Slope-intercept Form to Standard Form and Standard Form to Slope-intercept Form Robert Conyer Algebra II.

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Slope-intercept Form to Standard Form and Standard Form to Slope-intercept Form Robert Conyer Algebra II

Slope-Intercept Form: Y = MX + B Standard Form: -MX + Y = B To convert a linear equation from slope-intercept form to standard form Slope-intercept Standard Form: -3X + 2Y = 16 First) Convert the slope from a fraction to a whole number by multiplying everything by two. 2Y = 3X + 16 Second) Move the X from the right side of the equation to the left side by subtracting 3X from both sides of the equation. 2Y = 3X X -3X 0 Standard Form: -3X + 2Y = 16

Example 35: Slope-intercept Form: Y = -5X – 6 Step One: The slope is not a fraction. Add 5X to both sides of the equation. Slope-intercept form: Y = -5X – 6 +5X +5X Standard Form: 5X + Y = -6 ______________________________________________________________________ Example 36: Slope-intercept Form: Y = - ¼ X Standard Form: X + 4Y = 0 Step One: Multiply both sides by four. (4)Y = (4) (- ¼ X)4Y = -X Step Two: Add X to both sides of the equation. 4Y = -X +X +X Standard Form: X + 4Y = 0

Slope-Intercept Form: Y = MX + B Standard Form: -MX + Y = B To convert a linear equation from standard form to slope-intercept form. Standard Form: 8X + 3Y = 30Slope-intercept Form: Step One: Divide everything by three. 8X + 3Y = Step Two: Subtract 8/3X from both sides. Slope-Intercept Form

Example 37: Standard Form: 10X – 7Y = 4 Step One: Divide everything by negative seven. 10X - 7Y = Step Two: Add 10/7X to both sides of the equation. Slope-Intercept Form: