Stoichiometry – Mr. Mole.

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Presentation transcript:

Stoichiometry – Mr. Mole

Stoichiometry is… Greek for “measuring elements” Pronounced “stoy kee ahm uh tree” Defined as: calculations of the quantities in chemical reactions, based on a balanced equation. There are 4 ways to interpret a balanced chemical equation

#1. In terms of Particles An Element is made of atoms A Molecular compound (made of only nonmetals) is made up of molecules (Don’t forget the diatomic elements) Ionic Compounds (made of a metal and nonmetal parts) are made of formula units

Example: 2H2 + O2 → 2H2O Two molecules of hydrogen and one molecule of oxygen form two molecules of water.

Remember: A balanced equation is a Molar Ratio #2. In terms of Moles The coefficients tell us how many moles of each substance 2Al2O3 ® 4Al + 3O2 2Na + 2H2O ® 2NaOH + H2 Remember: A balanced equation is a Molar Ratio

#3. In terms of Mass 2H2 + O2 ® 2H2O The Law of Conservation of Mass applies We can check mass by using moles. 2H2 + O2 ® 2H2O 2.02 g H2 2 moles H2 = 4.04 g H2 1 mole H2 + 32.00 g O2 1 mole O2 = 32.00 g O2 1 mole O2 36.04 g total

In terms of Mass (for products) 2H2 + O2 ® 2H2O 18.02 g H2O = 36.04 g H2O 2 moles H2O 1 mole H2O 36.04 g H2 + O2 = 36.04 g H2O 36.04 grams reactant = 36.04 grams product The mass of the reactants must equal the mass of the products.

67.2 Liters of reactant ≠ 44.8 Liters of product! #4. In terms of Volume At STP, 1 mol of any gas = 22.4 L 2H2 + O2 ® 2H2O (2 x 22.4 L H2) + (1 x 22.4 L O2) ® (2 x 22.4 L H2O) NOTE: mass and atoms are ALWAYS conserved - however, molecules, formula units, moles, and volumes will not necessarily be conserved! 67.2 Liters of reactant ≠ 44.8 Liters of product!

Steps to Calculate Stoichiometric Problems Correctly balance the equation. Convert the given amount into moles. Set up mole ratios. Use mole ratios to calculate moles of desired chemical. Convert moles back into final unit.

*Mole to Mole Problem How many moles of O2 are produced when 3.34 moles of Al2O3 decompose?

*Mass-Mass Problem: 6.50 grams of aluminum reacts with an excess of oxygen. How many grams of aluminum oxide are formed?

*Volume-Volume Problem: How many liters of CH4 at STP are required to completely react with 17.5 L of O2 ?

Avogadro told us: Equal volumes of gas, at the same temperature and pressure contain the same number of particles. Moles are numbers of particles You can treat reactions as if they happen liters at a time, as long as you keep the temperature and pressure the same. 1 mole = 22.4 L @ STP