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Chapter 2 Review Proofs in Algebra. Vocabulary Addition and Subtraction Properties Multiplication and Division Properties Substitution Property Commutative.

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Presentation on theme: "Chapter 2 Review Proofs in Algebra. Vocabulary Addition and Subtraction Properties Multiplication and Division Properties Substitution Property Commutative."— Presentation transcript:

1 Chapter 2 Review Proofs in Algebra

2 Vocabulary Addition and Subtraction Properties Multiplication and Division Properties Substitution Property Commutative Properties Associative Properties Distributive Property Reflexive Property Symmetric Property Transitive Property

3 Vocabulary Segment Addition Postulate Overlapping segments Overlapping Segments Theorem Segment bisector Midpoint Perpendicular bisector

4 Name the property of equality that justifies each statement. a. If x = 4, then x ● 2 = 4 ● 2. b. If 5b = 10, then b = 2. c. d. If x – y = 2, then x = y + 2 e. If AB = 3y and AB = CD, then 3y = CD. f. If a = b, then b = a. g. 2 = 2

5 Name the property of equality that justifies each statement. a. (3 + 2) + 5 = 3 + (2 + 5) b. If AC = XY and BD = UV, then AC + BD = XY + UV c. 2r + 3r = 5r d. S + (t + u) = (t + u) + s e. If 3x = 9 and x = 3, then 3(3) = 9 f. If 3x + 2 = 17, then 3x = 15. g. If AC + BC = BC + DE, then AC = DE.

6 Identify the errors in the following proof: If 2x + 4 = 12, then x = 4. StatementsReasons a. 2x + 4 = 12a.Given b. 4 = 4b. Substitution property c. 2x = 8c. Addition Property of Equality d. 2=2 d. Reflexive Property e. x = 16e. Division property

7 Complete a proof for the following: If 5x = 9+2x, then x = 3. StatementsReasons

8 Complete a proof for the following: Given: AP = BP; PC = PD Prove: AC = BD StatementsReasons

9 Complete a proof for the following: Given: M bisects ; MB = BC Prove: AB = MC StatementsReasons a. M bisectsa. Given b. M is the midpoint ofb. c.c. Definition of midpoint d. AM = MBd. e. MB = BCe. f.f. Transitive Property of Equality g. AB = MCg.


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