1. Fluids II

2. Archimedes Example A cube of plastic 4.0 cm on a side with density = 0.8 g/cm 3 is floating in the water. When a 9 gram coin is placed on the block, how much sinks below water surface? 12 mg FbFb Mg h

3. Suppose you float a large ice-cube in a glass of water, and that after you place the ice in the glass the level of the water is at the very brim. When the ice melts, the level of the water in the glass will: 1. Go up, causing the water to spill out of the glass. 2. Go down. 3. Stay the same. Question Must be same! 14

4. Archimedes’ Principle l If object is floating… 8

5. Archimedes’ Principle l Which picture looks like an ice cube floating?… 8 A C B

6. How much of the Iceberg can you see?

7. Question 2 Which weighs more: 1. A large bathtub filled to the brim with water. 2. A large bathtub filled to the brim with water with a battle-ship floating in it. 3. They will weigh the same. Tub of water Tub of water + ship Overflowed water Weight of ship = Buoyant force = Weight of displaced water 16

8. Fluid Flow Concepts Mass flow rate:  Av (kg/s) Volume flow rate: Av (m 3 /s) Continuity:  A 1 v 1 =  A 2 v 2 i.e., mass flow rate the same everywhere e.g., flow of river A 1 P 1 A 2 P 2 v1v1 v2v2  21

9. Bernoulli’s Eq. And Work W =  K +  U l W=F d = PA d = P V (P 1 -P 2 ) V = ½ m (v 2 2 – v 1 2 ) + mg(y 2 -y 1 ) (P 1 -P 2 ) V = ½  V (v 2 2 – v 1 2 ) +  Vg(y 2 -y 1 ) P 1 +  gy 1 + ½  v 1 2 = P 2 +  gy 2 + ½  v 2 2 Compare P 1, P 2 33 A 1 P 1 A 2 P 2 v1v1 v2v2 

10. Example: hose A garden hose w/ inner diameter 2 cm, carries water at 2.0 m/s. To spray your friend, you place your thumb over the nozzle giving an effective opening diameter of 0.5 cm. What is the speed of the water exiting the hose? What is the pressure difference between inside the hose and outside? Bernoulli Equation Continuity Equation

11. Example: Lift a House Calculate the net lift on a 15 m x 15 m house when a 30 m/s wind (1.29 kg/m 3 ) blows over the top. 48

12. Is Bernoulli’s Eq. involved in airfoil lift?

13. Fluid Flow Summary Mass flow rate:  Av (kg/s) Volume flow rate: Av (m 3 /s) Continuity:  A 1 v 1 =  A 2 v 2 Bernoulli: P 1 + 1 / 2  v 1 2 +  gh 1 = P 2 + 1 / 2  v 2 2 +  gh 2 A 1 P 1 A 2 P 2 v1v1 v2v2  50