1. Chapter 10 Rotational Motion 9-8 Center of Mass 10-1 Angular Quantities 10-2 Vector Nature of Angular Quantities 10-3 Constant Angular Acceleration 10-4 Torque HW 7:Chap. 10: Pb.19, Pb. 23, Pb. 25, Pb. 29, Pb. 57, Pb. 67 Due on Friday, Nov. 13

2. Problem 62 Problem 62:The CM of an empty 1250-kg car is 2.50 m behind the front of the car. How far from the front of the car will the CM be when two people sit in the front seat 2.80 m from the front of the car, and three people sit in the back seat 3.90 m from the front? Assume that each person has a mass of 70.0 kg.

3. 9-8 Center of Mass ( CM ) For two particles, the center of mass lies closer to the one with the most mass: where M is the total mass.

4. 9-8 Center of Mass ( CM ) Exercise 9-15: Three particles in 2-D. Three particles, each of mass 2.50 kg, are located at the corners of a right triangle whose sides are 2.00 m and 1.50 m long, as shown. Locate the center of mass.

5. 9-8 Center of Mass ( CM ) Example 9-17: CM of L-shaped flat object. Determine the CM of the uniform thin L- shaped construction brace shown.

6. 9-8 Center of Mass ( CM ) For an extended object, we imagine making it up of tiny particles, each of tiny mass, and adding up the product of each particle’s mass with its position and dividing by the total mass. In the limit that the particles become infinitely small, this gives:

7. 9-8 Center of Mass ( CM ) The center of gravity is the point at which the gravitational force can be considered to act. It is the same as the center of mass as long as the gravitational force does not vary among different parts of the object.

8. 9-8 Center of Mass ( CM ) The center of gravity can be found experimentally by suspending an object from different points. The CM need not be within the actual object—a doughnut’s CM is in the center of the hole.

9. 9-9 Center of Mass and Translational Motion The total momentum of a system of particles is equal to the product of the total mass and the velocity of the center of mass. The sum of all the forces acting on a system is equal to the total mass of the system multiplied by the acceleration of the center of mass: Therefore, the center of mass of a system of particles (or objects) with total mass M moves like a single particle of mass M acted upon by the same net external force.

10. Exam 3 Review Problems for chap. 9 Chap. 9: 4, 22, 27,34, 37, 41, 44, 46, 50, 54, 56

11. Problem 5: (II) (a) A grinding wheel 0.35 m in diameter rotates at 2500 rpm. Calculate its angular velocity in rad/s. (b) What are the linear speed and acceleration of a point on the edge of the grinding wheel? Chapt10: Rotational Motion

12. Example 10-1: Birds of prey—in radians. A particular bird’s eye can just distinguish objects that subtend an angle no smaller than about 3 x 10 -4 rad. (a) How many degrees is this? (b) How small an object can the bird just distinguish when flying at a height of 100 m? 10-1 Angular Quantities