Ch. 18 – Sampling Distribution Models (Day 1 – Sample Proportions)

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Ch. 18 – Sampling Distribution Models (Day 1 – Sample Proportions) Part V – From the Data at Hand to the World at Large Ch. 18 – Sampling Distribution Models (Day 1 – Sample Proportions)

Survey Results During the first week of the Obama presidency, the Gallup Poll released the new president’s first approval ratings. Their survey of 1,591 adults found that 68% approved of how he had performed so far. If Gallup could have surveyed all U.S. adults, they would have obtained the true (population) proportion who approved of Obama’s job performance Obviously this is not practical, so they depended on their sample proportion instead p = population proportion (parameter) p = sample proportion (statistic) ^

Sampling Variability If the Gallup Poll had conducted a second poll asking the same question, they probably would have obtained slightly different results (perhaps 67% or 69%) Because each sample will contain different, randomly selected individuals, the results will be a little different each time Remember that this is called sampling error or sampling variability

Sampling Distribution Suppose Gallup repeated the sampling procedure many times and recorded the proportion who approve of the president in each sample:

Sampling Distribution In real life, we would only conduct the sample once, but we can imagine what the distribution of all possible samples would look like This is called the sampling distribution Sampling Distribution Model: A model representing the values taken on by a statistic over all possible samples of size n

Characteristics of the Sampling Distribution of Sample Proportions Suppose that in reality, the true proportion of Americans who approve of Obama’s performance is 40%. If we took many, many samples, we would expect: Does this shape look familiar?

Characteristics of the Sampling Distribution of Sample Proportions The model follows a Normal distribution Remember that we describe Normal models using the notation N(µ, σ) The mean (µ) is the center of the distribution In this case, we would expect that to be the true proportion, p For the sampling distribution of a proportion:

How does this help us? We can make calculations involving sample proportions using these ideas Ex Suppose the true presidential approval rating is 67%. What is the probability that a random sample of 1000 adults would have less than 650 who approve of the president’s performance?

Using your formula sheet Remember that we have been using the formula But now, we are going to use this more general form (on your formula sheet)

Using your formula sheet For sample proportions, this means

Back to the problem… .65 .67

Assumptions & Conditions Like most statistical procedures, sampling distribution models only work when certain assumptions are met The assumptions are: The sampled values must be independent of each other The sample size, n, must be large enough (the larger the sample, the better the Normal model fits)

Assumptions & Conditions In order for those assumptions to be reasonable, we need to check these conditions: Randomization: The sample should be a SRS, or at least a non-biased, representative sample 10% Condition: The sample should be less than 10% of the population Success/Failure Condition: We should expect at least 10 successes & 10 failures

Checking Conditions Do the necessary assumptions seem reasonable for the Gallup Poll example we just did? Random Sample? Sample < 10% of population? n large enough? Yes, given in problem Yes, since there are more than 10,000 Americans (1000 is less than 10% of all Americans)

Putting it all together… A national study found that 44% of college students engage in binge drinking. After reading about this, a professor conducts a random survey of 244 of the students at his college. Use the 68-95-99.7 rule to describe the sampling distribution for this situation .35 .38 .41 .44 .47 .50 .53

Don’t forget assumptions! Do you think the appropriate conditions are met to use this model? Random Sample? Sample < 10% of population? n large enough? Yes, given in problem We have to assume there are more than 2440 students in the college (244 is less than 10% of all students in the college)

Using the Model When he conducted his poll, the professor found that 96 of the 244 students he surveyed admitted having been engaged in binge drinking. Should he be surprised? .35 .38 .41 .44 .47 .50 .53 He should not be surprised – this is less than 2 standard deviations away from the mean, so it’s not that unusual.

One more question… What is the probability that the professor’s survey would have more than 48% admitting they have engaged in binge drinking? .44 .48

Homework 18-1 p. 432 #12, 14, 16, 21, 24