Lesson 4-3 Solving systems by elimination

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Presentation transcript:

Lesson 4-3 Solving systems by elimination Objective: To solve a system by the third final method of elimination

Solving by Elimination When you use the elimination method to solve a system of linear equations, align all like terms in the equations. Then determine whether any like terms can be eliminated because they have opposite coefficients.

Solving by Elimination Solve by elimination. 3x – 4y = 10 x + 4y = –2

Solving by Elimination Solve by elimination. y + 3x = –2 2y – 3x = 14

Solving by Elimination Solve by elimination. 2x + y = –5 2x – 5y = 13

Solving by Elimination Solve by elimination. 2x + y = –5 2x – 5y = 13

Solving by Elimination Solve by elimination. x + 2y = 11 –3x + y = –5

Solving by Elimination Solve by elimination. x + 2y = 11 –3x + y = –5

Solving by Elimination Solve by elimination. –5x + 2y = 32 2x + 3y = 10

Solving by Elimination Solve by elimination. 3x + 2y = 6 –x + y = –2

Solving by Elimination Solve by elimination. 2x + 5y = 26 –3x – 4y = –25

Solving by Elimination Solve by elimination. 2x – 5y = –5 2x – 5y = 13

Solving by Elimination Solve by elimination. 3x – 6y =9 x – 2y = 3