Physics 101: Lecture 17, Pg 1 Physics 101: Lecture 17 Fluids II Exam correction today during lab time in 242 Loomis Exam III

Physics 101: Lecture 17, Pg 2 Archimedes’ Principle l Determine force of fluid on immersed cube è Draw FBD 43 l Buoyant force is weight of displaced fluid!

Physics 101: Lecture 17, Pg 3 Archimedes Example A cube of plastic 4.0 cm on a side with density = 0.8 g/cm 3 is floating in the water. When a 9 gram coin is placed on the block, how much sinks below water surface? 12 mg FbFb Mg h

Physics 101: Lecture 17, Pg 4 Suppose you float a large ice-cube in a glass of water, and that after you place the ice in the glass the level of the water is at the very brim. When the ice melts, the level of the water in the glass will: 1. Go up, causing the water to spill out of the glass. 2. Go down. 3. Stay the same. Question Must be same! 14

Physics 101: Lecture 17, Pg 5 Archimedes’ Principle l If object is floating… 8

Physics 101: Lecture 17, Pg 6 Archimedes’ Principle l Which picture looks like an ice cube floating?… 8 A C B

Physics 101: Lecture 17, Pg 7 How much of the Iceberg can you see?

Physics 101: Lecture 17, Pg 8 Where are you going to hit the Iceberg?

Physics 101: Lecture 17, Pg 9 Question 2 Which weighs more: 1. A large bathtub filled to the brim with water. 2. A large bathtub filled to the brim with water with a battle-ship floating in it. 3. They will weigh the same. Tub of water Tub of water + ship Overflowed water Weight of ship = Buoyant force = Weight of displaced water 16

Physics 101: Lecture 17, Pg 10 Fluid Flow Concepts Mass flow rate:  Av (kg/s) Volume flow rate: Av (m 3 /s) Continuity:  A 1 v 1 =  A 2 v 2 i.e., mass flow rate the same everywhere e.g., flow of river A 1 P 1 A 2 P 2 v1v1 v2v2  21

Physics 101: Lecture 17, Pg 11 Bernoulli’s Eq. And Work W =  K +  U l W=F d = PA d = P V (P 1 -P 2 ) V = ½ m (v 2 2 – v 1 2 ) + mg(y 2 -y 1 ) (P 1 -P 2 ) V = ½  V (v 2 2 – v 1 2 ) +  Vg(y 2 -y 1 ) P 1 +  gy 1 + ½  v 1 2 = P 2 +  gy 2 + ½  v 2 2 Compare P 1, P 2 33 A 1 P 1 A 2 P 2 v1v1 v2v2 

Physics 101: Lecture 17, Pg 12 Example: hose A garden hose w/ inner diameter 2 cm, carries water at 2.0 m/s. To spray your friend, you place your thumb over the nozzle giving an effective opening diameter of 0.5 cm. What is the speed of the water exiting the hose? What is the pressure difference between inside the hose and outside? Bernoulli Equation Continuity Equation

Physics 101: Lecture 17, Pg 13 Example: Lift a House Calculate the net lift on a 15 m x 15 m house when a 30 m/s wind (1.29 kg/m 3 ) blows over the top. 48

Physics 101: Lecture 17, Pg 14 Is Bernoulli’s Eq. involved in airfoil lift?

Physics 101: Lecture 17, Pg 15 Fluid Flow Summary Mass flow rate:  Av (kg/s) Volume flow rate: Av (m 3 /s) Continuity:  A 1 v 1 =  A 2 v 2 Bernoulli: P / 2  v  gh 1 = P / 2  v  gh 2 A 1 P 1 A 2 P 2 v1v1 v2v2  50