Chapter 11 The Mole.

Slides:



Advertisements
Similar presentations
Chapter 11 Empirical and Molecular Formulas
Advertisements

Chapter 10: Chemical Quantities
Section 10.1 Measuring Matter
Chapter 8 Chemical Composition Chemistry B2A. Atomic mass unit (amu) = × g Atomic Weight Atoms are so tiny. We use a new unit of mass:
The Mole: A measurement of Matter
Ch. 11 The Mole.
The Mole and Chemical Composition
The Mole and Chemical Composition
CHAPTER 7: The Mole.
Chapter 11. Mole SI base unit for measuring the amount of substance The number of representative particles in exactly 12 grams of pure carbon-12 1 mole.
The Mole AA. Review Must turn in your packet with notes stapled to it before you can take the test.
Unit 5: The Mole.
Mole Concept. Counting Units  A pair refers to how many shoes?  A dozen refers to how many doughnuts or eggs?  How many pencils are in a gross?  How.
Chapter 7: Chemical Formulas and Chemical Compounds
Chapter 7 Chemical Quantities. The Mole (Friend or foe)  What is a mole? 1. SI base unit to measure the amount of a substance 2. The amount of a substance.
The Mole Ch.8. (8-1) Mole (mol): amt. of substance – # of atoms in 12g of carbon-12 Avogadro’s constant: 6.02 x particles / mol –Atoms, molecules.
The Mole: A Measurement of Matter
Chapter 10 The Mole. Chemical Measurements Atomic Mass Units (amu) – The mass of 1 atom – 1 oxygen atom has a mass of 16 amu Formula Mass (amu or fu)
Chapter 11 : Matter Notes. Mole (mol) is equal to 6.02x10 23 The mole was named in honor of Amedeo Avogadro. He determined the volume of one mole of gas.
Mole Calculations. The Mole Mole – measurement of the amount of a substance. –We know the amount of different substances in one mole of that substance.
Chapter 7 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
WHAT IS A MOLE?. Moles: Measuring Matter A UNIT OF MEASURE!!! 1 mole = 6.02 x representative particles – atoms, molecules, formula units, ions –
Mole Concept. Counting Units  A pair refers to how many shoes?  A dozen refers to how many doughnuts or eggs?  How many pencils are in a gross?  How.
Using chemical formulas. Formula Mass and Molar Mass  formula mass - mass in grams (amu) of all of the atoms of ea element in a compound  add up all.
Formula (Molar) Mass Li Mn K. Formula (Molar) Mass Add atomic mass of each atom in formula Unit: g/mol Mass of one mole of a pure substance.
Molar Mass, Moles, and Molecules 7.3 Using Chemical Formulas.
Chapter 10 The Mole Measuring Matter Dozen eggs Pair of gloves.
Percent Composition What is the % mass composition (in grams) of the green markers compared to the all of the markers? % green markers = grams of green.
1 Unit 9. 2 How do we measure how much of something we have? How do we measure how much of something we have? n Mass (g) - how much stuff n Volume (L)
Chapter 11 The Mole. I. Measuring Matter A. Counting Particles Chemists needed a convenient method for counting the number of atoms in a sample of a substance.
The Mole Chemistry – Chapter 11. Measuring Matter  What measurements do we use?  Pair  Dozen  Gross  Ream  Counting Particles  Atoms and molecules.
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
Conversion factors from chemical formula
Chemistry 200 Fundamentals D Chemical Composition.
Chapter 7 Chemical Quantities.
III. Formula Calculations (p )
Glencoe: Chapter 11 Sections 11.1 & 11.2
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
Empirical and Molecular Formulas
III. Formula Calculations (p )
The Mole Formula Calculations.
Chapter 6 The mole.
Empirical Formulas.
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
III. Formula Calculations
The Mole Chapter 10.1.
Chemistry 100 Chapter 6 Chemical Composition.
EMPIRICAL FORMULA The empirical formula represents the smallest ratio of atoms present in a compound. The molecular formula gives the total number of atoms.
III. Formula Calculations (p )
III. Formula Calculations (p )
Chapter 10 – Chemical Quantities
Molecular formulas.
Ch. 8 – The Mole Empirical formula.
Percent Composition Empirical Formula Molecular Formula
Unit 6 Mole Calculations
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
II. Percent composition
Chapters 10 Chemical Quantities.
III. Formula Calculations
Chapter 10: The Mole.
mole (symbolized mol) = 6.02 x particles
II. Percent composition
III. Formula Calculations (p )
Chemical Composition Mole (mol) – The number equal to the number of carbon atoms in grams of carbon. Avogadro’s number – The number of atoms in exactly.
Ch. 7: Chemical Formulas and Compounds
UNIT 8: THE MOLE (Counting Atoms)
The Mole.
Ch. 7: Chemical Formulas and Compounds
Empirical and Molecular Formulae
Molecular Formula.
Presentation transcript:

