve 2-step equations

Math-7 NOTES What are Two-Step Equations??

Learn to solve equations with integers.

Example 2B: Solving Linear Systems by Elimination

Solving Two Step Algebraic Equations

Do Now Solve. 1. –8p – 8 = d – 5 = x + 24 = 60 4.

Solve equations using multiplication and division.

Objective The student will be able to:

Solving 2-Step Variable Equations

Math-7 NOTES 1) 3x = 15 2) 4x = 16 Multiplication equations:

Do Now Solve. n + 9 = z = 55 n = x = z = -16

Equations – Success if you can do these

Solving Linear Equations

Solving Algebraic Equations with Addition and Subtraction

Objective Solve radical equations.. Objective Solve radical equations.

Solving Algebraic Equations with Addition and Subtraction

Presentation transcript:

Equations – Success if you can do these 3x = 6 4x + 2 = 3x + 7 x/4 = 2 5x – 3 = 7 + 3x x + 3 = 17 3(x + 2) = 12 x – 4 = 13 4(x + 5) = 32 3x + 4 = 25 3(2x – 2) = 2(x + 6) 4x – 3 = 17 4(3x + 5) = 2(x + 15)

How to solve the 5x = 20 type of equation 5 and 20 can be any number

5x = 20 means 5 X x = 20 5x = 20 5 X x = 20

So, you get rid of the 5 X by ÷ 5 5x = 20 means 5 X x = 20 So, you get rid of the 5 X by ÷ 5 5x = 20 5 X x ÷ 5 = 20 ÷ 5

So, you get rid of the 5 X by ÷ 5 5x = 20 means 5 X x = 20 So, you get rid of the 5 X by ÷ 5 5x = 20 5 X x ÷ 5 = 20 ÷ 5 x = 4

5x = 20 means 5 X x = 20 So, you get rid of the 5 X by ÷ 5 5x = 20 5 X x ÷ 5 = 20 ÷ 5 x = 4 But you must divide both sides by 5

just divide both sides by the number that multiplies the x. For equations like 5x = 20 just divide both sides by the number that multiplies the x. 5x = 20 x = 20 ÷ 5 x = 4 Like this

How to solve the x/3 = 4 type of equation The 3 and 4 can be any number

It means x ÷ 3 = 4 x/3 = 4 x ÷ 3 = 4

x/3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 X 3 It means x ÷ 3 = 4 Get rid of ÷ 3 by using a X 3

x/3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 x = 12 X 3 It means x ÷ 3 = 4 Get rid of ÷ 3 by using a X 3

x/3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 x = 12 X 3 It means x ÷ 3 = 4 Get rid of ÷ 3 by using a X 3 You must X 3 on both sides

just multiply both sides by the number that divides the x. For equations like x/3 = 4 just multiply both sides by the number that divides the x. x/3 = 4 x = 4 X 3 x =12 Like this

Try these 1 2x = 16 7 x/4 = 2 2 3x = 21 8 x/2 = 3 3 5x = 35 9 x/4 = 5 10 x/5 = 6 5 2x = 7 11 x/8 = 7 6 5x = 12 12 x/9 = 10

Remember, always do the same thing to both sides. Felix is checking that you do this properly. x/3 = 12 x ÷ 3 X 3 = 12 X 3 x =36