Chapter 4 Compounds and Their Bonds 4.1 Valence Electrons 4.2 Octet Rule and Ions LecturePLUS Timberlake

LecturePLUS Timberlake Chemical Bonds Attraction between two or more atoms Interaction between valence electrons Ionic bonds Covalent bonds Metallic bonds LecturePLUS Timberlake

LecturePLUS Timberlake Valence Electrons Electrons in the highest (outer) electron level Have most contact with other atoms Outer shells of noble gases contain 8 valence electrons (except He = 2) Example: Ne 2, 8 Ar 2, 8, 8 LecturePLUS Timberlake

Electron Dot Structures Symbols of atoms with dots to represent the valence-shell electrons 1A 2A 3A 4A 5A 6A 7A 8A H He:            Li Be  B   C   N   O  : F  :Ne :                    Na Mg  Al  Si  P S :Cl  :Ar :         LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check  A. X would be the electron dot formula for 1) Na 2) K 3) Al   B.  X  would be the electron dot formula 1) B 2) N 3) P LecturePLUS Timberlake

LecturePLUS Timberlake Solution  A. X would be the electron dot formula for 1) Na 2) K   B.  X  would be the electron dot formula 2) N 3) P LecturePLUS Timberlake

LecturePLUS Timberlake Octet Rule An octet in the outer shell makes atoms stable Electrons are lost, gained or shared to form an octet Unpaired valence electrons strongly influence bonding LecturePLUS Timberlake

Metals forming ions- Cations (cats have paws-pos) Metals lose electrons to match the number of valence electrons of their nearest noble gas Positive ions form as a result LecturePLUS Timberlake

Formation of Sodium Ion Sodium atom Sodium ion Na  – e  Na + 2-8-1 2-8 ( = Ne) 11 p+ 11 p+ 11 e- 10 e- 0 1+ LecturePLUS Timberlake

Formation of Magnesium Ion Magnesium atom Magnesium ion  Mg  – 2e  Mg2+ 2-8-2 2-8 (=Ne) 12 p+ 12 p+ 12 e- 10 e- 0 2+ LecturePLUS Timberlake

Some Typical Ions with Positive Charges (Cations) Group 1A Group 2A Group 3A H+ Mg2+ Al3+ Li+ Ca2+ Na+ Sr2+ K+ Ba2+ LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check A. Number of valence electrons in aluminum 1) 1 e- 2) 2 e- 3) 3 e- B. Change in electrons for octet 1) lose 3e- 2) gain 3 e- 3) gain 5 e- C. Ionic charge of aluminum 1) 3- 2) 5- 3) 3+ LecturePLUS Timberlake

LecturePLUS Timberlake Solution A. Number of valence electrons in aluminum 3) 3 e- B. Change in electrons for octet 1) lose 3e- C. Ionic charge of aluminum 3) 3+ LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check Give the ionic charge for each of the following: A. 12 p+ and 10 e- 1) 0 2) 2+ 3) 2- B. 50p+ and 46 e- 1) 2+ 2) 4+ 3) 4- C. 15 p+ and 18e- 2) 3+ 2) 3- 3) 5- LecturePLUS Timberlake

LecturePLUS Timberlake Solution Give the ionic charge for each of the following: A. 12 p+ and 10 e- 2) 2+ B. 50p+ and 46 e- 2) 4+ C. 15 p+ and 18e- 2) 3- LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check A. Why does Ca form a Ca2+ ion? B. Why does O form O2- ion? LecturePLUS Timberlake

LecturePLUS Timberlake Solution A. Why does Ca form a Ca2+ ion? Loses 2 electrons to give octet 2-8-8-2 2-8-8 (like Ar) B. Why does O form O2- ion? Gains 2 electrons to give octet 2-6 + 2e- 2-8 (like Ne) LecturePLUS Timberlake

Nonmetal Ions-anions (a negative ion) Nonmetals in 5A, 6A, and 7A gain electrons from metals, become negatively charged Nonmetal ionic charge: 3-, 2-, or 1- LecturePLUS Timberlake

LecturePLUS Timberlake Fluoride Ion unpaired electron octet     1 - : F  + e : F :     2-7 2-8 (= Ne) 9 p+ 9 p+ 9 e- 10 e- 0 1 - ionic charge LecturePLUS Timberlake

LecturePLUS Timberlake Learning Check Complete the names of the following ions: 5A 6A 7A N3 O2 F nitride __________ fluoride P3 S2 Cl ___________ __________ _________ Br  _________ LecturePLUS Timberlake

LecturePLUS Timberlake Solution 5A 6A 7A N3 O2 F nitride oxide fluoride P3 S2 Cl phosphide sulfide chloride Br  bromide LecturePLUS Timberlake