1. Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Chapter 2 Equations, Inequalities and Problem Solving

2. 22 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Bellwork: 1. The sum of the angles of a triangle is 180°. If one angle of a triangle measures x° and a second angle measures (2x+7)°, express the measure of the third angle in terms of x. Simplify the expression. 2. A quadrilateral is a four-sided figure whose angle sum is 360°. If one angle measures x°, another 3x°, and another 5x°, express the measure of the fourth angle in terms of x. Simplify the expression. Hint: DRAW THE PICTURE!!

3. 33 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Bellwork: 1. The sum of the angles of a triangle is 180°. If one angle of a triangle measures x° and a second angle measures (2x+7)°, express the measure of the third angle in terms of x. Simplify the expression. x° (2x+7)° ?°

4. 44 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Bellwork: 1. The sum of the angles of a triangle is 180°. If one angle of a triangle measures x° and a second angle measures (2x+7)°, express the measure of the third angle in terms of x. Simplify the expression. x° (2x+7)° ?° ?° = 180° - x° - (2x+7)° = (-3x+173)°

5. 55 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Bellwork: 2. A quadrilateral is a four-sided figure whose angle sum is 360°. If one angle measures x°, another 3x°, and another 5x°, express the measure of the fourth angle in terms of x. Simplify the expression. x° ?° 5x° 3x°

6. 66 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Bellwork: 2. A quadrilateral is a four-sided figure whose angle sum is 360°. If one angle measures x°, another 3x°, and another 5x°, express the measure of the fourth angle in terms of x. Simplify the expression. x° ?° 5x° 3x° ?° = 360° - x° - 3x° - 5x° = (-9x+360)°

7. Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 2.3 The Multiplication Property of Equality

8. 88 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Objectives:  Use the multiplication property of equality to solve linear equations  Write work phrases as algebraic expressions

9. 99 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Multiplication Property of Equality Let a, b, and c represent numbers and let c ≠ 0. Then, a = ba = b and a · c = b · cand are equivalentare equivalent equations.equations.

10. 10 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1

11. 11 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1

12. 12 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1

13. 13 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1

14. 14 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 A number divided by itself is one!

15. 15 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one!

16. 16 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one!

17. 17 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one!

18. 18 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one!

19. 19 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one!

20. 20 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one!

21. 21 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one!

22. 22 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one! True Statement!

23. 23 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve –4x = 16 for x. Check: Example 1 1 A number divided by itself is one! ✔ True Statement!

24. 24 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: Example 2

25. 25 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: Example 2

26. 26 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: Example 2

27. 27 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: Example 2 The product of reciprocals is one!

28. 28 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: Example 2 The product of reciprocals is one!

29. 29 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: Example 2 The product of reciprocals is one! Simplify

30. 30 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: Example 2 The product of reciprocals is one! Simplify

31. 31 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: –1.2x = –36 Example 3

32. 32 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: –1.2x = –36 Example 3

33. 33 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: –1.2x = –36 Example 3

34. 34 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: –1.2x = –36 Example 3 A number divided by itself is one!

35. 35 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: –1.2x = –36 Example 3 A number divided by itself is one!

36. 36 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: –1.2x = –36 Example 3 A number divided by itself is one!

37. 37 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 4 Simplify both sides. Multiply both sides by 7. Solve:

38. 38 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 4 Simplify both sides. Multiply both sides by 7. Solve:

39. 39 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 4 Simplify both sides. Multiply both sides by 7. Solve:

40. 40 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 4 Simplify both sides. Multiply both sides by 7. Solve:

41. 41 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 4 Simplify both sides. Multiply both sides by 7. Solve:

42. 42 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 4 Simplify both sides. Multiply both sides by 7. Solve: The product of reciprocals is one!

43. 43 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 4 Simplify both sides. Multiply both sides by 7. Solve: The product of reciprocals is one!

44. 44 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 4x – 8x = 16 Example 5

45. 45 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 4x – 8x = 16 Example 5

46. 46 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 4x – 8x = 16 Example 5

47. 47 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 4x – 8x = 16 Example 5

48. 48 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 4x – 8x = 16 Example 5 A number divided by itself is one!

49. 49 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 4x – 8x = 16 Example 5 A number divided by itself is one!

50. 50 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26

51. 51 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26

52. 52 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides!

53. 53 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides!

54. 54 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides! Simplify

55. 55 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides! Simplify

56. 56 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides! Simplify Divide on both sides!

57. 57 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides! Divide on both sides! Simplify

58. 58 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides! Divide on both sides! Simplify

59. 59 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 6 3z – 1 = 26 3z = 27 z = 9 3z – 1 + 1 = 26 + 1 Solve: 3z – 1 = 26 Add to both sides! Divide on both sides! Simplify

60. 60 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7

61. 61 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify

62. 62 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify

63. 63 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides!

64. 64 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides!

65. 65 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides! Simplify

66. 66 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides! Simplify

67. 67 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides! Simplify Divide on both sides!

68. 68 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides! Simplify Divide on both sides!