Chapter 11 The Mole

Measuring Matter: THE MOLE Mole (mol): unit to measure the amount of a substance. 1 mol = 6.02 x 1023 particles = Avogadro’s # 6.02 x 1023 particles = 602,000,000,000,000,000,000,000 Particles can be atoms, molecules (covalents), formula units (ionics), e-, or ions depending on the substance

Measuring Matter: THE MOLE Ex: 1 mol Elephants = 6.02 x 1023 elephants 1 mol M&M’s = 6.02 x 1023 M&M’s 1 mol Cu = 6.02 x 1023 Cu atoms 1 mol H2O = 6.02 x 1023 H2O molecules 1 mol NaCl = 6.02 x 1023 NaCl formula units You can convert between moles, atoms, molecules, formula units, particles, etc. using conversion factors

To convert from moles (atoms, molecules, formula units) to particles, multiply by Avogadro’s Number To convert from particles (atoms, molecules, formula units) to moles, divide by Avogadro’s Number.

The Mass of a Mole (Elements) Molar Mass: Mass (g) of 1 mol of any pure substance Units of molar mass are g/mol Conversion Factor: For elements: 1 mol = atomic mass number Ex: What is the mass of 3.0 mol Mn? 3.0 mol Mn x 54.94g Mn = 164.8 g Mn 1 mol Mn

The Mass of a Mole (Compounds) Molar mass of a compound is the sum of the molar masses of all elements making it up. Ex: H2O 2 mol H atoms x 1.008 g H = 2.016g H 1 mol H 1 mol O atoms x 15.999 g O = 15.999g O 1 mol O Molar Mass water = 2.016 + 15.999 = 18.015 g

The Mass of a Mole (Compounds) Multiply the number of atoms of an element by it’s atomic mass. Do this for all elements, then add them up. CCl2F2 C = 12 x 1 = 12; Cl = 2 x 35.45 = 70.9; F = 2 x 19 = 38 12 + 70.9 + 38 = 120.9 g Al2O3 Al = 2 x 26.98 = 53.96; O = 3 x 15.99 =47.97 53.96 + 47.97 = 101.93 g H2SO4 H = 1.008; S = 32.07; O = 4 x 15.99 = 63.96 1.008 + 32.07 + 63.96 = 97.04 g

Try These ….. What is the mass of 2.5 mol fluorine? 2.5 mol F x 19.0 g = 47.5g F 1 mol F How many moles are in 325 g C? 325 g C x 1 mol C = 27.1 mol C 12.0 g C How many moles are in 34.4 g N? 34.4 g N x 1 mol N = 2.46 mol N 14.0 g N

Converting Between mol + mass of Compds Always start by calculating the molar mass, then use conversion factors to get the necessary units What is the mass of 2.6 mol H2O? Molar mass = 18.015g 2.6 mol H2O x 18.015 g H2O = 46.839 g H2O 1 mol H2O What is the mass of 6.94 mol CCl2F2 ? Molar Mass = 120.9g 6.94 mol CCl2F2 x 120.9 g CCl2F2 = 839.04 g CCl2F2 1 mol CCl2F2

Converting Between mol + mass of Compds How many mol H2O are in 599.653 g? Molar mass = 18.015g 599.653 g H2O x 1 mol H2O = 33.286 mol H2O 18.015 g H2O How many mol CCl2F2 are in 692.222 g? Molar Mass = 120.9g 692.222 g CCl2F2 x 1 mol CCl2F2 = 5.73 mol CCl2F2 120.9 g CCl2F2

Percent Composition % Comp = (mass element/mass compound)x 100 A 100g sample of XY contains 55g X and 45g Y. What is the % composition of each element? X = (55g X/100g XY) x 100 = 55% X Y = (45g Y/100g XY) x 100 = 45% Y A 200g sample of CO2 contains 67g C and 133g O. What is the % composition of each element? C = (67g C/200g CO2) x 100 = 33.5% C O = (133g O/200g CO2) x 100 = 66.5% O

Using % Comp to Find Molecular Formulas Steps: Convert mass of each element to moles. Divide moles of each element by the smallest number of moles available to get mole ratios If ratios are not whole numbers, multiply to make them whole. Write the empirical formula Divide known molar mass (represents molec formula) by the molar mass of emp formula Multiply your subscripts by that number to write the molecular formula same