8.4 Properties of Similar Triangles

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Presentation transcript:

8.4 Properties of Similar Triangles

Example 1: Finding the Length of a Segment Find US.

Example 2: Verifying Segments are Parallel Verify that . Since , by the Converse of the Triangle Proportionality Theorem.

Check It Out! Example 2 AC = 36 cm, and BC = 27 cm. Verify that . Since , by the Converse of the Triangle Proportionality Theorem.

Example 3: Art Application Suppose that an artist decided to make a larger sketch of the trees. In the figure, if AB = 4.5 in., BC = 2.6 in., CD = 4.1 in., and KL = 4.9 in., find LM and MN to the nearest tenth of an inch.

The previous theorems and corollary lead to the following conclusion.

Example 4: Using the Triangle Angle Bisector Theorem Find PS and SR. by the ∆  Bisector Theorem. Substitute the given values. 40(x – 2) = 32(x + 5) Cross Products Property 40x – 80 = 32x + 160 Distributive Property

Example 4 Continued 40x – 80 = 32x + 160 8x = 240 Simplify. x = 30 Divide both sides by 8. Substitute 30 for x. PS = x – 2 SR = x + 5 = 30 – 2 = 28 = 30 + 5 = 35

Check It Out! Example 4 Find AC and DC. by the ∆  Bisector Theorem. Substitute in given values. 4y = 4.5y – 9 Cross Products Theorem –0.5y = –9 Simplify. y = 18 Divide both sides by –0.5. So DC = 9 and AC = 16.

Find the length of each segment. 1. 2. SR = 25, ST = 15

Classwork Page 277 (8-21 all) Page 279 (32-34)