69. 69 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides! Simplify Divide on both sides! Simplify

70. 70 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 12x + 30 + 8x – 6 = 10 20x + 24 = 10 20x = – 14 20x + 24 + ( – 24) = 10 + ( – 24) Solve: Example 7 Simplify Add to both sides! Simplify Divide on both sides! Simplify

71. 71 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8

72. 72 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute

73. 73 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute

74. 74 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify

75. 75 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify

76. 76 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides!

77. 77 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides!

78. 78 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides! Simplify

79. 79 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides! Simplify

80. 80 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides! Simplify Divide on both sides!

81. 81 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides! Simplify Divide on both sides!

82. 82 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides! Simplify Divide on both sides! Simplify

83. 83 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 – 15 = 6 – 15 10x + 15 = 6 10x = –9 Example 8 Distribute Simplify Add to both sides! Simplify Divide on both sides! Simplify

84. 84 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Recall: Integers are the whole steps from -∞ to ∞, and consecutive means one right after another. Consecutive Integers Consecutive integers If n is the first integer, then: n+1 is the second, n+2 is the third, n+3 is the fourth, etc…

85. 85 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Recall: Integers are the whole steps from -∞ to ∞, and consecutive means one right after another. Consecutive Integers Consecutive even integers If n is the first integer, then: n+2 is the second, n+4 is the third, n+6 is the fourth, etc…

86. 86 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Recall: Integers are the whole steps from -∞ to ∞, and consecutive means one right after another. Consecutive Integers Consecutive odd integers If n is the first integer, then: n+2 is the second, n+4 is the third, n+6 is the fourth, etc…

87. 87 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9

88. 88 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9

89. 89 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9 x is the first consecutive integer no even or odd, so x + 1 is the second

90. 90 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9 x is the first consecutive integer no even or odd, so x + 1 is the second express the sum

91. 91 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9 x is the first consecutive integer no even or odd, so x + 1 is the second express the sum 1 st + 2 nd is the sum

92. 92 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9 x is the first consecutive integer no even or odd, so x + 1 is the second express the sum 1 st + 2 nd is the sum x + (x + 1)

93. 93 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9 x is the first consecutive integer no even or odd, so x + 1 is the second express the sum 1 st + 2 nd is the sum x + (x + 1) Simplify

94. 94 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9 x is the first consecutive integer no even or odd, so x + 1 is the second express the sum 1 st + 2 nd is the sum x + (x + 1) x + x + 1 Simplify

95. 95 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If x is the first of two consecutive integers, express the sum of the first and the second integer in terms of x. Simplify if possible. Example 9 x is the first consecutive integer no even or odd, so x + 1 is the second express the sum 1 st + 2 nd is the sum x + (x + 1) x + x + 1 Simplify 2x + 1

96. 96 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Closure: 1. What is the Multiplication Property of Equality? 2. What should you do to both sides of an equation?

97. 97 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Exit Pass 5(3x – 1) + 2 = 12x + 6 Step 1_________________ Step 2_________________ Step 3_________________ Step 4_________________ Step 5_________________ Solve the equation for x. Describe your process for each step.

98. 98 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Exit Pass Solve the equation for x. Describe your process for each step. 5(3x – 1) + 2 = 12x + 6 15x – 5 + 2 = 12x + 6 _________________ 15x – 3 = 12x + 6 _________________ 3x – 3 = 6 _________________ 3x = 9 _________________ 3x/3 = 9/3 _________________ x=3

99. 99 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Exit Pass Solve the equation for x. Describe your process for each step. 5(3x – 1) + 2 = 12x + 6 15x – 5 + 2 = 12x + 6 _________________ 15x – 3 = 12x + 6 _________________ 3x – 3 = 6 _________________ 3x = 9 _________________ 3x/3 = 9/3 _________________ x=3 Distribute

100. 100 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Exit Pass Solve the equation for x. Describe your process for each step. 5(3x – 1) + 2 = 12x + 6 15x – 5 + 2 = 12x + 6 _________________ 15x – 3 = 12x + 6 _________________ 3x – 3 = 6 _________________ 3x = 9 _________________ 3x/3 = 9/3 _________________ x=3 Distribute Simplify or Combine like terms

101. 101 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Exit Pass Solve the equation for x. Describe your process for each step. 5(3x – 1) + 2 = 12x + 6 15x – 5 + 2 = 12x + 6 _________________ 15x – 3 = 12x + 6 _________________ 3x – 3 = 6 _________________ 3x = 9 _________________ 3x/3 = 9/3 _________________ x=3 Distribute Simplify or Combine like terms Add same on both sides

102. 102 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Exit Pass Solve the equation for x. Describe your process for each step. 5(3x – 1) + 2 = 12x + 6 15x – 5 + 2 = 12x + 6 _________________ 15x – 3 = 12x + 6 _________________ 3x – 3 = 6 _________________ 3x = 9 _________________ 3x/3 = 9/3 _________________ x=3 Distribute Simplify or Combine like terms Add same on both sides

103. 103 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Exit Pass Solve the equation for x. Describe your process for each step. 5(3x – 1) + 2 = 12x + 6 15x – 5 + 2 = 12x + 6 _________________ 15x – 3 = 12x + 6 _________________ 3x – 3 = 6 _________________ 3x = 9 _________________ 3x/3 = 9/3 _________________ x=3 Distribute Simplify or Combine like terms Add same on both sides Divide on both sides Add same on both sides