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Deadly Pez Dispenser. Team Members Quincy Beasley Quincy Beasley London Webb London Webb Joel Fugate Joel Fugate Michael Bettis Michael Bettis.

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Presentation on theme: "Deadly Pez Dispenser. Team Members Quincy Beasley Quincy Beasley London Webb London Webb Joel Fugate Joel Fugate Michael Bettis Michael Bettis."— Presentation transcript:

1 Deadly Pez Dispenser

2 Team Members Quincy Beasley Quincy Beasley London Webb London Webb Joel Fugate Joel Fugate Michael Bettis Michael Bettis

3 Purpose The purpose of project is to rapidly dispense candy. Conservation of energy is used to make 2 ping pong balls hit a mouse trap that will release candy. The purpose of project is to rapidly dispense candy. Conservation of energy is used to make 2 ping pong balls hit a mouse trap that will release candy.

4 Demonstration

5 Energy Conversions Summary of Energy Conversions Summary of Energy Conversions Step 1 : Ping pong ball rolls down first pvc pipe Step 1 : Ping pong ball rolls down first pvc pipe Height above ground to center of pvc pipe – 17.5 inches Height above ground to center of pvc pipe – 17.5 inches Distance till impact with second ping pong ball – 2.5 inches Distance till impact with second ping pong ball – 2.5 inches Gravitational potential energy  Kinetic energy Gravitational potential energy  Kinetic energy mgh =.5mv^2 + mgh mgh =.5mv^2 + mgh (386.4 inches/sec^2)(17.5 inches) =.5v^2 + (386.4 inches/sec^2)(15 inches) (386.4 inches/sec^2)(17.5 inches) =.5v^2 + (386.4 inches/sec^2)(15 inches) (masses cancel) (masses cancel) V= 43.95 inches/sec (3.66 ft/sec) V= 43.95 inches/sec (3.66 ft/sec) Step 2 : Ping pong ball hits other ping pong ball Step 2 : Ping pong ball hits other ping pong ball Mv1 + mv2 = mv1’ + mv2’ Mv1 + mv2 = mv1’ + mv2’ 43.95 inches/sec + 0 = 0 + v2’ 43.95 inches/sec + 0 = 0 + v2’ 43.95 inches/sec = v2’ (masses cancel) 43.95 inches/sec = v2’ (masses cancel) Step 3 : Ping pong ball hits mouse trap Step 3 : Ping pong ball hits mouse trap Height of mouse trap -.75 inches Height of mouse trap -.75 inches Initial Kinectic energy + Gravitational potential energy  Kinetic energy Initial Kinectic energy + Gravitational potential energy  Kinetic energy.5mv^2 + mgh =.5mv^2 + mgh.5mv^2 + mgh =.5mv^2 + mgh.5(43.95 inches/sec) ^2 + (386.4 inches/sec^2)(15 inches) =.5v^2 +.5(43.95 inches/sec) ^2 + (386.4 inches/sec^2)(15 inches) =.5v^2 + (386.4 inches/sec^2)(.75 inches) (386.4 inches/sec^2)(.75 inches) V= 113.77 inches/sec (9.48 ft/sec) V= 113.77 inches/sec (9.48 ft/sec)


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