Using Formulas and Literal Equations

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Presentation transcript:

Using Formulas and Literal Equations Section 3.6 Solve literal equations for a specific variable and use formulas to solve problems.

Literal Equation: An equation that involves two or more variables. Formula: A literal equation that states a rule for a relationship among quantities. Examples: C = (F – 32) A = P + I A = lw P = 2l + 2w D = rt C = np y = mx + b C = 2πr A = ½h(b₁ + b₂) D =

Example: Find the area of the trapezoid by using the formula A = ½h(b₁ + b₂), if h = 5, b₁ = 6, and b₂ = 9. b₁ h b₂

C = (F – 32) Degrees Celsius Degrees Fahrenheit Example: Convert each temperature from degrees Fahrenheit to degrees Celsius a. 68°F b. 32°F c. 23°F Practice: P147 Try this after Example 1

Example: Louis has 480 feet of chicken wire and is building a pen Example: Louis has 480 feet of chicken wire and is building a pen. He wants the length of the pen to be 3 times the width. Find the dimensions of the pen. Practice: P151 # 11

Example: The area of a trapezoid is 90 square inches Example: The area of a trapezoid is 90 square inches. The height of the trapezoid is 12 inches. The longer base is 9 inches. Use the formula for the area of a trapezoid, A = ½h(b₁ + b₂), to find the length of the shorter base. Practice: P151 # 12

Example: Use the formula C = 2πr to find the value of r for the given circumference. Use 3.14 for π. Practice: P151 # 13

Example: Solve for the indicated variable d = k + s for s r = for d y = mx + b for m p = 6x + 2z for z Practice: P 151 #’s 8-10 Homework: P151-152 #15-51 (by 3s)