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Solving Systems Using Elimination

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1 Solving Systems Using Elimination
Section 6-3 Part 2

2 Further Elimination In Part 1 of this lesson, you was that to eliminate a variable, its coefficients must have a sum or difference of zero. In some cases, you will first need to multiply one or both of the equations by a number so that one variable has opposite coefficients, so you can add or subtract to eliminate the variable.

3 Example: Multiplying One Equation
2x + 2y = 6 3x – y = 5

4 Example: Continued 2x + 2y = 6 3x – y = 5

5 Example: Continued 2x + 2y = 6 3x – y = 5

6 Example: Multiplying One Equation
x + 4y = 7 4x – 3y = 9

7 Example: Continued x + 4y = 7 4x – 3y = 9

8 Your Turn: Solve the system by elimination. x + 2y = 11 –3x + y = –5

9 Your Turn: Solve the system by elimination. 3x + 2y = 6 –x + y = –2

10 Example: Multiplying Both Equations
3x + 4y = -1 4x – 3y = 7

11 Your Turn: Solve the system by elimination. –5x + 2y = 32 2x + 3y = 10

12 Your Turn: Solve the system by elimination. 2x + 5y = 26

13 infinitely many solutions
IDENTIFYING THE NUMBER OF SOLUTIONS NUMBER OF SOLUTIONS OF A LINEAR SYSTEM CONCEPT SUMMARY y x y x y x Lines intersect one solution Lines are parallel no solution Lines coincide infinitely many solutions

14 Identifying The Number of Solutions
If both variable terms are eliminated as you solve a system of equations, the answer is either no solution or infinite solutions. No solution: get a false statement when solving the system. Infinite solutions: get a true statement when solving the system.

15 A Linear System with Infinite Solutions
Show that this linear system has infinitely many solutions. – 2 x  y  3 Equation 1 – 4 x  2y  6 Equation 2 METHOD: Elimination

16 Show that this linear system
A Linear System with No Solution Show that this linear system has no solution. 2 x  y  Equation 1 2 x  y  Equation 2 METHOD: Elimination

17 Your Turn: Solve the systems using elimination.

18 Summary

19 Summary of Methods for Solving Systems
7.3 The Elimination Method Summary of Methods for Solving Systems Example Suggested Method Why 6x + y = 10 y = 5 Substitution The value of one variable is known and can easily be substituted into the other equation.

20 Summary of Methods for Solving Systems
7.3 The Elimination Method Summary of Methods for Solving Systems Example Suggested Method Why 2x – 5y = –20 4x + 5y = 14 Elimination eliminate ‘y’  5 Add the two equations

21 Summary of Methods for Solving Systems
7.3 The Elimination Method Summary of Methods for Solving Systems Example Suggested Method Why 9a – 2b = –11 8a + 4b = 25 Elimination eliminate ‘b’  4 Multiply first equation by 2 Add the equations


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