Analyzing Experimental Data The Straight Line D as a function of T With Calculator Screens Created for CVCA Physics by Dick Heckathorn 30 August 2K+4 Chapter 1 Section 7 Page 21

A. Getting Ready 1. [On] [Mode] 2. Normal Float Degree Func Connected Sequential Real Full 3. To Exit: [2nd] [Quit]

B. Clearing Lists 1. [Stat] [Edit] 2. Place cursor over list header 4. [] 5. Repeat for each header

C. Re-name Columns/Store Data 1. Cursor over blank header 2. [2nd] [INS] ‘T’ [Enter] [] 3. Cursor over blank header 4. [2nd] [INS] ‘D’ [Enter] [] 5. Enter data in correct column. T (s) 1 2 3 4 5 6 7 D( m) 28 56 84 112 140 168 196

D. Clear Active Graphing 1 [y=] 2. clear any equations

D. Clear Active Graphing 3. [2nd] [stat plot] 4. [4:PlotsOff] 5. [Enter] Will plot ‘D’ as a function of ‘T’

E. Preparing to Graph 1. [2nd] [Stat Plot] 2. With cursor at 1: [Enter] 3. a. on b. Type: select 1st graph (points) c. Xlist to: ‘T’ [2nd] [List] ‘T’ Ylist to: ‘D’ [2nd] [List] ‘D’ d. Mark: square

(This allows all points to be plotted using all of the screen.) E. Graphing Data 1. [Zoom] [9: ZoomStat] (This allows all points to be plotted using all of the screen.)

E. Graphing Data 2. Graph

E. Graphing Data 3. [Windows] a. Set both ‘Xmin=’ and ‘Ymin=’ to zero

(If can’t see horizontal & vertical axes) [2nd] [Format] [AxesOn”] E. Graphing Data 3. b. [Graph] (This shows all of 1st quadrant) (If can’t see horizontal & vertical axes) [2nd] [Format] [AxesOn”]

F. Finding the Equation Shape of line is? 1. a straight going through origin. From this we can determine? 2. Equation of the straight line using: y = mx + b concept

F. Finding the Equation zero because? 3. The value of b is? it crosses the y axis at zero 4. What is the equation?

F. Finding the Equation [Stat] [Calc] [4:LinReg(ax+b)]

F. Finding the Equation 3. [2nd] [List] ‘T’, ‘,’ 4. [2nd] [List] ‘D’ 5. [Enter]

F. Finding the Equation 6. On screen we see:

y = ax + b F. Finding the Equation Starting with: Substituting 28 m/s for ‘a’ and zero for ‘b’, one gets: Replacing ‘y’ with ‘D’ and ‘x’ with ‘T’ one gets the equation:

G. Relationship Since b = 0, we can say; D is directly proportional to T What does this means?

H. Plotting Line of Best Fit 1. [y=]

H. Plotting Line of Best Fit [VARS] [5:Statistics…] [EQ] [1:RegEq]

H. Plotting Line of Best Fit [Enter] [Graph] Add graph

I. Summary Since the first graph yielded a straight line, we then found the equation of this straight line.

Do not go on unless you have completed the above. J. A Final, Final Thought At this time, write out a brief summary using bullet points for what you did. Do not go on unless you have completed the above.

General Summary ▪ Get Ready ▪ Clear Lists ▪ Rename Columns/Store Data ▪ Clear Active Graphing ▪ Graph Data ▪ Find the Equation ▪ Plot Line of Best Fit

K. A Shortcut 1. Using original data, plot ‘D’ as a function of ‘T’ 2. [Stat] [Calc] [A:PwrReg]

K. A Shortcut 4. [2nd] [List] ‘T’ [,] 5. [2nd] [List] ‘D’ [Enter]

K. A Shortcut 5. On screen we see:

K. A Shortcut y = a*x^b Starting with: Substituting 28 m/s for a and 1 for b, one gets: Replacing ‘y’ with ‘D’ and ‘x’ with ‘T’ one gets the equation:

L. Summary 6. How does this equation compare to that found earlier? They should be the same.

That’s all folks!