Warm-Up Exercises EXAMPLE 1 Standardized Test Practice What are the solutions of 3x 2 + 5x = 8? –1 and – A 8 3 B –1 and 8 3 C 1 and – 8 3 D 1 and 8 3 SOLUTION.

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Warm-Up Exercises EXAMPLE 1 Standardized Test Practice What are the solutions of 3x 2 + 5x = 8? –1 and – A 8 3 B –1 and 8 3 C 1 and – 8 3 D 1 and 8 3 SOLUTION Write original equation. 3x 2 + 5x = 8 Write in standard form. 3x 2 + 5x – 8 = 0 Quadratic formula ± x = –bb 2 – 4ac 2a2a

Warm-Up Exercises EXAMPLE 1 Standardized Test Practice Substitute values in the quadratic formula : a = 3, b = 5, and c = – 8. Simplify. = –5 ± Simplify the square root. = –5 ± 11 6 The solutions of the equation are – = 1 and –5 – 11 6 = – 8 3 The correct answer is C. ANSWER x = –5 ± 5 2 – 4(3)(–8) 2(3)

Warm-Up Exercises EXAMPLE 2 Solve a quadratic equation 2x 2 – 7 = x 2x 2 – x – 7 = 0 Solve 2x 2 – 7 = x. Write original equation. Write in standard form. Quadratic formula x =x = b 2 – 4ac + – –b 2a2a Substitute values in the quadratic formula: a = 2, b = –1, and c = –7. Simplify. – (–1) – + ( –1) 2 – 4(2)(–7) 2(2) = 4 = + – 1 57

Warm-Up Exercises EXAMPLE 2 Solve a quadratic equation Write the equation in standard form, 2x 2 – x – 7 = 0. Then graph the related function y = 2x 2 – x – 7. The x- intercepts are about –1.6 and 2.1. So, each solution checks. ANSWER and 1 – 4 – The solutions are CHECK 57

Warm-Up Exercises GUIDED PRACTICE for Examples 1and 2 Solve the equation by Quadratic Formula. 1. x 2 – 8x + 16 = n 2 – 5n = –1 3. 4z 2 = 7z + 2

Warm-Up Exercises EXAMPLE 3 Use the quadratic formula y = 10x 2 – 94x = 10x 2 – 94x – = 10x 2 – 94x – 300 Write function. Substitute 4200 for y. Write in standard form. SOLUTION For the period 1971  2001, the number y of films produced in the world can be modeled by the function y = 10x 2  94x where x is the number of years since In what year were 4200 films produced ? FILM PRODUCTION

Warm-Up Exercises EXAMPLE 3 Use the quadratic formula Substitute values in the quadratic formula: a = 10, b = –94, and c = – , – 20 = Simplify. The solutions of the equation are: ANSWER There were 4200 films produced about 12 years after 1971, or in x = (–94) 2 – 4 (10)(–300) –(–94) + – 2(10) , –20, –3. and

Warm-Up Exercises GUIDED PRACTICE for Example 4 WHAT IF? In Example 3, find the year when 4750 films were produced. 4.

Warm-Up Exercises EXAMPLE 4 Choose a solution method Tell what method you would use to solve the quadratic equation. Explain your choice(s). a. 10x 2 – 7 = 0 SOLUTION a. The quadratic equation can be solved using square roots because the equation can be written in the form x 2 = d.

Warm-Up Exercises Choose a solution method EXAMPLE 4 b. The equation can be solved by factoring because the expression x 2 + 4x can be factored easily. Also, the equation can be solved by completing the square because the equation is of the form ax 2 + bx + c = 0 where a = 1 and b is an even number. Tell what method you would use to solve the quadratic equation. Explain your choice(s). b. x 2 + 4x = 0 SOLUTION

Warm-Up Exercises Choose a solution method EXAMPLE 4 c. The quadratic equation cannot be factored easily, and completing the square will result in many fractions. So, the equation can be solved using the quadratic formula. Tell what method you would use to solve the quadratic equation. Explain your choice(s). c. 5x 2 + 9x – 4 = 0 SOLUTION

Warm-Up Exercises GUIDED PRACTICE for Example 4 Tell what method you would use to solve the quadratic equation. Explain your choice(s). Factoring because the expression factors easily. 5. x 2 + x – 6 = 0

Warm-Up Exercises GUIDED PRACTICE for Example 4 Tell what method you would use to solve the quadratic equation. Explain your choice(s). Factoring because the expression factors easily. Using square roots is another option since the equation can be written in the form x 2 = d. 6. x 2 – 9 = 0