Force on springs F = kx F = restoring force (in N) k = spring constant (in N/m) (spring stiffness) x - Amount the spring has been distorted (in m) (stretched,/compressed)

A spring requires 15 N to stretch 42 cm. k = ? F = kx 15 N = k(.42 m), k = (15 N)/(.42 m) = 35.7 N/m 35.7 N/m

Ali Zabov stretches a 53 N/m spring 13 cm with what force? F = kx = (53 N/m)(.13 m) = 6.89 N = 6.9 N 6.9 N

Nona Zabov allows the weight of a 2 Nona Zabov allows the weight of a 2.1 kg mass to stretch a 35 N/m spring. What distance does it stretch? F = ma, weight = mg F = kx F = (2.1 kg)(9.8 N/kg) = 20.58 N F = kx, x = F/k x = (20.58 N)/(35 N/m) = .588 m = .59 m .59 m