1) Which pair of factors of 8 has a sum of 9?

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Presentation transcript:

1) Which pair of factors of 8 has a sum of 9? Bellwork: 1/25/18 1) Which pair of factors of 8 has a sum of 9? 2) Which pair of factors of 30 has a sum of –17? Multiply 3) (x +2)(x +3) 4) (r + 5)(r – 9)

Factoring We will... Factor quadratic trinomials of the form  ax2 + bx + c.

Factor 3x2 – 2x – 8 Factor: Factor 6x2 + 11x + 4 Factor x2 + 15x + 36

Factor: w2+w-12 3x3-21x2+30x 2w2+10w-48 y2-8y+15 6x2 + 17x + 5

Bellwork: 1/26/18 Factor out the GCF: 1) 12y3-6y2-9y 2) -15ab+25a 3) 2x3+3x2+8x+12 4) 3n2 + 11n – 4

x2+6x+8 t2-8t-20 x2-100 6x2 + 7x – 3 -4y2+4y+24 2x2 + 9x – 18 4n2 – n – 3

(x + 3)(x +4) = x2 + 7x + 12

x2 – 8x – 20 x2 + x – 20 x2 – 13x + 40 x2 – 5x + 6 x2 – 3x – 18 Factor: x2 + 13x + 42 x2 – 5x + 6 x2 – 8x + 15 x2 + 8x + 12 x2 + x – 20 x2 – 3x – 18 x2 – 8x – 20 x2 – 13x + 40

Factor x2 + x – 20 x2 – 8x – 20 x2 – 3x – 18 x2 + 2x – 15

Factor y2 + 10y + 21. Show that the original polynomial  and the factored form have the same value for n = 0, 1, 2,  3, and 4. Factor n2 – 7n + 10. Show that the original polynomial  and the factored form have the same value for n = 0, 1, 2,  3, and 4.

Bellwork: 2/10/15 Factor out the GCF: 1) 16x3+8x2+4x 2) 27xy-9x2y2 3) -12p2+5p 4) -6b2+12b-15

Bellwork: 1/30/18 Factor out the GCF: 1) 45x2y2-10xy 2) 8a3-16a2-4a 3) m3+3m2-5m-15 4) x2-4x-12 5) How many factors are there in the expression (2x+7)(y-12)z?

Factoring Continued We will.... Factor special polynomials Practice all factoring using grouping method Take Quiz

Factor: x2+6x+9 y2+10y+25 a2+18a+81 x2+16x+64 y2-49 4x2-25 m2-144

2x2 - 12x -14 6x2 + 11x + 3